/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 The diameters of the main rotor ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The diameters of the main rotor and tail rotor of a singleengine helicopter are \(7.60 \mathrm{~m}\) and \(1.02 \mathrm{~m}\), respectively. The respective rotational speeds are 450 rev/min and 4138 rev/min. Calculate the speeds of the tips of both rotors. Compare these speeds with the speed of sound, \(343 \mathrm{~m} / \mathrm{s}\)

Short Answer

Expert verified
The speed of the tip of the main rotor is \(179.07 m/s\) and the speed of the tip of the tail rotor is \(221.0972 m/s\). Both speeds are significantly slower than the speed of sound which is \(343 m/s\).

Step by step solution

01

Calculate the Circumference

Convert the diameters of the rotors to radii by dividing by 2. For the main rotor, the radius is \(7.6m/2 = 3.8m\), and for the tail rotor, the radius is \(1.02m/2 = 0.51m\). Then, calculate the circumference of each rotor. The formula for circumference is \(2\pi r\). For the main rotor, the circumference is \(2*\pi*3.8m = 23.876m\), and for the tail rotor, the circumference is \(2*\pi*0.51m = 3.204m\).
02

Calculate the Speed of the Rotor Tips

Now, calculate the distance each rotor tip travels in one minute. Since the rotational speed is given in revolutions per minute, simply multiply the circumference by the rotational speed. For the main rotor, the speed is \(23.876m*450rev/min = 10744.2m/min\), and for the tail rotor, the speed is \(3.204m*4138rev/min = 13265.832m/min\). To convert this to metres per second, divide by 60. The main rotor tip speed is \(10744.2m/min/60 = 179.07m/s\), and the tail rotor tip speed is \(13265.832m/min/60 = 221.0972m/s\).
03

Compare with the Speed of Sound

Finally, compare these speeds with the speed of sound, which is \(343m/s\). The main rotor tip speed is \(179.07m/s\), and the tail rotor tip speed is \(221.0972m/s\). Therefore, both are significantly slower than the speed of sound.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed Calculation
In physics, understanding how to calculate speed involves grasping how far an object travels over a given period. When we talk about circular motion, such as that of a helicopter rotor, this becomes a bit unique. The key here is to identify the right components:
  • The diameter or radius of the rotor
  • The rotational speed (in revolutions per minute)
First, convert the diameter to a radius. The radius is half of the diameter. Using this, you can calculate the rotor's circumference, which is essential in determining distance. The formula for circumference is: \[ \text{Circumference} = 2\pi \times \text{radius}\]Once you have the circumference, calculate how far the rotor tip travels in one minute by multiplying the circumference by the rotational speed. This gives you a speed in terms of distance per minute. Convert this speed to meters per second by dividing by 60, because there are 60 seconds in a minute.
Helicopter Rotor Dynamics
Helicopter rotor dynamics is a fascinating study area within aerodynamics that explains how these spinning blades lift and maneuver the vehicle. A helicopter's main rotor provides the essential lift that allows the helicopter to take off and stay in the air. The rotor is the equivalent of an airplane's wings.
  • The main rotor is larger and rotates slower compared to the tail rotor.
  • The tail rotor is generally smaller and rotates faster; it counteracts the torque produced by the main rotor, stabilizing the helicopter.
In our specific problem, the main rotor and tail rotor work at different speeds, highlighting the delicate balance needed for flight stability. Observing these details, mechanics and pilots ensure that the helicopter operates smoothly and safely. Understanding rotor dynamics helps us not only grasp how helicopters can hover but also how they can smoothly transition between different flight modes.
Comparison with Speed of Sound
The speed of sound is a critical benchmark often used in aviation to evaluate the performance of aerospace designs and mechanisms. The speed of sound reaches approximately 343 m/s in air at sea level. When comparing the rotor tips' speeds to the speed of sound, we are essentially seeing how close these components are to crossing into the transonic range—where shockwaves and other complicating factors can arise.
  • The main rotor's tip speed is about 179.07 m/s.
  • The tail rotor's tip speed is approximately 221.10 m/s.
Both speeds fall well below the speed of sound, ensuring that standard helicopter operations remain in a subsonic region. Staying within these limits is crucial because operating rotors at or beyond the speed of sound can lead to significant aerodynamic challenges and heightened mechanical stress. These dynamics are avoided in typical helicopter designs, promoting smooth and reliable performance.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

ecp The pilot of an airplane executes a constant-speed loop-the-loop maneuver in a vertical circle as in Figure 7.15b. The speed of the airplane is \(2.00 \times 10^{2} \mathrm{~m} / \mathrm{s}\), andthe radius of the circle is \(3.20 \times 10^{3} \mathrm{~m}\). (a) What is the pilot's apparent weight at the lowest point of the circle if his true weight is \(712 \mathrm{~N}\) ? (b) What is his apparent weight at the highest point of the circle? (c) Describe how the pilot could experience weightlessness if both the radius and the speed can be varied. Note: His apparent weight is equal to the magnitude of the force exerted by the seat on his body. Under what conditions does this occur? (d) What speed would have resulted in the pilot experiencing weightlessness at the top of the loop?

8\. One method of pitching a softball is called the "windmill" delivery method, in which the pitcher's arm rotates through approximately \(360^{\circ}\) in a vertical plane before the 198 -gram ball is released at the lowest point of the circular motion. An experienced pitcher can throw a ball with a speed of \(98.0 \mathrm{mi} / \mathrm{h}\). Assume the angular acceleration is uniform throughout the pitching motion and take the distance between the softball and the shoulder joint to be \(74.2 \mathrm{~cm}\). (a) Determine the angular speed of the arm in rev/s at the instant of release. (b) Find the value of the angular acceleration in \(\mathrm{rev} / \mathrm{s}^{2}\) and the radial and tangential acceleration of the ball just before it is released. (c) Determine the force exerted on the ball by the pitcher's hand (both radial and tangential components) just before it is released.

A stuntman whose mass is \(70 \mathrm{~kg}\) swings from the end of a \(4.0\) -m-long rope along the arc of a vertical circle. Assuming he starts from rest when the rope is horizontal, find the tensions in the rope that are required to make him follow his circular path (a) at the beginning of his motion, (b) at a height of \(1.5 \mathrm{~m}\) above the bottom of the circular arc, and (c) at the bottom of the arc.

The tires on a new compact car have a diameter of \(2.0 \mathrm{ft}\) and are warranted for 60000 miles. (a) Determine the angle (in radians) through which one of these tires will rotate during the warranty period. (b) How many revolutions of the tire are equivalent to your answer in part (a)?

ecp A pail of water is rotated in a vertical circle of radius \(1.00 \mathrm{~m}\). (a) What two external forces act on the water in the pail? (b) Which of the two forces is most important in causing the water to move in a circle? (c) What is the pail's minimum speed at the top of the circle if no water is to spill out? (d) If the pail with the speed found in part (c) were to suddenly disappear at the top of the circle, describe the subsequent motion of the water. Would it differ from the motion of a projectile?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.