/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Which of the following statement... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 12: Problem 9

Which of the following statements about the photon is true? i. The photon has a wavelength; ii. The photon has a mass; iii. The photon can undergo interference; iv. The photon is charged; \(\mathrm{v}\). The photon has a momentum. (A) i only (B) i, ii only (C) i, iii, v only (D) i, ii, iii, iv only (E) iii, v only

Short Answer

Expert verified
(A) The photon has a wavelength only. (B) The photon has a wavelength and a mass only. (C) The photon has a wavelength, can undergo interference, and has momentum only. (D) The photon has a wavelength, mass, can undergo interference, and is charged only. (E) The photon can undergo interference and has momentum only. Answer: (C) The photon has a wavelength, can undergo interference, and has momentum only.

Step by step solution

01

Understand the properties of photons

Photons are fundamental particles of light that have characteristic properties. They have no mass, are uncharged, and move at the speed of light. They also have a wavelength and can undergo phenomena such as interference and diffraction.
02

Analyze the given statements

We will analyze each of the given statements and determine if they are true or false based on the properties of photons: i. The photon has a wavelength - Yes, photons have wavelengths associated with their energies and frequencies. ii. The photon has a mass - No, photons do not have mass, as they are massless particles. iii. The photon can undergo interference - Yes, photons can undergo interference, as demonstrated in experiments like the double-slit experiment. iv. The photon is charged - No, photons are not charged. They are electrically neutral. v. The photon has a momentum - Yes, photons have momentum, which can be calculated by \(p = \frac{h}{\lambda}\), where \(p\) is the momentum, \(h\) is the Planck's constant, and \(\lambda\) is the wavelength of the photon.
03

Identify the correct choices based on the statements' validity

Now that we had analyzed the accuracy of each statement, let's review the choices and identify the correct combination of true statements: (A) i only - This option is missing necessary true statements, so it's incorrect. (B) i, ii only - This option incorrectly includes the statement about the photon having mass. (C) i, iii, v only - This option correctly includes all three true statements, making it the correct choice. (D) i, ii, iii, iv only - This option incorrectly includes the statements about the photon having mass and being charged. (E) iii, v only - This option is missing the true statement about the photon having a wavelength. Based on our analysis, the correct answer is (C) i, iii, v only.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave-Particle Duality
The concept of wave-particle duality is a fundamental principle in quantum mechanics. This principle suggests that every particle, like photons, exhibit both wave and particle characteristics. For photons, which are the particles of light, this duality explains a variety of phenomena:
  • Wave nature: Photons exhibit the properties of waves, including wavelength and frequency. This manifests in behaviors like interference and diffraction. For example, in the famous double-slit experiment, light creates an interference pattern typical of waves.
  • Particle nature: Despite their wave-like behavior, photons are also individual particles. They carry energy and momentum, adhering to the given values in their interactions.
The dual nature of photons is fascinating as it challenges our classical understanding of physics. This principle is central to explaining behaviors that light exhibits in various scenarios.
Electromagnetic Radiation
Photons are the fundamental units of electromagnetic radiation, which encompasses a broad spectrum of energy. This spectrum includes visible light, radio waves, X-rays, and more. Understanding electromagnetic radiation involves the following key points:
  • Uncharged particles: Photons carry no electric charge, which allows them to travel unimpeded by electromagnetic fields. This attribute ensures that light can move through diverse mediums, from air to space.
  • Speed of light: Photons travel at the speed of light in a vacuum, approximately 299,792 kilometers per second (about 186,282 miles per second). This speed is constant regardless of the observer's frame of reference.
  • Energy and frequency: The energy of a photon is directly related to its frequency. High-frequency photons, such as gamma rays, carry more energy compared to low-frequency ones like radio waves.
Photoelectric and electromagnetic properties of photons, such as emission and absorption, are critical to technologies like solar panels and radios.
Momentum of Light
Despite being massless, photons possess momentum! This concept might be counterintuitive because we often associate momentum with objects having mass. However, in quantum mechanics, momentum is not solely reliant on mass. For photons, momentum is defined by their energy and wavelength:
  • Calculation: Photon momentum is calculated using the formula: \[ p = \frac{h}{\lambda} \]where \( p \) represents momentum, \( h \) is Planck's constant, and \( \lambda \) is the wavelength. This formula shows that longer wavelengths yield lower momentum.
  • Applications: The momentum of light has practical applications. For instance, it is exploited in optical tweezers, which use light to move microscopic particles, and in spacecraft propulsion using solar sails.
Understanding photon momentum enhances our ability to harness light in innovative ways, impacting scientific research and technological advancements.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A boron atom bombarded by a slow neutron can undergo the following reaction: $$ \mathrm{n}+{ }^{10} \mathrm{~B} \rightarrow{ }^4 \mathrm{He}+{ }^7 \mathrm{Li}+\gamma . $$ The reaction products receive \(2.31 \mathrm{MeV}\) of kinetic energy. This kinetic energy should be computed as (A) equal to the kinetic energy of the neutron. (B) the total energy of the neutron. (C) the energy deficit of the reaction. (D) the energy deficit of the reaction minus the photon energy. (E) the energy deficit of the reaction minus the kinetic energy of the neutron.

Two isotopes of an element ordinarily (A) have the same atomic number. (B) have the same atomic mass. (C) contain the same number of nucleons in the nucleus. (D) contain the same number of electrons. (E) (A) and (D)

A hypothetical atom has energy levels at \(-12 \mathrm{eV},-8 \mathrm{eV},-3 \mathrm{eV},-1 \mathrm{eV}\). a) Draw the energy levels of the atom. Label the levels with the principal quantum number. b) An electron with velocity \(v=1.326 \times 10^6 \mathrm{~m} / \mathrm{s}\) is incident on the atom. What is the de Broglie wavelength of the electron? Ignore any relativistic effects. c) Can the electron excite an electron in any of the energy levels to a higher state? If so, which are the two levels involved? d) An electron decays from the \(-3 \mathrm{eV}\) state to the \(-8 \mathrm{eV}\) state and emits a photon. What is its wavelength? What part of the electromagnetic spectrum is it in?

Of the following scientists, who did not contribute to the development of quantum mechanics? (A) Niels Bohr (B) Max Planck (C) Albert Einstein (D) James Clerk Maxwell (E) John Nicholson

An atomic nucleus is induced to break into two pieces, during which process energy is released. One can say with certainty that (A) the original atomic mass was greater than that of iron. (B) the fragments will each have an atomic mass less than that of iron. (C) the masses of the fragments will add up to be less than the mass of the original nucleus. (D) (A) and (C) (E) None of the above
See all solutions

Recommended explanations on Physics Textbooks

Waves Physics

Read Explanation

Space Physics

Read Explanation

Circular Motion and Gravitation

Read Explanation

Quantum Physics

Read Explanation

Measurements

Read Explanation

Work Energy and Power

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.