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Thunderclouds may develop a voltage difference of about 5 \(\times\) 10\(^7\)V. Given that an electric field of 3 \(\times\) 10\(^6\)V/m is required to produce an electrical spark within a volume of air, estimate the length of a thundercloud lightning bolt. [Can you see why, when lightning strikes from a cloud to the ground, the bolt has to propagate as a sequence of steps?]

Short Answer

Expert verified
The estimated length of the lightning bolt is approximately 16.67 meters.

Step by step solution

01

Understand the Relationship

To find the length of the lightning bolt, we need to understand the relationship between the electric field, voltage, and distance. The electric field \(E\) is defined as the voltage \(V\) divided by the distance \(d\): \(E = \frac{V}{d}\).
02

Rearrange the Equation

Rearrange the equation to solve for the distance \(d\): \(d = \frac{V}{E}\). This equation will help us determine the length of the lightning bolt if we know the voltage and the electric field strength.
03

Substitute Given Values

Now, substitute the given values into the equation. The voltage difference \(V\) is \(5 \times 10^7\) volts and the electric field \(E\) required to produce a spark is \(3 \times 10^6\) volts per meter. Substitute these values in: \(d = \frac{5 \times 10^7}{3 \times 10^6}\).
04

Calculate the Length

Perform the division to calculate the length of the lightning bolt: \(d = \frac{5 \times 10^7}{3 \times 10^6} = \frac{50}{3} \approx 16.67\) meters.
05

Understand the Propagation

Consider why a lightning bolt propagates as a sequence of steps. The air can only break down and allow current to flow where the field strength is high enough, so it happens in segments, as each step increases the electric potential between the cloud and ground.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Field
The concept of an electric field is essential in understanding how lightning bolts form. An electric field describes the influence a charged object has on surrounding charges. It can be thought of as a field of force that charges experience. The strength of this field determines how much a charge will accelerate if placed within it. For lightning, the electric field is crucial. It dictates how the energy within a thundercloud can break down air molecules, leading to a discharge. This discharge is what we perceive as a lightning bolt.

When discussing electric fields, it's important to grasp that the field's strength is measured in volts per meter (V/m). This measurement tells us how much potential energy a charge will gain or lose as it moves through space. In the case of our exercise, generating an electric spark requires a field of at least 3 \(\ times \) 10\(^6\) V/m. It's this intense field that forces the air to ionize, creating the path for the lightning bolt.
Voltage Difference
The voltage difference, also known as potential difference, is a key player in creating lightning bolts. It describes how much potential energy is available to push charges from one point to another. In terms of a thunderstorm, different regions within a cloud can accumulate vast amounts of charge. This produces a significant voltage difference between these regions, or between the cloud and the ground.

A voltage difference as large as 5 \(\times\) 10\(^7\) V, as provided in the exercise, indicates the incredible energy potential contained within a thundercloud. This difference is quite powerful, and, when sufficient conditions are met, it triggers a movement of charges through the atmosphere. As the electric field strengthens and overcomes resistance in the air, the charges quickly follow the potential difference, resulting in a lightning bolt.

Understanding voltage difference helps explain why lightning can travel such substantial distances and why it can be so destructive upon impact with the ground.
Thunderclouds
Thunderclouds are the birthplace of lightning and play a critical role in its formation. Composed of water droplets and ice crystals, these clouds become electrically charged during storms. Through processes like friction and collision within the cloud, charges separate, leading to a polarized cloud structure with distinct positive and negative areas.

The separation and accumulation of charges within a thundercloud create intense electric fields and significant voltage differences. This is the setup that leads to lightning. When the electric stress overcomes the air's insulating properties, electrical breakdown occurs, leading to a discharge – a lightning strike.

Thunderclouds essentially act as giant capacitors. They store energy until the conditions are ripe for release. This energy is released through currents that even out the disparities in electric charge, which is why understanding the dynamics within thunderclouds is key to understanding lightning itself.
Electric Spark
An electric spark is the visible and audible result of a sudden discharge of electricity through the air. Sparks occur when the voltage is high enough for charges to jump between two points that usually don't conduct electricity. When a cloud builds up a substantial charge, the air can be ionized, creating a conductive path for the charge to flow.

In the context of a lightning bolt, an electric spark is the first visible sign that the electric field within the cloud has reached critical strength. The air is overcome by the high electric field (in this exercise, 3 \(\times \) 10\(^6\) V/m), allowing the stored charge to flow rapidly. This flow ionizes more air along its path, allowing the spark to grow into a full lightning bolt.

Understanding electric sparks helps to explain how electrical energy is transferred through the atmosphere and why it happens in rapid, bright bursts, setting the stage for larger phenomena like lightning.

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Most popular questions from this chapter

A huge 4.0-F capacitor has enough stored energy to heat 2.8 kg of water from 21\(^\circ\)C to 95\(^\circ\)C. What is the potential difference across the plates?

In the \(\textbf{dynamic random access memory (DRAM)}\) of a computer, each memory cell contains a capacitor for charge storage. Each of these cells represents a single binarybit value of "1" when its 35-fF capacitor (1 fF = 10\(^{-15}\)) is charged at 1.5 V, or "0" when uncharged at 0 V. (a) When fully charged, how many excess electrons are on a cell capacitor's negative plate? (\(b\)) After charge has been placed on a cell capacitor's plate, it slowly "leaks" off at a rate of about 0.30fC/s. How long does it take for the potential difference across this capacitor to decrease by 2.0\(\%\) from its fully charged value? (Because of this leakage effect, the charge on a DRAM capacitor is "refreshed" many times per second.) Note: A DRAM cell is shown in Fig. 21-29.

A 3.4\(\mu\)C and a -2.6\(\mu\)C charge are placed 2.5 cm apart. At what points along the line joining them is (\(a\)) the electric field zero, and (\(b\)) the electric potential zero?

(I) The electric field between two parallel plates connected to a 45-V battery is 1900 V/m. How far apart are the plates?

In an older television tube, electrons are accelerated by thousands of volts through a vacuum. If a television set were laid on its back, would electrons be able to move upward against the force of gravity? What potential difference, acting over a distance of 2.4 cm, would be needed to balance the downward force of gravity so that an electron would remain stationary? Assume that the electric field is uniform.

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