/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 (II) The Sun, on average, is 93 ... [FREE SOLUTION] | 91Ó°ÊÓ

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(II) The Sun, on average, is 93 million miles from Earth. How many meters is this? Express (\(a\)) using powers of 10, and (\(b\)) using a metric prefix (km).

Short Answer

Expert verified
(a) \(1.4966862 \times 10^{11}\) m, (b) 149,668,620 km

Step by step solution

01

Convert miles to kilometers

To convert miles to kilometers, use the conversion factor: 1 mile = 1.60934 kilometers. So, multiply 93 million miles by this factor: \[ 93,000,000 ext{ miles} \times 1.60934 \text{ km/mile} = 149,668,620 \text{ km} \]
02

Express in scientific notation (powers of 10)

To express the kilometers in scientific notation, identify the significant figures and place the decimal:\[ 149,668,620 \text{ km} = 1.4966862 \times 10^{8} \text{ km} \]
03

Convert kilometers to meters

Since 1 kilometer is equal to 1,000 meters, convert kilometers to meters by multiplying:\[ 1.4966862 \times 10^{8} \text{ km} \times 1,000 \frac{\text{m}}{\text{km}} = 1.4966862 \times 10^{11} \text{ m} \]
04

Express using a metric prefix (kilometers)

Since we already have the distance in kilometers from Step 1, express it using the metric prefix as follows:\[ 149,668,620 \text{ km} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Miles to Kilometers Conversion
Converting miles to kilometers is a common task in many scientific and everyday calculations. The conversion factor between miles and kilometers is that 1 mile is equivalent to 1.60934 kilometers. This means that if you have a distance in miles, you can find out how many kilometers it equals by multiplying the miles by 1.60934.
For example, to convert 93 million miles to kilometers, you multiply:
  • 93,000,000 miles
  • By the conversion factor 1.60934 km/mile
This calculation gives us approximately 149,668,620 kilometers. This conversion is useful in numerous fields such as astronomy, to understand vast distances in a unit that may be more familiar or easier to work with.
Scientific Notation
Scientific notation is a way to express very large or very small numbers concisely. In scientific notation, numbers are written as a product of a number (between 1 and 10) and a power of ten.
For instance, to express 149,668,620 kilometers in scientific notation:
  • Identify the significant figures: 1.4966862
  • Count the places the decimal has moved to the right: 8 places
  • Write the number as: \( 1.4966862 \times 10^{8} \)
This notation helps simplify calculations and makes it easier to read and compare very large numbers, such as astronomical distances. It also reduces the error when dealing with the precision of large numbers.
Metric Prefixes
Metric prefixes are used in the metric system to denote multiples of units, providing a shorthand way to express quantities. The prefix 'kilo' means one thousand, and it is often used with meters to give kilometers.
The process of using metric prefixes makes it easier to deal with large numbers by avoiding long strings of zeros. Instead of writing distances in meters when dealing with such large numbers, kilometers are used. As in our example:
  • 1 kilometer = 1,000 meters
  • 1.4966862 \( \times 10^{8} \) kilometers means the same as 149,668,620 km
Using these prefixes allows us to maintain clarity and reduce mistakes in calculations, making these measurements easily interpretable. Metric prefixes not only simplify the expression of large or small quantities but also allow clear communication across various scientific fields.

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Most popular questions from this chapter

Recent findings in astrophysics suggest that the observable universe can be modeled as a sphere of radius \(R =\) 13.7 \(\times\) 10\(^9\) light-years \(=\) 13.0 \(\times\) 10\(^25\) m with an average total mass density of about 1 \(\times\) 10\(^{-26}\) kg/m\(^3\). Only about 4% of total mass is due to "ordinary" matter (such as protons, neutrons, and electrons). Estimate how much ordinary matter (in kg) there is in the observable universe. (For the light-year, see Problem 19.)

(III) The smallest meaningful measure of length is called the \(\textbf{Planck length}\), and is defined in terms of three fundamental constants in nature: the speed of light \(c =\) 3.00 \(\times\) 10\(^8\) m/s, the gravitational constant \(G =\) 6.67 \(\times\) 10\(^{-11}\) m\(^3\)/kg \(\cdot\) s\(^2\) and Planck's constant \(h =\) 6.63 \(\times\) 10\(^{-34}\) kg \(\cdot\) m\(^2\)/s. The Planck length \(l_\mathrm{p}\) is given by the following combination of these three constants: $$l_\mathrm{p} = \sqrt{ \frac{Gh}{c^3}. }$$ Show that the dimensions of \(l_\mathrm{p}\) are length [\(L\)], and find the order of magnitude of \(l_\mathrm{p}\). [Recent theories (Chapters 32 and 33) suggest that the smallest particles (quarks, leptons) are "strings" with lengths on the order of the Planck length, These theories also suggest that the "Big Bang," with which the universe is believed to have begun, started from an initial size on the order of the Planck length.]

(II) The speed \(\upsilon\) of an object is given by the equation \(\upsilon = At^3 - Bt\), where \(t\) refers to time. (\(a\)) What are the dimensions of \(A\) and \(B\)? (\(b\)) What are the SI units for the constants \(A\) and \(B\)?

(II) (\(a\)) How many seconds are there in 1.00 year? (\(b\)) How many nanoseconds are there in 1.00 year? (\(c\)) How many years are there in 1.00 second?

(II) How much longer (percentage) is a one-mile race than a 1500-m race ("the metric mile")?

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