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A virus has a mass of about \(10^{-18} \mathrm{~kg}\). The de Broglie wavelength of a virus being blown in the wind at \(10 \mathrm{~m} / \mathrm{s}\) is nearest to (A) one billionth the size of a hydrogen atom. (B) one millionth the size of a hydrogen atom. (C) one thousandth the size of a hydrogen atom. (D) the size of a hydrogen atom. (E) one thousand times the size of a hydrogen atom.

Short Answer

Expert verified
(A) one thousandth (B) one millionth (C) one billionth Answer: (B) one millionth

Step by step solution

01

Know the de Broglie wavelength formula

The de Broglie wavelength formula is given by \(\lambda = \frac{h}{p}\), where \(\lambda\) is the wavelength, \(h\) is the Planck's constant, and \(p\) is the momentum of the particle. For an object with mass \(m\) and velocity \(v\), its momentum \(p = m \times v\). Therefore, we have \(\lambda = \frac{h}{mv}\).
02

Plug in the given data into the formula

We are given the mass \(m = 10^{-18} \mathrm{~kg}\), and the velocity \(v = 10 \mathrm{~m}/\mathrm{s}\). The Planck's constant is \(h = 6.626 \times 10^{-34} \mathrm{~Js}\). Now, substitute these values into the formula: \(\lambda = \frac{6.626 \times 10^{-34} \mathrm{~Js}}{(10^{-18} \mathrm{~kg})(10 \mathrm{~m} / \mathrm{s})}\).
03

Calculate the de Broglie wavelength

Perform the calculation from the previous step to find the de Broglie wavelength of the virus: \(\lambda = \frac{6.626 \times 10^{-34}}{10^{-17}} = 6.626 \times 10^{-17} \mathrm{~m}\).
04

Compare the de Broglie wavelength to the size of a hydrogen atom

The size of a hydrogen atom is typically around \(1 \mathrm{~Ã…} = 10^{-10}\mathrm{~m}\). To compare the de Broglie wavelength of the virus to the size of a hydrogen atom, divide the de Broglie wavelength by the size of a hydrogen atom, and then compare the result to the given options: \(\frac{6.626 \times 10^{-17} \mathrm{~m}}{10^{-10} \mathrm{~m}} = 6.626 \times 10^{-7}\). This value is closest to one millionth (Option B), which means that the de Broglie wavelength of the virus is about one millionth the size of a hydrogen atom. Therefore, the answer is (B).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Planck's Constant
Planck's constant, denoted by the symbol \( h \), is a fundamental constant in physics that plays a crucial role in the field of quantum mechanics. It is named after Max Planck, who first introduced it in the early 20th century. This constant helps bridge the wave and particle nature of matter and radiation.
\( h \) has a value of approximately \( 6.626 \times 10^{-34} \) Joule-seconds, and it is used to calculate the energy of a photon from its frequency through the equation \( E = h u \), where \( E \) is the energy and \( u \) is the frequency.

In the context of de Broglie wavelength, Planck's constant is a part of the equation \( \lambda = \frac{h}{p} \), which allows us to connect a particle's wave-like properties with its momentum. Using \( h \), we can determine the wavelength of particles such as electrons or even larger objects like viruses based on their momentum.
Momentum
Momentum is a measure of the motion of an object and is a fundamental concept in physics. For an object with mass \( m \) and velocity \( v \), momentum \( p \) is calculated as \( p = m \times v \). This concept is essential for understanding how objects move and interact.

In the de Broglie wavelength formula, momentum helps us find the wavelength that a particle would exhibit if it had wave-like properties. Since momentum is dependent on both the mass and velocity of an object, it affects how large or small the de Broglie wavelength will be.
  • If an object is heavier or moving faster, it has greater momentum, thus shorter de Broglie wavelength.
  • If an object is lighter or moving slower, it has less momentum, leading to a longer de Broglie wavelength.
This connection between momentum and wavelength helps deepen our understanding of how matter behaves on a quantum level.
Hydrogen Atom Size
The size of a hydrogen atom is often used as a reference point in many physics problems due to its simplicity and well-defined structure in atomic physics. A hydrogen atom is composed of a single electron orbiting a single proton.
The typical size of a hydrogen atom, represented by its atomic radius, is about \( 1 \) angstrom, which is \( 10^{-10} \) meters. This atomic size is essential for comparing the scale of different particles or wavelengths.
In the context of the de Broglie wavelength problem, knowing the size of a hydrogen atom allows us to determine how the wave nature of particles, like a virus, compares to atomic scales. Calculating the de Broglie wavelength of such particles and comparing it with the hydrogen atom's size helps in understanding how tangible or significant these wave properties are in relation to atomic dimensions.

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Most popular questions from this chapter

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