/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 If you used only a keyboard to e... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If you used only a keyboard to enter data, how many years would it take to fill up the hard drive in a computer that can store 1.0 terabytes (1.0 \(\times\) 10\(^{12}\) bytes) of data? Assume 40-hour work weeks, and that you can type 180 characters per minute, and that one byte is one keyboard character.

Short Answer

Expert verified
It would take approximately 44,514 years to fill up the hard drive.

Step by step solution

01

Calculate bytes typed per minute

Since each character typed is equal to one byte, if you type 180 characters per minute, you type 180 bytes per minute.
02

Calculate bytes typed per hour

To find out how many bytes you type in an hour, multiply the bytes typed per minute by 60 minutes. So, \(180\, \text{bytes/minute} \times 60\, \text{minutes/hour} = 10,800\, \text{bytes/hour}.\)
03

Calculate bytes typed per week

Given that you work 40 hours per week, multiply the number of bytes typed per hour by the number of hours in a workweek: \(10,800\, \text{bytes/hour} \times 40\, \text{hours/week} = 432,000\, \text{bytes/week}.\)
04

Calculate weeks needed for 1 terabyte

The hard drive can store \(1.0 \times 10^{12}\, \text{bytes}\). To find how many weeks it takes to fill this, divide the total storage capacity by the bytes typed per week: \(\frac{1.0 \times 10^{12}\, \text{bytes}}{432,000\, \text{bytes/week}} \approx 2,314,815.24\, \text{weeks}.\)
05

Convert weeks to years

Since there are approximately 52 weeks in a year, divide the number of weeks by 52 to convert it into years: \(\frac{2,314,815.24\, \text{weeks}}{52\, \text{weeks/year}} \approx 44,513.75\, \text{years}.\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Data Storage
Data storage refers to the way information is saved and retrieved on digital devices. Every piece of data, whether it's a document, a photo, or music, is stored in bytes. A byte is the basic unit of both physical and virtual data. Each character you type on a computer or a mobile device translates into one byte of information.
For instance, when you type the word 'Hello,' you are using 5 characters which equals 5 bytes of data. Basic knowledge of data storage helps in understanding how storage devices like hard drives save and manage information. It's important to know that as digital information grows, the need for storage space increases exponentially. This is why understanding data storage is crucial in our data-driven world.
Characters per Minute
Characters per minute measure how fast you can type, affecting how quickly data is input into a system. In this particular exercise, we assumed a typing speed of 180 characters per minute. Each character is equivalent to one byte, so typing 180 characters means you're typing 180 bytes in a minute.
Typing speed is an essential factor when estimating how quickly tasks like data entry can be completed. It is often measured in keys per minute or words per minute. Words per minute can vary, considering the average word consists of 5-6 characters. Whether you're a fast typist or just practicing, understanding your typing speed in characters can help plan workloads. Fast typists might complete certain tasks in less time than anticipated, leading to increased efficiency.
Terabyte
A terabyte is a sizable unit of data storage, and it equates to 1 trillion bytes, or precisely, 1.0 \( \times \) 10\(^{12}\) bytes. It's crucial for holding extensive quantities of information. For comparison, a gigabyte (GB) is significantly smaller, with 1 terabyte being 1,000 gigabytes.
Having a hard drive with a terabyte of space means you can store a vast amount of data, such as tens of thousands of hours of music, millions of documents, or hours of video footage in high definition. Working with terabytes is increasingly common as digital technologies advance, making it essential to grasp how vast this unit of storage is. An understanding of such large storage capacity allows better management of digital resources and makes planning for data growth more pragmatic.
Time Estimation
When you're looking to fill a storage device up with data through consistent typing, estimating the time required to do so becomes necessary. In the exercise, the aim was to fill 1 terabyte of data by typing. With a typing speed of 180 characters per minute, the task was to determine how long it would take.
First, calculate the weekly data input by considering the total number of bytes input each minute, then per hour, and eventually per week. With the storage capacity known, dividing the total bytes by weekly input gives the number of weeks required. Finally, by dividing weeks by the number of weeks in a year, we convert our estimate to years.
  • Bytes per minute: 180
  • Bytes per hour: 10,800
  • Bytes per week: 432,000 (assuming a 40-hour workweek)
  • Total weeks required for 1.0 terabyte: approximately 2,314,815.24 weeks
  • Converted to years: about 44,513.75 years
Understanding time estimation helps in planning and managing digital tasks effectively, ensuring realistic goals and efficient results in various work scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A certain compact disc (CD) contains 783.216 megabytes of digital information. Each byte consists of exactly 8 bits. When played, a CD player reads the CD's information at a constant rate of 1.4 megabits per second. How many minutes does it take the player to read the entire CD?

(III) You are lying on a beach, your eyes 20 cm above the sand. Just as the Sun sets, fully disappearing over the horizon, you immediately jump up, your eyes now 150 cm above the sand, and you can again just see the top of the Sun. If you count the number of seconds (= \(t\)) until the Sun fully disappears again, you can estimate the Earth's radius. But for this Problem, use the known radius of the Earth to calculate the time \(t\).

(II) A \(\textbf{light-year}\) is the distance light travels in one year (at speed \(=\) 2.998 \(\times\) 10\(^8\) m/s). (\(a\)) How many meters are there in 1.00 light-year? (\(b\)) An astronomical unit (AU) is the average distance from the Sun to Earth, 1.50 \(\times\) 10\(^8\) km. How many AU are there in 1.00 light- year?

Recent findings in astrophysics suggest that the observable universe can be modeled as a sphere of radius \(R =\) 13.7 \(\times\) 10\(^9\) light-years \(=\) 13.0 \(\times\) 10\(^25\) m with an average total mass density of about 1 \(\times\) 10\(^{-26}\) kg/m\(^3\). Only about 4% of total mass is due to "ordinary" matter (such as protons, neutrons, and electrons). Estimate how much ordinary matter (in kg) there is in the observable universe. (For the light-year, see Problem 19.)

(I) Write the following as full (decimal) numbers without prefixes on the units: (\(a\)) 286.6 mm, (\(b\)) 85 \(\mu\)V, (\(c\)) 760 mg, (\(d\)) 62.1 ps, (\(e\)) 22.5 nm, (\(f\)) 2.50 gigavolts.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.