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(II) A person jogs eight complete laps around a 400-m track in a total time of 14.5 min. Calculate (\(a\)) the average speed and (\(b\)) the average velocity, in m/s.

Short Answer

Expert verified
Average speed: 3.68 m/s; Average velocity: 0 m/s.

Step by step solution

01

Determine Total Distance Jogged

To find the total distance jogged, multiply the number of laps by the length of one lap. Here, the number of laps is 8 and each lap is 400 m.\[\text{Total Distance} = 8 \times 400 = 3200 \text{ m}\]
02

Convert Time to Seconds

The total time given is 14.5 minutes. To calculate speed and velocity in meters per second, convert the time to seconds.\[14.5\text{ min} = 14.5 \times 60 = 870\text{ s}\]
03

Calculate Average Speed

Average speed is calculated by dividing the total distance by the total time taken.\[\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{3200 \text{ m}}{870 \text{ s}} \approx 3.68 \text{ m/s}\]
04

Determine Displacement

Since the person jogs around a track and ends up at the starting point, the displacement is 0. Displacement measures the change in position, and if the starting and ending points are the same, this is 0 m.
05

Calculate Average Velocity

Average velocity is calculated by dividing the displacement by the total time taken. Since displacement is 0, the average velocity is:\[\text{Average Velocity} = \frac{\text{Displacement}}{\text{Total Time}} = \frac{0\text{ m}}{870\text{ s}} = 0 \text{ m/s}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement
Displacement is a measurement of how far an object has moved from its initial position, considering only the shortest path. In the context of jogging around a track, if you start and finish at the same point, your displacement is zero. This is because displacement takes into account the initial and final positions, not the path traveled. It's important to differentiate displacement from distance traveled, as distance accounts for the entire path taken, which can be quite lengthy. When dealing with circular paths or laps, like in the exercise, remember:
  • If you return to your starting point, displacement is 0.
  • Displacement focuses on the change in position, not the journey.
Understanding this concept helps clarify why, in scenarios like the exercise, a jogger who completes laps around a track has zero displacement despite having run a significant distance.
Calculation of Velocity
Velocity is not just about how fast you're moving; it incorporates direction, which is why it is a vector quantity. The average velocity is determined by dividing displacement by total time. For circular movements, if your start and end points are identical after completing one or more "laps," your displacement becomes zero. This can lead to a situation where, despite considerable motion, your average velocity is zero. For our jogging exercise:
  • Average velocity becomes zero due to zero displacement.
  • Velocity must involve a directional component to be non-zero.
Thus, whenever you're working with velocity, don't forget to check both the magnitude (speed) and the direction, as both are crucial to understanding velocity completely.
Distance and Time Conversion
When working with average speed calculations, it is important to ensure that the units for distance and time are compatible. Typically, speed and velocity are expressed in meters per second (m/s), so it's vital to convert time into seconds if it's given in minutes or any other unit. Here's why and how you do it:
  • Given time in minutes, multiply by 60 to convert to seconds.
  • Ensure distance is in meters for consistency with m/s.
In the context of the exercise, the conversion from 14.5 minutes to seconds involved multiplying by 60, resulting in 870 seconds. This step is crucial because using inconsistent units could lead to incorrect results. Maintaining unit consistency simplifies calculations and helps prevent errors in determining average speeds or velocities.

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Most popular questions from this chapter

(I) A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.55 s. How high is the cliff?

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