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The units of momentum can be expressed as (A) \(\mathrm{N} \cdot \mathrm{S}\) (B) \(\sqrt{\mathrm{kg} \cdot \mathrm{J}}\) (C) \(\sqrt{\mathrm{kg} \cdot \mathrm{W} \cdot \mathrm{s}}\) (D) all of the above (E) none of the above

Short Answer

Expert verified
(A) \(\mathrm{N} \cdot \mathrm{S}\) (B) \(\sqrt{\mathrm{kg} \cdot \mathrm{J}}\) (C) \(\sqrt{\mathrm{kg} \cdot \mathrm{W} \cdot \mathrm{s}}\) (D) \(\text{kg} \cdot \text{m}^2\) (E) None of the above Answer: (E) None of the above

Step by step solution

01

Write the formula for momentum

The formula for momentum, denoted as "p", is given by: \(p = m \cdot v\) where "m" is mass (in kg) and "v" is velocity (in m/s).
02

Determine the units for momentum

Now, we will determine the unit for momentum by multiplying the units of mass (kg) and velocity (m/s): Units for momentum = \((\text{kg}) \cdot (\text{m/s})\) Units for momentum = \((\text{kg} \cdot \text{m})/\text{s}\)
03

Compare the units for momentum with given options

Now that we have determined the units for momentum, we will compare it with the given options in the exercise: (A) \(\mathrm{N} \cdot \mathrm{S}\) = \(\text{N} \cdot \text{s}\) (B) \(\sqrt{\mathrm{kg} \cdot \mathrm{J}}\) = \(\sqrt{\text{kg} \cdot \text{J}}\) (C) \(\sqrt{\mathrm{kg} \cdot \mathrm{W} \cdot \mathrm{s}}\) = \(\sqrt{\text{kg} \cdot \text{W} \cdot \text{s}}\) From these options, we can see that none of the given options match the actual unit for momentum, which is \((\text{kg} \cdot \text{m})/\text{s}\).
04

Final answer

Since none of the given options match the actual unit for momentum, the correct answer is: (E) none of the above

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Units of Measurement in Momentum
In physics, units of measurement are essential for comprehensively describing quantities like force, energy, and, in this case, momentum. Momentum is depicted by the formula: \[ p = m \cdot v \] where \( m \) stands for mass measured in kilograms (kg), and \( v \) denotes velocity measured in meters per second (m/s). The units for momentum, therefore, become \((\text{kg} \cdot \text{m/s})\).
  • Mass: measured in kilograms (kg)
  • Velocity: measured in meters per second (m/s)
  • Momentum: measured in (kg \(\cdot\) m/s)
This mathematical relationship helps physicists determine how an object's momentum will affect its motion. In the context of our previous exercise question, none of the provided unit options align with the standard unit for momentum, \((\text{kg} \cdot \text{m/s})\). Understanding this helps avoid confusion when solving physics problems.
Physics Problem Solving Essentials
Solving physics problems can seem complex, but breaking them down into simple steps can make them manageable. Let’s dive into some strategies: - **Identify Known Variables:** Start by writing down what you already know about the problem. This includes formulas, units, and given data. - **Choose the Right Formula:** Use formulas relevant to the problem. For momentum problems, the key formula is \( p = m \cdot v \). - **Plug in Values:** Substitute the given values into the formula. Make sure the units are compatible. - **Calculate & Check:** Perform the mathematical calculations carefully. Afterwards, check if your solution is plausible based on the physical context. Using these steps, physics becomes less about solving abstract equations and more about interpreting the physical world around us.
Preparing for the SAT Physics Exam
Preparing for the SAT Physics exam involves mastering various concepts and practicing problem-solving. Here are some essential tips to excel: - **Understand Core Concepts:** Focus on understanding the fundamental concepts such as momentum, force, and energy before jumping into practice problems. - **Practice Regularly:** Solve as many practice questions as possible. Familiarize yourself with common question types and formats. - **Time Management:** The SAT is a timed test, so practice under timed conditions. This helps in managing the time spent per question during the actual exam. - **Review Mistakes:** Learn from mistakes in practice tests. Understanding why an error happened is crucial for improvement. - **Use SAT-Specific 91Ó°ÊÓ:** Utilize SAT preparation books and online resources. They provide SAT-specific tips and practice questions. By following these strategies, you can effectively prepare for the SAT Physics exam and increase your confidence in handling problems like those involving momentum.

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Most popular questions from this chapter

A block of mass \(5 \mathrm{~kg}\) hangs by a string from the ceiling. cant copy image. The force the ceiling exerts on the string is most nearly: (A) \(1 \mathrm{~N}\), acting up (B) \(5 \mathrm{~N}\), acting down (C) \(50 \mathrm{~N}\), acting down (D) \(50 \mathrm{~N}\), acting up (E) \(100 \mathrm{~N}\), acting up

You find yourself stranded on planet Alpha, which is half as dense as Earth but which has a radius three times that of Earth's. What is your weight on Alpha compared to your weight on Earth? (A) \(2 / 3\) (B) The same (C) \(3 / 2\) (D) 3 (E) 6

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An object of mass \(m_1\) and an object of mass \(m_2\) are initially attached to each other and at rest. At the instant \(t=0\) they are pushed apart by a spring that has been compressed between them. After \(t=0\), \(v_1=2 \mathrm{~m} / \mathrm{s}\) and \(v_2=-3 \mathrm{~m} / \mathrm{s}\). One can conclude that (A) \(m_1 / m_2=3 / 2\) (B) \(m_1=2 \mathrm{~kg}\) and \(m_2=3 \mathrm{~kg}\) (C) \(m_1=3 \mathrm{~kg}\) and \(m_2=2 \mathrm{~kg}\) (D) \(m_1 / m_2=2 / 3\) (E) \(m_1 / m_2=-3 / 2\)

Your dog Astro is nosing a dinner plate of mass \(M\) across a frozen pond at a constant velocity \(v\). There is a coefficient of friction \(\mu\) between the ice and the block. What is the rate of work Astro does on the plate? (A) \(\mu M v^2\) (B) \(\mu M g v\) (C) \(M g v^2 / \mu\) (D) \(\mu M v^2 / g\) (E) \(\mu M g / v\)

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