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A motor run by a 9.0-V battery has a 20-turn square coil with sides of length 5.0 cm and total resistance 28 \(\Omega\). When spinning, the magnetic field felt by the wire in the coil is 0.020 T. What is the maximum torque on the motor?

Short Answer

Expert verified
The maximum torque on the motor is \( 3.214 \times 10^{-4} \space N \cdot m \).

Step by step solution

01

Calculate the Current in the Coil

First, calculate the current flowing through the coil using Ohm's law. The formula is \( I = \frac{V}{R} \), where \( V = 9.0 \,V \) and \( R = 28 \, \Omega \). So, \( I = \frac{9.0}{28} = 0.3214 \, A \).
02

Determine the Area of the Coil

Next, determine the area of one side of the square coil. The formula for the area of a square is \( A = s^2 \), where \( s = 5.0 \, cm = 0.050 \, m \). Thus, \( A = (0.050)^2 = 0.0025 \, m^2 \).
03

Use the Torque Formula

The torque on a current loop in a magnetic field is given by the formula \( \tau = n \times I \times A \times B \times \sin(\theta) \), where \( n = 20 \), \( I = 0.3214 \, A \), \( A = 0.0025 \, m^2 \), \( B = 0.020 \, T \), and \( \theta \) is the angle between the normal to the coil and the magnetic field. For maximum torque, \( \sin(\theta) = 1 \) (when \( \theta = 90^\circ \)).
04

Calculate the Maximum Torque

Substitute the values into the torque formula: \( \tau = 20 \times 0.3214 \times 0.0025 \times 0.020 \times 1 = 3.214 \times 10^{-4} \space N \cdot m \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is an essential principle in electrical circuits that relates voltage, current, and resistance. This law states that the current \(I\) passing through a conductor between two points is directly proportional to the voltage \(V\) across the two points and inversely proportional to the resistance \(R\) of the conductor. Mathematically, it is expressed as:
  • \( I = \frac{V}{R} \)
In the context of our motor problem, we applied Ohm's Law to determine the current flowing through the motor's coil. Given a 9.0-V battery and 28 \(\Omega\) resistance, the current is calculated as \( I = 0.3214 \, A \). Knowing the current is crucial as it determines the amount of torque produced by the motor, linking directly with how effectively the motor can perform its mechanical tasks.
Torque Calculation
Torque in the context of an electric motor relates to the turning ability of the motor's rotor. The formula for torque \(\tau\) generated by a current loop placed in a magnetic field is:
  • \( \tau = n \times I \times A \times B \times \sin(\theta) \)
where:
  • \( n \) is the number of turns in the coil,
  • \( I \) is the current,
  • \( A \) is the area of one turn of the coil,
  • \( B \) is the magnetic field strength,
  • \( \theta \) is the angle between the magnetic field and the normal to the coil.
To achieve maximum torque, the coil should be perpendicular to the magnetic field, i.e., \(\sin(\theta) = 1\). For our motor, substituting the given values results in a maximum torque of \(3.214 \times 10^{-4} \, N \cdot m\). Torque is a key factor in determining the motor's ability to perform work, such as turning a fan or propelling a vehicle.
Magnetic Field Effects
Magnetic fields play a crucial role in the operation of electric motors. A magnetic field exerts a force on a current-carrying wire, which can cause the wire to move—an essential concept for generating torque. In our scenario, the magnetic field is specified as 0.020 T. The influence of the magnetic field is also directly related to the effectiveness of the motor, as described by the torque formula. Several key effects of a magnetic field in an electric motor include:
  • Creating the Lorentz force that causes the rotor to spin.
  • Influencing the magnitude of the torque produced.
  • Affecting the efficiency of energy conversion from electrical to mechanical form.
Understanding these magnetic field effects allows engineers to design more efficient motors by optimizing the magnetic field direction and strength, the number of coil turns, and other factors that determine motor performance.

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Most popular questions from this chapter

(I) A 2.6-m length of horizontal wire carries a 4.5-A current toward the south. The dip angle of the Earth's magnetic field makes an angle of 41\(^\circ\) to the wire. Estimate the magnitude of the magnetic force on the wire due to the Earth's magnetic field of 5.5 \(\times\) 10\(^{-5}\) T.

(II) A horizontal compass is placed 18 cm due south from a straight vertical wire carrying a 48-A current downward. In what direction does the compass needle point at this location? Assume the horizontal component of the Earth's field at this point is 0.45 \(\times\) 10\(^{-4}\) T and the magnetic declination is 0\(^\circ\).

(I) Protons move in a circle of radius 6.10 cm in a 0.566-T magnetic field.What value of electric field could make their paths straight? In what direction must the electric field point?

Two long straight parallel wires are 15 cm apart. Wire A carries 2.0-A current. Wire B's current is 4.0 A in the same direction. (\(a\)) Determine the magnetic field magnitude due to wire A at the position of wire B. (\(b\)) Determine the magnetic field due to wire B at the position of wire A. (\(c\)) Are these two magnetic fields equal and opposite? Why or why not? (\(d\)) Determine the force on wire A due to wire B, and the force on wire B due to wire A. Are these two forces equal and opposite? Why or why not?

(III) A \(\textbf{Hall probe,}\) consisting of a thin rectangular slab of current-carrying material, is calibrated by placing it in a known magnetic field of magnitude 0.10 T. When the field is oriented normal to the slab's rectangular face, a Hall emf of 12 mV is measured across the slab's width. The probe is then placed in a magnetic field of unknownmagnitude \(B\), and a Hall emf of 63 mV is measured. Determine \(B\) assuming that the angle \(\theta\) between the unknown field and the plane of the slab's rectangular face is (a) \(\theta = 90^\circ\), and (b) \(\theta = 60^\circ\)

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