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(II) A 64-kg ice-skater moving at 7.5 m/s glides to a stop. Assuming the ice is at 0\(^\circ\)C and that 50\(\%\) of the heat generated by friction is absorbed by the ice, how much ice melts?

Short Answer

Expert verified
Approximately 0.0027 kg of ice melts.

Step by step solution

01

Determine Kinetic Energy

Calculate the initial kinetic energy of the ice-skater using the formula for kinetic energy: \( KE = \frac{1}{2}mv^2 \). Here, \( m = 64 \text{ kg} \) and \( v = 7.5 \text{ m/s} \). \[ KE = \frac{1}{2} \times 64 \times (7.5)^2 \]\[ KE = 0.5 \times 64 \times 56.25 = 1800 \text{ J} \] The initial kinetic energy is 1800 Joules.
02

Calculate Heat Absorbed by Ice

Since 50% of the generated heat is absorbed by the ice, we calculate the heat absorbed by the ice as \( Q = 0.5 \times KE \).\[ Q = 0.5 \times 1800 = 900 \text{ J} \] The heat absorbed by the ice is 900 Joules.
03

Find Mass of Ice Melted

The heat needed to melt ice is given by \( Q = mL_f \), where \( L_f = 334,000 \text{ J/kg} \) is the latent heat of fusion for ice. Rearranging for mass, \( m = \frac{Q}{L_f} \).\[ m = \frac{900}{334,000} \] \[ m \approx 0.0027 \text{ kg} \] Thus, approximately 0.0027 kg of ice melts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy an object has due to its motion. For an ice-skater moving on the ice, this energy depends on both the mass of the skater and their speed. The formula to calculate kinetic energy is: \[KE = \frac{1}{2}mv^2\]where \( m \) is the mass and \( v \) is the speed. In our example, the ice-skater weighs 64 kg and is moving at 7.5 m/s. Using the formula, we calculate:* \( KE = \frac{1}{2} \times 64 \times (7.5)^2 \)* \( KE = 0.5 \times 64 \times 56.25 \)* \( KE = 1800 \text{ J} \)This means the ice-skater initially possesses 1800 Joules of kinetic energy. As the skater stops, this energy gets converted mainly into heat due to friction between the skates and the ice.
Heat Absorption
When the ice-skater glides to a stop, the kinetic energy is transformed into thermal energy because of friction. It's essential to understand where this energy goes. Friction on ice assumes that not all energy is used to melt the ice. In this scenario, 50% of the generated heat is absorbed by the ice. This is calculated as:\[Q = 0.5 \times KE\]For our skater:* \( Q = 0.5 \times 1800 \)* \( Q = 900 \text{ J} \)Thus, 900 Joules of heat are absorbed by the ice, which contributes to the melting process.
Latent Heat of Fusion
The latent heat of fusion is the amount of heat energy required to change a substance from solid to liquid at its melting point, without changing its temperature. For ice, this value is given as 334,000 J/kg. To calculate the mass of ice that melts, we use the formula:\[m = \frac{Q}{L_f}\]where \( m \) is the mass of melted ice, \( Q \) is the heat absorbed, and \( L_f \) is the latent heat of fusion.Applying the values from our problem:* \( m = \frac{900}{334,000} \)* \( m \approx 0.0027 \text{ kg} \)Therefore, approximately 0.0027 kg of ice melts due to the heat absorbed. This illustrates the concept of latent heat effectively, showing how even a small amount of absorbed energy causes a phase change from solid to liquid.

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Most popular questions from this chapter

A leaf of area 40 cm\(^2\) and mass \(4.5 \times 10^{-4}\) kg directly faces the Sun on a clear day. The leaf has an emissivity of 0.85 and a specific heat of 0.80 kcal/kg\(\cdot\)K.(\(a\)) Estimate the energy absorbed per second by the leaf from the Sun, and then (\(b\)) estimate the rate of rise of the leaf's temperature. (\(c\)) Will the temperature rise continue for hours? Why or why not? (\(d\)) Calculate the temperature the leaf would reach if it lost all its heat by radiation to the surroundings at 24\(^\circ\)C. (\(e\)) In what other ways can the heat be dissipated by the leaf?

(II) How long does it take a 750-W coffeepot to bring to a boil 0.75 L of water initially at 11\(^\circ\)C? Assume that the part of the pot which is heated with the water is made of 280 g of aluminum, and that no water boils away.

(II) A 0.095-kg aluminium sphere is dropped from the roof of a 55-m-high building. If 65\(\%\) of the thermal energy produced when it hits the ground is absorbed by the sphere, what is its temperature increase?

(II) When a diver jumps into the ocean, water leaks into the gap region between the diver's skin and her wetsuit, forming a water layer about 0.5 mm thick. Assuming the total surface area of the wetsuit covering the diver is about 1.0 m\(^2\), and that ocean water enters the suit at 10\(^\circ\)C and is warmed by the diver to skin temperature of 35\(^\circ\)C, estimate how much energy (in units of candy bars \(=\) 300 kcal) is required by this heating process.

(II) A 55-g bullet traveling at 250 m/s penetrates a block of ice at 0\(^\circ\)C and comes to rest within the ice. Assuming that the temperature of the bullet doesn't change appreciably, how much ice is melted as a result of the collision?

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