Chapter 21: Problem 16
(II) In Fig. 21-11, the moving rod has a resistance of 0.25 \(\Omega\) and moves on rails 20.0 cm apart. The stationary U-shaped conductor has negligible resistance.When a force of 0.350 N is applied to the rod, it moves to the right at a constant speed of 1.50 m/s What is the magnetic field?
Short Answer
Expert verified
Magnetic field \( B \approx 1.208 \text{ T} \).
Step by step solution
01
Identify the known values
We are given that the resistance of the rod is \( R = 0.25 \Omega \), the distance between the rails is \( L = 0.20 \text{ m} \), the force applied is \( F = 0.350 \text{ N} \), and the velocity of the rod is \( v = 1.50 \text{ m/s} \).
02
Understand the concept of electromagnetic force
When the rod moves at a constant velocity through a magnetic field, it cuts across magnetic field lines, inducing an electromotive force (emf). According to Faraday's law of induction, the emf \( \mathcal{E} \) can be calculated using \( \mathcal{E} = B \cdot L \cdot v \), where \( B \) is the magnetic field strength.
03
Calculate the emf using the mechanical power
For the rod to move at a constant speed, the mechanical power (force times velocity) is equal to the electrical power dissipated (emf squared over resistance). Thus, we have \( P_{mech} = F \cdot v \) and \( P_{elec} = \frac{\mathcal{E}^2}{R} \). Therefore, equating these two gives us \( \mathcal{E} = \sqrt{F \cdot v \cdot R} \).
04
Substitute and solve for induced emf
Substitute the given values into the equation \( \mathcal{E} = \sqrt{0.350 \text{ N} \times 1.50 \text{ m/s} \times 0.25 \Omega} \). Calculate \( \mathcal{E} = \sqrt{0.13125} \approx 0.3623 \text{ V} \).
05
Solve for magnetic field \( B \)
Use the relationship \( \mathcal{E} = B \cdot L \cdot v \) to solve for \( B \): \( B = \frac{\mathcal{E}}{L \cdot v} = \frac{0.3623 \text{ V}}{0.20 \text{ m} \cdot 1.50 \text{ m/s}} \). This gives \( B \approx 1.208 \text{ T} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Faraday's law of induction
Imagine you're watching a magician who makes coins appear out of thin air. Faraday's law of induction is a bit like magic, but it's all science! In simple terms, this law explains how a changing magnetic environment can create an electric "oomph" or push, known as electromotive force (emf).
When you have a conducting loop, such as a wire loop or a moving rod, and it experiences a change in the magnetic field around it, an electromotive force is produced. For instance, if you move a wire through a magnetic field or change the magnetic field over time, emf is generated in that wire.
Faraday quantified this effect with the equation:
In our exercise, this concept is used to find the electric force caused by the rod moving in a magnetic field.
When you have a conducting loop, such as a wire loop or a moving rod, and it experiences a change in the magnetic field around it, an electromotive force is produced. For instance, if you move a wire through a magnetic field or change the magnetic field over time, emf is generated in that wire.
Faraday quantified this effect with the equation:
- \[ \mathcal{E} = - \frac{d \Phi}{dt} \]
In our exercise, this concept is used to find the electric force caused by the rod moving in a magnetic field.
Electromotive force
Electromotive force, often abbreviated as emf, might sound complex, but it's simply the "push" that causes electric charges to move through a conductor. Think of it like the battery that powers your remote control.
In any closed loop of wire, electromotive force is all about generating a voltage when there's a change in the magnetic field. It's measured in volts, similar to how we measure the battery power. The emf isn't really a force; rather, it's the potential difference that's created to move electrons.
In mechanical terms, like in our exercise setup: when the conducting rod slides through a magnetic field, it cuts across magnetic lines of force. This movement induces an emf using:
In any closed loop of wire, electromotive force is all about generating a voltage when there's a change in the magnetic field. It's measured in volts, similar to how we measure the battery power. The emf isn't really a force; rather, it's the potential difference that's created to move electrons.
In mechanical terms, like in our exercise setup: when the conducting rod slides through a magnetic field, it cuts across magnetic lines of force. This movement induces an emf using:
- \[ \mathcal{E} = B \cdot L \cdot v \]
Magnetic field strength
Magnetic field strength describes how strong or weak a magnetic field is at any given point. Imagine the invisible force that tugs on a paperclip when you hold a magnet over it - that's the magnetic field.
In physics, the magnetic field strength is symbolized by \( B \) and its unit is the Tesla (T). Stronger magnetic fields mean a greater ability to induce electric currents and exert forces. Whether you are dealing with a fridge magnet or the giant magnetosphere of Earth, understanding this field's strength is vital.
For example, when a rod moves through this field at a constant velocity, it experiences a magnetic force. This influence results in an induced electric current as the rod acts like a conductor closing the "circuit".
In our exercise, once we knew the emf and other properties of the system, we solved for the magnetic field strength using:
In physics, the magnetic field strength is symbolized by \( B \) and its unit is the Tesla (T). Stronger magnetic fields mean a greater ability to induce electric currents and exert forces. Whether you are dealing with a fridge magnet or the giant magnetosphere of Earth, understanding this field's strength is vital.
For example, when a rod moves through this field at a constant velocity, it experiences a magnetic force. This influence results in an induced electric current as the rod acts like a conductor closing the "circuit".
In our exercise, once we knew the emf and other properties of the system, we solved for the magnetic field strength using:
- \[ B = \frac{\mathcal{E}}{L \cdot v} \]