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(II) A 75-W, 120-V bulb is connected in parallel with a 25-W, 120-V bulb. What is the net resistance?

Short Answer

Expert verified
The net resistance is approximately 144 Ω.

Step by step solution

01

Calculate the Resistance of Each Bulb

To find the resistance of each bulb, use the formula for electrical power: \( P = \frac{V^2}{R} \), where \( P \) is power, \( V \) is voltage, and \( R \) is resistance. Rearranging the formula gives \( R = \frac{V^2}{P} \). For the 75-W bulb, \( R_1 = \frac{120^2}{75} = 192 \ \Omega \). For the 25-W bulb, \( R_2 = \frac{120^2}{25} = 576 \ \Omega \).
02

Understanding Parallel Resistance

When resistors are placed in parallel, the total or net resistance \( R_{net} \) can be found using the formula \( \frac{1}{R_{net}} = \frac{1}{R_1} + \frac{1}{R_2} \). This formula accounts for the fact that the total resistance decreases in a parallel circuit.
03

Calculate the Net Resistance

Substitute the resistances from Step 1 into the parallel resistance formula: \( \frac{1}{R_{net}} = \frac{1}{192} + \frac{1}{576} \). Calculate each reciprocal: \( \frac{1}{192} \approx 0.005208 \) and \( \frac{1}{576} \approx 0.001736 \). Sum these values: \( \frac{1}{R_{net}} \approx 0.005208 + 0.001736 = 0.006944 \). Finally, take the reciprocal to find \( R_{net} \approx \frac{1}{0.006944} \approx 144 \ \Omega \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrical Resistance
Electrical resistance is a measure of how much an object opposes the flow of electric current. It is an essential concept in understanding how circuits work. Resistance is measured in ohms (\( \Omega \)) and, in a physical sense, it's like a boulder in a stream blocking water flow. The higher the resistance, the lower the current that can pass through.
Electrical devices, like light bulbs, have resistance, which can be calculated using their power rating and the voltage they operate on. By applying the formula:
  • \( R = \frac{V^2}{P} \)
you can find the resistance value. For example, a 75-W, 120-V bulb has a resistance of \( 192 \Omega \), as shown by substituting the values into the formula. Similarly, a 25-W, 120-V bulb has a higher resistance of \( 576 \Omega \), meaning it is less "open" to allowing current to flow as compared to the 75-W bulb.
Electrical Power
Electrical power in a circuit describes the rate at which energy is used or consumed. It's measured in watts (W). Every electrical appliance specifies its power rating, indicating how much energy it uses over time. Understanding power helps us gauge how much electricity is drawn by devices, which is vital for managing energy consumption effectively.
The relationship between power, voltage, and resistance is given by the equation:
  • \( P = \frac{V^2}{R} \),
where \( P \) is power, \( V \) is voltage, and \( R \) is resistance. This equation tells us that for a fixed voltage, increasing the power lowers the resistance, and vice versa. For instance, the 75-W bulb uses more power and hence has a lower resistance than the 25-W bulb. This knowledge is practical in understanding how varying appliances have different electrical requirements and their impact on a circuit.
Ohm's Law
Ohm's Law is a fundamental principle in electronics that describes the relationship between voltage, current, and resistance. It is expressed as:
  • \( V = I \times R \),
where \( V \) is the voltage across the resistor, \( I \) is the current flowing through it, and \( R \) is the resistance. This law acts as a guideline for predicting how current flows in a circuit subjected to a certain voltage and resistance.
In a parallel circuit, such as the one with the 75-W and 25-W bulbs, Ohm's Law supports understanding how the division of current occurs across components. In such circuits, while the voltage across each component remains the same, currents vary inversely with their resistance values. Due to this, the total resistance in a parallel circuit scenario often decreases, simplifying paths for the current, and hence is calculated as:
  • \( \frac{1}{R_{net}} = \frac{1}{R_1} + \frac{1}{R_2} \),
helping us determine the net effective resistance, like finding \( R_{net} \approx 144 \Omega \) for our light bulb example.

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Most popular questions from this chapter

(II) Three 1.70-k\(\Omega\) resistors can be connected together in four different ways, making combinations of series and/or parallel circuits. What are these four ways, and what is the net resistance in each case?

How many \(\frac{1}{2}\)-W resistors, each of the same resistance, must be used to produce an equivalent 3.2-k\(\Omega\), 3.5-W resistor? What is the resistance of each, and how must they be connected? Do not exceed \(P = \frac{1}{2}\)W in each resistor.

A \(\textbf{Wheatstone bridge}\) is a type of "bridge circuit" used to make measurements of resistance. The unknown resistance to be measured, \(R_x,\) is placed in the circuit with accurately known resistances \(R_1, R_2,\) and \(R_3\) (Fig. 19-76). One of these, is a variable resistor which is adjusted so that when the switch is closed momentarily, the ammeter A shows zero current flow. The bridge is then said to be balanced. (\(a\)) Determine \(R_x\) in terms of \(R_1, R_2,\) and \(R_3\). (\(b\)) If a Wheatstone bridge is "balanced" when \(R_1 =\) 590 \(\Omega\), \(R_2 =\) 972 \(\Omega\), and \(R_3 =\) 78.6 \(\Omega\), what is the value of the unknown resistance?

(I) Three 45-\(\Omega\) lightbulbs and three 65-\(\Omega\) lightbulbs are connected in series. (\(a\)) What is the total resistance of the circuit? (\(b\)) What is the total resistance if all six are wired in parallel?

Suppose that a person's body resistance is 950 \(\Omega\) (moist skin). (\(a\)) What current passes through the body when the person accidentally is connected to 120 V? (\(b\)) If there is an alternative path to ground whose resistance is 25 \(\Omega\), what then is the current through the body? (\(c\)) If the voltage source can produce at most 1.5 A, how much current passes through the person in case (\(b\))?

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