/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 (II) Derive a formula for the ma... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(II) Derive a formula for the maximum speed \(v_{\max }\) of a simple pendulum bob in terms of \(g\) , the length \(L,\) and the angle of swing \(\theta_{0} .\)

Short Answer

Expert verified
\(v_{\max} = \sqrt{2gL(1 - \cos \theta_0)}\)

Step by step solution

01

Understanding the Problem

To derive the formula for the maximum speed of a pendulum bob, we first summarize the system: a simple pendulum consists of a mass (bob) attached to a string of length \(L\) that swings with a maximum angle \(\theta_0\) from the vertical. We want to find \(v_{\max}\), the maximum speed of the bob, using gravitational acceleration \(g\), the pendulum length \(L\), and the maximum swing angle \(\theta_0\).
02

Conservation of Energy

The principle of conservation of energy states that the total mechanical energy (potential + kinetic) in a system remains constant if only conservative forces are involved. For the pendulum, this means the potential energy at the highest point equals the kinetic energy at the lowest point.
03

Calculating Potential Energy at Maximum Height

When the pendulum is at its maximum height, its speed is zero, and all its energy is potential. The height \(h\) can be found using geometry: \(h = L(1 - \cos \theta_0)\). The potential energy \(U\) at this point is \(U = mgh = mgL(1 - \cos \theta_0)\).
04

Kinetic Energy at Lowest Point

At the lowest point, the pendulum's energy is purely kinetic. The kinetic energy \(K\) is given by \(K = \frac{1}{2}mv_{\max}^2\), where \(v_{\max}\) is the maximum speed we want to find.
05

Equating Energies and Solving for Maximum Speed

Since the potential energy at the highest point equals the kinetic energy at the lowest point, we have:\[ mgL(1 - \cos \theta_0) = \frac{1}{2}mv_{\max}^2 \]Solving for \(v_{\max}\) gives us:\[ v_{\max} = \sqrt{2gL(1 - \cos \theta_0)} \]
06

Final Formula for Maximum Speed

The formula derived for the maximum speed of the pendulum bob is:\[ v_{\max} = \sqrt{2gL(1 - \cos \theta_0)} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

maximum speed formula
The maximum speed of a pendulum bob is a crucial component when analyzing the behavior and dynamics of a simple pendulum. This formula is derived by considering the conversion of energy from potential to kinetic throughout the pendulum's swing.
To obtain the maximum speed, denote the angle from which the pendulum is released as \(\theta_0\), the length of the pendulum as \(L\), and the gravitational acceleration as \(g\). The maximum speed \(v_{\max}\) occurs at the bottom-most point of the swing. Using the derived formula:
  • \(v_{\max} = \sqrt{2gL(1 - \cos \theta_0)}\)
This expression tells us that the speed depends on the initial angular displacement and the pendulum's length and gravitational force. This is a result of energy transformation from the initial potential energy to the kinetic energy at the nadir of the swing.
conservation of energy
The conservation of energy principle is a fundamental concept in physics that applies to simple pendulums. It underscores the idea that energy within a closed system remains constant over time. For a pendulum, this principle is instrumental in explaining how potential energy converts to kinetic energy and back.
In the case of a simple pendulum:
  • At the highest point of its swing, the energy is entirely potential.
  • At the lowest point, this energy has transformed into kinetic energy.
By equating these energies, we can derive formulas such as the maximum speed formula. This principle implies that any loss is through non-conservative actions, like air resistance, which aren't considered in a perfect theoretical model.
potential energy
Potential energy in a simple pendulum is the stored energy due to its position in a gravitational field. At the pendulum's highest swing point, it has maximum potential energy, attributed to its height above the lowest point.
The potential energy \(U\) at maximum displacement is calculated using the height \(h\) derived from geometry:
  • \(h = L(1 - \cos \theta_0)\)
By substituting in the potential energy formula:
  • \(U = mgh = mgL(1 - \cos \theta_0)\)
The potential energy depends on the mass of the pendulum bob, the gravitational constant \(g\), and the effective height of the swing, which equates to the energy stored at this point.
kinetic energy
Kinetic energy is the energy of motion and is maximized in a pendulum at its lowest point. This is where the pendulum has transferred all its initial potential energy into motion.
The formula for kinetic energy \(K\) in a pendulum is:
  • \(K = \frac{1}{2}mv_{\max}^2\)
At the lowest point of the swing, the entire potential energy has converted into kinetic energy, providing maximum speed. Thus:
  • \(mgL(1 - \cos \theta_0) = \frac{1}{2}mv_{\max}^2\)
This equation illustrates how the energy changes from potential at the top to kinetic at the bottom, allowing us to solve for the maximum velocity \(v_{\max}\) the pendulum achieves.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A tsunami of wavelength 250 \(\mathrm{km}\) and velocity 750 \(\mathrm{km} / \mathrm{h}\) travels across the Pacific Ocean. As it approaches Hawaii, people observe an unusual decrease of sea level in the harbors. Approximately how much time do they have to run to safety? (In the absence of knowledge and warning, people have died during tsunamis, some of them attracted to the shore to see stranded fishes and boats.)

The ripples in a certain groove 10.8 \(\mathrm{cm}\) from the center of a 33 -rpm phonograph record have a wavelength of 1.70 \(\mathrm{mm}\) . What will be the frequency of the sound emitted?

(II) When you slosh the water back and forth in a tub at just the right frequency, the water alternately rises and falls at each end, remaining relatively calm at the center. Suppose the frequency to produce such a standing wave in a 65 -cm-wide tub is 0.85 \(\mathrm{Hz}\) . What is the speed of the water wave?

(II) A vertical spring with spring stiffness constant 305 \(\mathrm{N} / \mathrm{m}\) vibrates with an amplitude of 28.0 \(\mathrm{cm}\) when 0.260 \(\mathrm{kg}\) hangs from it. The mass passes through the equilibrium point \((y=0)\) with positive velocity at \(t=0 .\) (a) What equation describes this motion as a function of time? (b) At what times will the spring have its maximum and minimum extensions?

(I) \((a)\) AM radio signals have frequencies between 550 \(\mathrm{kHz}\) and 1600 \(\mathrm{kHz}\) (kilohertz) and travel with a speed of \(3.00 \times 10^{8} \mathrm{m} / \mathrm{s} .\) What are the wavelengths of these signals? \((b)\) On FM, the frequencies range from 88.0 \(\mathrm{MHz}\) to 108 \(\mathrm{MHz}\) (megahertz) and travel at the same speed; what are their wavelengths?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.