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(II) An iron boiler of mass 180 kg contains 730 kg of water at 18\(^\circ\)C. A heater supplies energy at the rate of 58,000 kJ/h. How long does it take for the water (\(a\)) to reach the boiling point, and (\(b\)) to all have changed to steam?

Short Answer

Expert verified
Water reaches boiling point in 4.33 hours; convert to steam in 28.45 hours, total 32.78 hours.

Step by step solution

01

Understand the Problem

We need to calculate the time required for water in a boiler to (a) reach the boiling point from an initial temperature of 18°C, and (b) completely convert to steam. The boiler has a mass of 180 kg, and the water has a mass of 730 kg. The heater supplies energy at a rate of 58,000 kJ/h.
02

Calculate Energy to Heat Water to Boiling Point

First, calculate the energy required to heat the water from 18°C to 100°C. Use the formula:\[ Q_1 = m c \Delta T \]where \( m = 730 \text{ kg} \) is the mass of the water, \( c = 4.186 \text{ kJ/kg°C} \) is the specific heat capacity of water, and \( \Delta T = 100°C - 18°C = 82°C \).Calculate:\[ Q_1 = 730 \times 4.186 \times 82 \approx 250991.4 \text{ kJ} \]
03

Calculate Time to Heat Water to Boiling Point

We know the boiler is providing energy at a rate of 58,000 kJ/h. To find the time \( t_1 \) to heat water to the boiling point:\[ t_1 = \frac{Q_1}{\text{Energy Rate}} = \frac{250991.4}{58000} \approx 4.327 \text{ hours} \]
04

Calculate Energy for Phase Change to Steam

Once the water is at 100°C, calculate the energy required to convert 730 kg of water into steam. The latent heat of vaporization of water is 2260 kJ/kg. Use the formula:\[ Q_2 = m \cdot L \]where \( L = 2260 \text{ kJ/kg} \). Calculate:\[ Q_2 = 730 \times 2260 = 1649800 \text{ kJ} \]
05

Calculate Time for Phase Change to Steam

Using the same energy rate, calculate the time \( t_2 \) required for the phase change:\[ t_2 = \frac{Q_2}{\text{Energy Rate}} = \frac{1649800}{58000} \approx 28.448 \text{ hours} \]
06

Calculate Total Time

The total time required is the sum of the time taken to reach the boiling point and the time to convert all water to steam:\[ t_{\text{total}} = t_1 + t_2 = 4.327 + 28.448 \approx 32.775 \text{ hours} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Heat Capacity
Specific heat capacity is a key concept in thermodynamics that helps determine how much heat energy, or thermal energy, is required to change the temperature of a substance. It is defined by the amount of heat needed to raise the temperature of 1 kilogram of a substance by 1 degree Celsius (or Kelvin).
  • The formula to calculate the heat needed is: \( Q = mc \Delta T \).
  • Here, \( m \) is the mass of the substance, \( c \) is its specific heat capacity, and \( \Delta T \) is the change in temperature.
Water, with a specific heat capacity of 4.186 kJ/kg°C, requires a significant amount of energy to see a change in its temperature. For example, to heat 730 kg of water from 18°C to 100°C, you would use the said formula. It will show you that 250,991.4 kJ is necessary for the water in this exercise to reach its boiling point. Understanding specific heat capacity can give insights into why different materials heat up and cool down at different rates, impacting everything from our daily cooking to industrial processes.
Latent Heat of Vaporization
The latent heat of vaporization is the amount of heat energy required to change a substance from liquid to gas without a temperature change. During this phase, the substance absorbs heat energy but stays at a constant temperature as the energy is used to break the intermolecular bonds.
  • The formula for calculating the required energy is: \( Q = mL \).
  • Here, \( m \) represents the mass and \( L \) is the latent heat of vaporization.
For water, this value is quite high at 2260 kJ/kg, indicating a massive amount of energy needed to convert liquid water into steam. In our exercise, transforming 730 kg of water into steam needs 1,649,800 kJ.
This concept is crucial in many processes such as power generation and climate science. When considering applications, the high latent heat of vaporization of water makes it suitable for use in heating and cooling systems, as it can store and release large amounts of energy efficiently.
Phase Change
A phase change refers to the transition of matter from one state to another, such as from solid to liquid, liquid to gas, or vice versa. This process occurs without a temperature change in the substance but involves energy exchange in the form of latent heat. There are several key points to understand in phase changes:
  • The energy required or released during the phase change is known as latent heat.
  • Temperature remains constant during the phase transition.
In our exercise, as the water reaches 100°C, it undergoes a phase change from a liquid to a gaseous state (steam). This change requires energy, which continues to be supplied by the heater even though the temperature doesn't increase.
Phase changes are important not only in educational problems but also in nature and technology. For instance, the melting of ice caps and the boiling of water in industrial boilers rely heavily on these concepts. Understanding phase changes can lead to better energy management and innovations in thermal systems.

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Most popular questions from this chapter

A house thermostat is normally set to 22\(^\circ\)C, but at night it is turned down to 16\(^\circ\)C for 9.0 h. Estimate how much more heat would be needed (state as a percentage of daily usage) if the thermostat were not turned down at night. Assume that the outside temperature averages 0\(^\circ\)C for the 9.0 h at night and 8\(^\circ\)C for the remainder of the day, and that the heat loss from the house is proportional to the temperature difference inside and out. To obtain an estimate from the data, you must make other simplifying assumptions; state what these are.

(II) How long does it take a 750-W coffeepot to bring to a boil 0.75 L of water initially at 11\(^\circ\)C? Assume that the part of the pot which is heated with the water is made of 280 g of aluminum, and that no water boils away.

(I) What is the specific heat of a metal substance if 135 kJ of heat is needed to raise 4.1 kg of the metal from 18.0\(^\circ\)C to 37.2\(^\circ\)C?

(II) When a diver jumps into the ocean, water leaks into the gap region between the diver's skin and her wetsuit, forming a water layer about 0.5 mm thick. Assuming the total surface area of the wetsuit covering the diver is about 1.0 m\(^2\), and that ocean water enters the suit at 10\(^\circ\)C and is warmed by the diver to skin temperature of 35\(^\circ\)C, estimate how much energy (in units of candy bars \(=\) 300 kcal) is required by this heating process.

During light activity, a 70-kg person may generate 200 kcal/h. Assuming that 20\(\%\) of this goes into useful work and the other 80\(\%\) is converted to heat, estimate the temperature rise of the body after 45 min if none of this heat is transferred to the environment.

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