/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 A digital audio compact disc car... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A digital audio compact disc carries data along a continuous spiral track from the inner circumference of the disc to the outside edge. Each bit occupies \(0.6 \mu \mathrm{m}\) of the track. A CD player turns the disc to carry the track counterclockwise above a lens at a constant speed of \(1.30 \mathrm{~m} / \mathrm{s}\). Find the required angular speed (a) at the beginning of the recording, where the spiral has a radius of \(2.30 \mathrm{~cm}\), and (b) at the end of the recording, where the spiral has a radius of \(5.80 \mathrm{~cm} .\) (c) A full-length recording lasts for \(74 \mathrm{~min}, 33 \mathrm{~s}\). Find the average angular acceleration of the disc. (d) Assuming the acceleration is constant, find the total angular displacement of the disc as it plays. (e) Find the total length of the track.

Short Answer

Expert verified
The required angular speed at the beginning of the recording is \(56.52 rad/s\), and at the end of the recording is \(22.41 rad/s\). The average angular acceleration of the disc is \(-0.0076 rad/s²\). The total angular displacement of the disk as it plays is \(135210 rad\) and the total length of the track is \(81.12 m\)

Step by step solution

01

Calculation of Angular Speed

The following formula is used to calculate the angular speed (ω): \(ω = v/r\)\n\nwhere \(v\) represents the linear speed and \(r\) represents the radius.\n\na) At the beginning of the recording, the radius is \(0.023m\). So the angular speed will be: \(ω = 1.30/0.023 = 56.52 rad/s\) \n\nb) At the end of the recording, when the radius is \(0.058m\), the angular speed will be: \(ω = 1.30/0.058 = 22.41 rad/s\)
02

Calculation of Average Angular Acceleration

The average angular acceleration can be calculated using the formula: \(αav = (ωf - ωi) / t\)\n\nwhere \(ωf\) is the final angular speed, \(ωi\) is the initial angular speed and \(t\) is the time duration. Here \(ωf = 22.41 rad/s\), \(ωi = 56.52 rad/s\) and \(t = 4473s\).\n\nAverage angular acceleration will be: \(αav = (22.41 - 56.52) / 4473 = -0.0076 rad/s²\)
03

Calculation of Total Angular Displacement

The total angular displacement is calculated using the formula \(θ= ωi.t + 0.5.αav.t²\). On substituting the known values, the angular displacement \(θ = 56.52*4473 + 0.5*-0.0076*4473² = 135210 rad\)
04

Calculation of Total Length of Track

The total length of the track can be calculated by the formula: \(L = b.θ\), where \(b\) is the space per bit and \(θ\) the total angular displacement. The space per bit for CDs is \(0.6μm\), we convert it into meters which are \(0.6*10^-6 m\). Hence the total length of the track is calculated to be \(L = 135210*(0.6*10^-6) = 81.12 m\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Speed
When discussing angular motion, a key concept is angular speed, often denoted by \( \omega \). This refers to how fast an object rotates or revolves relative to a fixed point. Angular speed is typically measured in radians per second (rad/s). Unlike linear speed, which measures distance traveled over time, angular speed measures how quickly an angle changes over time.
To find angular speed, the formula \( \omega = \frac{v}{r} \) is used, where \( v \) is the linear speed (in meters per second) and \( r \) is the radius of the circular path (in meters).This formula illustrates the relationship between linear and angular speed: an increase in radius with a constant linear speed results in a decrease in angular speed. It's a fundamental concept when working with rotating objects like CDs, turbines, or wheel gears.
Angular Acceleration
Angular acceleration is another important concept when studying angular motion. It refersto how quickly the angular speed of an object changes with time. Angular acceleration is usually denoted by \( \alpha \) and is measured in radians per second squared (rad/s²).
The formula for average angular acceleration is \( \alpha_{av} = \frac{\omega_f - \omega_i}{t} \),where \( \omega_f \) is the final angular speed, \( \omega_i \) the initial angular speed, and \( t \)is the time period over which the change occurs. This concept is crucial for understanding how a rotating disc, such as a CD, gradually decreases or increases its speed, often due to frictional forces or the need to maintain a certain data transmission speed.
In practical scenarios, knowing the angular acceleration helps to predict the future movement of rotating bodies and makes it possible to design systems that can compensate for these changes.
Angular Displacement
Angular displacement is a pivotal concept in the realm of rotational motion. It measures the change in the angle as an object moves along a circular path. Unlike linear displacement, which measures how far an object has traveled in a straight line, angular displacement tells us how much rotation has occurred around a center or axis. It's measured in radians.
The formula to calculate the total angular displacement of an object when the angular acceleration is constant is \( \theta = \omega_i \cdot t + 0.5 \cdot \alpha \cdot t^2 \). Here, \( \omega_i \) represents the initial angular speed, \( \alpha \) the angular acceleration, and \( t \) the time duration. This equation is essential in solving problems related to how much a disc or wheel turns over a period, providing insights into movement behaviors duringevents like a CD playing its tracks.
Linear Speed
Linear speed is the rate at which an object moves along a path and is a fundamental aspect of motion analysis. Measured in meters per second (m/s), it represents the distance covered by an object per unit time.
In the context of a rotating disc, such as a CD, linear speed is closely linked to angular speed. While linear speed pertains to straight-line motion, the relationship \( \omega = \frac{v}{r} \)emphasizes its relevance in circular motion as well. It helps us understand how a consistent linear speed is maintained along the disc's spiral track, thereby ensuring smooth and uninterrupted playback.
By manipulating linear speed, we can control the rotational dynamics of materials and objects that need precise timing or alignment of continuously moving parts.
Radius
A fundamental yet often overlooked aspect of circular motion is the radius. The radius, represented by \( r \), is the straight-line distance from the center of a circle to any point on its circumference. In the realm of angular motion, it serves as an essential measure.
The radius directly impacts both angular speed and linear speed: an increase in radius necessitates a decrease in angular speed for a given linear speed, according to the formula \( \omega = \frac{v}{r} \). This principle is critical in the scenario of a CD player, where the spiral track's radius changes from beginning to end.
Understanding radius allows us to comprehensively interpret and solve problems involving circular paths, ensuring the application of accurate physical principles and designing efficient systems in real-world applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a popular amusement park ride, a rotating cylinder of radius \(3.00 \mathrm{~m}\) is set in rotation at an angular speed of \(5.00 \mathrm{rad} / \mathrm{s}\), as in Figure \(\mathrm{P} 7.75 .\) The floor then drops away, leaving the riders suspended against the wall in a vertical position. What minimum coefficient of friction between a rider's clothing and the wall is needed to keep the rider from slipping? (Hint: Recall that the magnitude of the maximum force of static friction is equal to \(\mu n\), where \(n\) is the normal force-in this case, the force causing the centripetal acceleration.)

Part of a roller-coaster ride involves coasting down an incline and entering a loop \(8.00 \mathrm{~m}\) in diameter. For safety considerations, the roller coaster's speed at the top of the loop must be such that the force of the seat on a rider is equal in magnitude to the rider's weight. From what height above the bottom of the loop must the roller coaster descend to satisfy this requirement?

A race car starts from rest on a circular track of radius \(400 \mathrm{~m}\). The car's speed increases at the constant rate of \(0.500 \mathrm{~m} / \mathrm{s}^{2}\). At the point where the magnitudes of the centripetal and tangential accelerations are equal, determine (a) the speed of the race car, (b) the distance traveled, and (c) the elapsed time.

ecp The pilot of an airplane executes a constant-speed loop-the-loop maneuver in a vertical circle as in Figure 7.15b. The speed of the airplane is \(2.00 \times 10^{2} \mathrm{~m} / \mathrm{s}\), andthe radius of the circle is \(3.20 \times 10^{3} \mathrm{~m}\). (a) What is the pilot's apparent weight at the lowest point of the circle if his true weight is \(712 \mathrm{~N}\) ? (b) What is his apparent weight at the highest point of the circle? (c) Describe how the pilot could experience weightlessness if both the radius and the speed can be varied. Note: His apparent weight is equal to the magnitude of the force exerted by the seat on his body. Under what conditions does this occur? (d) What speed would have resulted in the pilot experiencing weightlessness at the top of the loop?

ecp A coin rests \(15.0 \mathrm{~cm}\) from the center of a turntable. The coefficient of static friction between the coin and turntable surface is \(0.350\). The turntable starts from rest at \(t=0\) and rotates with a constant angular acceleration of \(0.730 \mathrm{rad} / \mathrm{s}^{2}\). (z (a) Once the turntable starts to rotate, what force causes the centripetal acceleration when the coin is stationary relative to the turntable? Under what condition does the coin begin to move relative to the turntable? (b) After what period of time will the coin start to slip on the turntable?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.