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Use Gauss' and Stokes' theorems (Appendix A) to convert Maxwell's differential equations for vacuum, \((82.1)\) to \((8.2 .4)\), to their integral form $$ \begin{aligned} &\oint_{S} \mathbf{E} \cdot d \mathbf{S}=\frac{q}{\epsilon_{0}} \\ &\oint_{L} \mathbf{E} \cdot d \mathbf{l}=-\frac{d \Phi_{m}}{d t} \\ &\oint_{S} \mathbf{B} \cdot d \mathbf{S}=0 \\ &\oint_{L} \mathbf{B} \cdot d \mathbf{l}=\mu_{0} I+\mu_{0} \frac{d \Phi_{*}}{d t} \end{aligned} $$ † See Sec. \(5.4\) and Prob. 8.2.4. where the closed surface \(S\) contains the net charge \(q\) and the closed line (loop) \(L\) is linked by the net current \(I\), the magnetic flux \(\Phi_{m}=\int \mathbf{B} \cdot d \mathbf{S}\), and the electric flux \(\Phi_{e}=\epsilon_{0} \int \mathbf{E} \cdot d \mathbf{S}\). Note: The corresponding equations for a general electromagnetic medium are developed in Prob. \(8.6 .1 .\)

Short Answer

Expert verified
1. Apply Gauss' theorem to convert \(\nabla \cdot \mathbf{E}\) into its integral form. $$\oint_{S} \mathbf{E} \cdot d \mathbf{S}=\frac{q}{\epsilon_{0}}$$ 2. Apply Stokes' theorem to convert \(\nabla \times \mathbf{E}\) into its integral form. $$\oint_{L} \mathbf{E} \cdot d \mathbf{l}=-\frac{d \Phi_{m}}{d t}$$ 3. Apply Gauss' theorem to convert \(\nabla \cdot \mathbf{B}\) into its integral form. $$\oint_{S} \mathbf{B} \cdot d \mathbf{S}=0$$ 4. Apply Stokes' theorem to convert \(\nabla \times \mathbf{B}\) into its integral form. $$\oint_{L} \mathbf{B} \cdot d \mathbf{l}=\mu_{0} I+\mu_{0} \frac{d \Phi_{*}}{d t}$$

Step by step solution

01

Applying Gauss' theorem to \(\nabla \cdot \mathbf{E}\)

According to Gauss' theorem: $$\oint_{S}\mathbf{E} \cdot d\mathbf{S} = \int_{V}\nabla \cdot \mathbf{E}\, dV$$ From \((82.1)\), we have \(\nabla \cdot \mathbf{E} = \frac{\rho}{\epsilon_{0}}\). Substituting in the above equation and taking \(\frac{1}{\epsilon_{0}}\) constant out of the integral, we get: $$\oint_{S}\mathbf{E} \cdot d\mathbf{S} = \frac{1}{\epsilon_{0}}\int_{V}\rho\, dV$$ Since \(\int_V \rho \, dV\) is the total charge enclosed by the surface \(S\), we can rewrite as: $$\oint_{S} \mathbf{E} \cdot d \mathbf{S}=\frac{q}{\epsilon_{0}}$$
02

Applying Stokes' theorem to \(\nabla \times \mathbf{E}\)

According to Stokes' theorem: $$\oint_{L}\mathbf{E} \cdot d\mathbf{l} = \iint_{S}\nabla \times \mathbf{E} \cdot d\mathbf{S}$$ From \((82.2)\), we have \(\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}}{\partial t}\). Substituting in the above equation and taking the time derivative inside the integral, we get: $$\oint_{L} \mathbf{E} \cdot d \mathbf{l}=-\iint_{S} \frac{\partial \mathbf{B}}{\partial t} \cdot d \mathbf{S}$$ Using the definition of magnetic flux \(\Phi_{m} = \int \mathbf{B} \cdot d\mathbf{S}\), we get: $$\oint_{L} \mathbf{E} \cdot d \mathbf{l}=-\frac{d \Phi_{m}}{d t}$$
03

Applying Gauss' theorem to \(\nabla \cdot \mathbf{B}\)

According to Gauss' theorem: $$\oint_{S}\mathbf{B} \cdot d\mathbf{S} = \int_{V}\nabla \cdot \mathbf{B}\, dV$$ From \((82.3)\), we have \(\nabla \cdot \mathbf{B} = 0\). Subtituting in the above equation, we get: $$\oint_{S} \mathbf{B} \cdot d \mathbf{S}=0$$
04

Applying Stokes' theorem to \(\nabla \times \mathbf{B}\)

According to Stokes' theorem: $$\oint_{L}\mathbf{B} \cdot d\mathbf{l} = \iint_{S}\nabla \times \mathbf{B} \cdot d\mathbf{S}$$ From \((82.4)\), we have \(\nabla \times \mathbf{B} = \mu_{0} \mathbf{J} + \mu_{0} \epsilon_{0} \frac{\partial \mathbf{E}}{\partial t}\). Substituting in the above equation, we get: $$\oint_{L} \mathbf{B} \cdot d \mathbf{l}=\iint_{S} \left(\mu_{0} \mathbf{J} + \mu_{0} \epsilon_{0} \frac{\partial \mathbf{E}}{\partial t}\right) \cdot d \mathbf{S}$$ Using \(\iint_S \mathbf{J} \cdot d \mathbf{S} = \mu_0I\), where \(I\) is the net current through the loop \(L\), and the definition of electric flux \(\Phi_{*} = \epsilon_{0} \int \mathbf{E} \cdot d\mathbf{S}\), we get: $$\oint_{L} \mathbf{B} \cdot d \mathbf{l}=\mu_{0} I+\mu_{0} \frac{d \Phi_{*}}{d t}$$ Thus, we have successfully converted the four differential equations into their integral form.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gauss' theorem
Gauss' theorem, also known as Gauss' law, is a fundamental principle in electromagnetism that relates the electric field \textbf{E} around a closed surface to the charge enclosed by that surface. Mathematically, the theorem can be expressed as \[ \oint_{S} \mathbf{E} \cdot d \mathbf{S} = \frac{q}{\epsilon_{0}} \], where \(\oint_{S}\) denotes the closed surface integral over surface \(S\), \mathbf{E}\ is the electric field, \(d\mathbf{S}\) is a vector representing an infinitesimal area on surface \(S\) pointing outward, \(q\) is the total electric charge enclosed within the surface, and \(\epsilon_{0}\) is the permittivity of free space.

Gauss' theorem is one of the four Maxwell's equations, which are the foundation of classical electrodynamics, optics, and electric circuits. The theorem has a deep physical significance: it implies that electric field lines originate from positive charges and terminate on negative charges, and the net flux through a closed surface depends only on the charge enclosed, not on the specifics of how the field is configured outside the surface.
Stokes' theorem
Stokes' theorem bridges the gap between the concepts of circulation and curl. It is used to relate the surface integral of the curl of a vector field to the line integral of the vector field around the boundary of the surface. In the context of electromagnetism, Stokes' theorem can be applied to the magnetic vector field \textbf{B}, enabling us to connect the electric field \textbf{E} around a closed loop to the rate of change of the magnetic flux through the enclosed surface. Stokes' theorem is expressed as \[ \oint_{L} \mathbf{B} \cdot d \mathbf{l} = \iint_{S} abla \times \mathbf{B} \cdot d \mathbf{S} \], where \(\oint_{L}\) is the line integral around closed loop \(L\), and the right-hand side involves the surface integral over the surface bounded by \(L\).

Understanding Stokes' theorem is essential when studying electromagnetic waves and the dynamic relationships in electromagnetism, such as how varying magnetic fields give rise to electric fields, and vice versa. This theorem plays a crucial role in the integral form of Maxwell's equations, providing a deeper look into the symmetry of nature's laws.
Electromagnetic waves
Electromagnetic waves are a form of energy transfer through space at the speed of light, consisting of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of propagation. Maxwell's equations predict the existence of these waves and describe how electric and magnetic fields are generated and altered by each other and by charges and currents.

Electromagnetic waves are fundamental to our understanding of the electromagnetic spectrum, including radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves are capable of traveling through a vacuum, unlike sound waves, which require a medium. The ability of electromagnetic waves to carry energy and information across vast distances is what enables technologies such as television, radio communication, and cellular phones. In the integral form of Maxwell's equations, these waves are described by time-varying fields, showing the interrelation between changing electric and magnetic fields in space.
Integral form of Maxwell's equations
The integral form of Maxwell's equations provides a powerful framework for understanding how electric and magnetic fields behave under various circumstances. These equations summarize the generation and interrelation of these fields and serve as the basis for classical electrodynamics. They appear in two forms: differential and integral. The integral form, derived from the differential form using theorems like Gauss' and Stokes', is often more practical when solving problems with symmetric geometries because it deals with the net effects over an entire region.

The integral form of Maxwell's equations consists of the following four equations:
  • Gauss' law for electricity, which relates the electric field to the charge distribution.
  • Gauss' law for magnetism, which states that there are no magnetic monopoles.
  • Faraday's law of induction, which describes how a changing magnetic field creates an electric field.
  • Ampère's law with Maxwell's addition, which relates the magnetic field to the electric current and the change in the electric field.
These equations are pivotal for predicting how fields interact with materials, how they propagate through space, and how they give rise to phenomena such as electromagnetic waves.

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Most popular questions from this chapter

(a) From \((8.7 .10)\) and \((8.7 .13)\), show that the guided ave impedance \(\left(E_{x}{ }^{2}+E_{y}{ }^{2}\right)^{1 / 2} /\) \(\left(H_{x}{ }^{2}+H_{z}{ }^{2}\right)^{1 / 2}\) is \(Z_{\mathrm{TE}}=\frac{Z_{0}}{\left[1-\left(\lambda_{0} / \lambda_{e}\right)^{2}\right]^{1 / 2}} \quad\) TE modes \(Z_{\text {T? }}=Z_{0}\left[1-\left(\lambda_{0} / \lambda_{c}\right)^{2}\right]^{1 / 2} \quad\) TM modes, where \(Z_{0}\) is the unbounded wave impedance \((8.3 .10)\) or, more generally, \((8.3 .12) .(b)\) For the TE o dominant mode in rectangular waveguide, show that the peak potential difference between opposite points in the cross section is $$ V_{0}=\left[\int_{0}^{b} E_{y}\left(x=\frac{1}{2} a\right) d y\right]_{p e s k}=b E_{0} $$ and that the peak axial current flowing in the top wall is $$ I_{0} \equiv\left[\frac{1}{\mu_{0}} \int_{0}^{a} B_{x}(y=b) d x\right]_{\text {pak }}=\frac{2 a E_{0}}{\pi Z_{\mathrm{TE}}} $$ Since the result of Prob. 8.7.10b can be written $$ \bar{P}=\frac{a b}{4} \frac{E_{0}{ }^{2}}{Z_{\mathrm{TB}}} $$ we can define three other (mode-dependent) waveguide impedances as follows: $$ \begin{aligned} &Z_{V, I}=\frac{V_{0}}{I_{0}}=\frac{\pi}{2}\left(\frac{b}{a} Z_{\mathrm{TE}}\right) \\ &Z_{P, V}=\frac{V_{0}{ }^{2}}{2 P}=2\left(\frac{b}{a} Z_{\mathrm{TE}}\right) \\\ &Z_{P, I}=\frac{2 \bar{P}}{I_{0}{ }^{2}}=\frac{\pi^{2}}{8}\left(\frac{b}{a} Z_{\mathrm{TE}}\right) \end{aligned} $$ which differ by small numerical factors. Only systems supporting a TEM mode (e.g., Sec. 8.1), have a unique impedance.

Postulate wave fields of the form $$ \begin{aligned} &\mathbf{E}=\mathbf{i} f(z-c t)+\mathbf{j} g(z-c t)+\mathbf{k} h(z-c t) \\ &\mathbf{B}=\mathbf{i} q(z-c t)+\mathbf{j} r(z-c t)+\mathbf{k} s(z-c t) \end{aligned} $$ where \(f, g, h, q, r, s\) are arbitrary (nonsinusoidal) functions, independent of \(x\) and \(y .\) Show that such waves are a solution of the wave equations \((8.2 .8)\) and \((82.9)\) and that Maxwell's equations (8.2.1) to \((8.2 .4)\) require $$ \begin{aligned} &h=s=0 \\ &f=c r \\ &g=-c q \end{aligned} $$ that is, that only two of the six functions are really arbitrary.

Consider an ionized gas of uniform electron density \(n\). Regard the positive ions as a smeared-out continuous fluid which renders the gas macroscopically neutral and through which the electrons can move without friction. Now assume that, by some external means, each electron is shifted in the \(x\) direction by the displacement \(\xi=\xi(x)\), a function of its initial, unperturbed location \(x\). (a) Show from Gauss' law (8.2.1) that the resulting electric field is \(E_{x}=n e \xi / e_{0} .(b)\) Show that each electron experiences a linear (Hooke's law) restoring force such that when the external forces are removed, it oscillates about the equilibrium position \(\xi=0\) with simple harmonic motion at the angular frequency $$ \omega_{p}=\left(\frac{n e^{2}}{\epsilon_{0} m}\right)^{1 / 2} $$ which is known as the electron plasma frequency. † For fuller discussion, see J. A. Ratcliffe, "The Magneto-ionic Theory and Its Applications to the Ionosphere," Cambridge University Press, New York, 1959 ; M. A. Heald and C. B. Wharton, "Plasma Diagnostics with Microwaves," John Wiley \& Sons Inc., New York, 1965; I. P. Shkarofsky, T. W. Johnson, and M. P. Bachynski, "Particle Kinetics of Plasma," Addison-Wesley Publishing Company, Reading, Mass., \(1965 .\)

Use the results of Prob. 8.2.3 to compute the Poynting vector for a coaxial transmission line. Integrate it over the annular area between conductors and show that the power carried down the line by the wave is $$ P=i^{2} Z_{0}=\frac{v^{2}}{Z_{0}}, $$ where \(i\) and \(v\) are the instantaneous current and voltage and \(Z_{0}\) is the characteristic impedance \((8.1 .9)\), that is, just the result one would expect from elementary circuit analysis.

Consider total reflection at an interface between two nonmagnetic media, with relative refractive index \(n=c_{1} / c_{2}<1\). For angles of incidence \(\theta_{1}\) exceeding the critical angle of (8.6.42), Snell's law gives $$ \sin \theta_{2}=\frac{\sin \theta_{1}}{n}>1, $$ which implies that \(\theta_{2}\) is a complex angle with an imaginary cosine, $$ \cos \theta_{2}=\left(1-\sin ^{2} \theta_{2}\right)^{1 / 2}=j\left(\frac{\sin ^{2} \theta_{1}}{n^{2}}-1\right)^{1 / 2} $$ Substitute these relations in the case I reflection coefficient (8.6.28) to establish $$ R_{\mathbf{E} \perp}=e^{-i 2 \phi_{\perp}}, $$ where $$ \tan \phi_{\perp}=\frac{\left(\sin ^{2} \theta_{1}-n^{2}\right)^{1 / x}}{\cos \theta_{1}} $$ That is, the magnitude of the reflection coefficient is unity, but the phase of the reflected wave depends upon angle. Similarly show for case II from (8.6.36), that \(R_{\text {III }}=e^{-\text {jod with }}\) $$ \tan \phi \|=\frac{\left(\sin ^{2} \theta_{1}-n^{2}\right)^{1 / 2}}{n^{2} \cos \theta_{1}}=\frac{1}{n^{2}} \tan \phi_{\perp} . $$ Note that the two phase shifts are different, so that in general the state of polarization of an incident wave is altered.

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