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A billiard ball moving at \(5.00 \mathrm{~m} / \mathrm{s}\) strikes a stationary ball of the same mass. After the collision, the first ball moves at \(4.33 \mathrm{~m} / \mathrm{s}\) at an angle of \(30^{\circ}\) with respect to the original line of motion. (a) Find the velocity (magnitude and direction) of the second ball after collision. (b) Was the collision inelastic or elastic?

Short Answer

Expert verified
The velocity of the second ball after the collision is \(4.33 \, \mathrm{m/s}\) at an angle of \(30^\circ\). The collision was inelastic

Step by step solution

01

Apply Conservation of Momentum

The total momentum before the collision is equal to the total momentum after the collision. Express the momentum in vector form considering the given angles. Before collision the momentum \(P_{initial}\) is simply the momentum of the first ball as the second one is stationary. \(P_{initial} = m u_1\). After the collision, both balls will have some momentum. Express these as vectors.
02

Solve for Velocity

From the first step, set up the following equation and solve it for the velocity of the second ball after collision. \(P_{initial} = P_{final}\) or \(m u_1 = m v_1 cos(30) + m v_2 cos(θ)\) and \(0 = m v_1 sin(30) - m v_2 sin(θ)\), after simplifying we get \(v_2 = v_1 ∗ cos(30) / cos(θ)\) and \(sin(θ) = v_1 * sin(30) / v_2\). Substituting the value of \(v_2\) from first equation to second equation we get \(sin(θ) = sin(30)\), so the \(θ= 30°\).
03

Finding type of Collision

Check if the collision was elastic or inelastic by comparing the kinetic energy before and after the collision. An elastic collision conserves kinetic energy, while an inelastic collision doesn't. Compare \(K_{initial} = 0.5 * m * u_1^2\) and \(K_{final} = 0.5 * m * v_1^2 + 0.5 * m * v_2^2\). After calculating, you'll see that the initial and final kinetic energies are not equal, therefore the collision is inelastic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
In physics, the law of conservation of momentum states that the total momentum of a closed system of objects (which does not interact with external forces) remains constant over time, irrespective of the internal forces acting between the objects. This principle is a cornerstone in collision problems.

Let's say you're watching a game of billiards and observe a collision between two balls. Here's how the conservation of momentum comes into play: If a moving billiard ball strikes a stationary one, the total momentum before the collision, which is solely due to the moving ball, will equal the total momentum after the collision, which is now shared between the two balls.

In mathematical terms, if the initial momentum is represented by \( P_{initial} = m u_1 \) where \( m \) is the mass of a ball and \( u_1 \) is the velocity of the moving ball, and the final momentum is the vector sum of the momenta of both balls after the collision, we have the equation \( P_{initial} = P_{final} \). This is the basis for solving collision problems in physics, just as it was used to solve for the velocity of the second ball in the provided exercise.
Inelastic and Elastic Collisions
Collisions are categorized as either elastic or inelastic, based on whether they conserve kinetic energy. An elastic collision is one where both momentum and kinetic energy are conserved. In these collisions, objects bounce off each other without losing energy to deformation or heat.

An inelastic collision, however, is one where the kinetic energy is not conserved due to energy being converted into other forms, like sound, heat, or deformation. Momentum is still conserved in inelastic collisions, but the objects may stick together or change shape.

To determine the type of collision in our exercise, we compared the kinetic energies before and after the collision. Since the kinetic energy was not the same, the collision was inelastic. This is a critical concept because it leads to understanding why and how objects behave after they collide. Energy analyses in collisions reveal much about the nature of the interactions between objects.
Kinematics in Two Dimensions
Kinematics is the study of objects in motion. When motion involves more than a single dimension, we deal with kinematics in two dimensions. Billiard balls traveling on a table is a perfect example.

In two-dimensional kinematics, we need to consider both the horizontal and vertical components of motion. For instance, when ball one in our exercise struck ball two, we not only cared about how fast they were moving but also the directions they were moving in after the impact. We used trigonometry to resolve the velocities into x (horizontal) and y (vertical) components and to find both the magnitude and the direction of the velocity for each ball.

This approach is immensely helpful, for example, when predicting the landing point of a projectile or analyzing the path of a satellite in orbit. By mastering kinematics in two dimensions, students can understand a wide array of physical phenomena that occur in everyday life, from the flight of a soccer ball to the motion of a car skidding around a curve.

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Most popular questions from this chapter

An unstable nucleus of mass \(1.7 \times 10^{-26} \mathrm{~kg}\), initially at rest at the origin of a coordinate system, disintegrates into three particles. One particle, having a mass of \(m_{1}=5.0 \times 10^{-27} \mathrm{~kg}\), moves in the positive \(y\) -direction with speed \(v_{1}=6.0 \times 10^{6} \mathrm{~m} / \mathrm{s}\). Another particle, of mass \(m_{2}=8.4 \times 10^{-27} \mathrm{~kg}\), moves in the positive \(x\) -direction with speed \(v_{2}=4.0 \times 10^{6} \mathrm{~m} / \mathrm{s}\). Find the magnitude and direction of the velocity of the third particle.

[8 In research in cardiology and exercise physiology, it is often important to know the mass of blood pumped by a person's heart in one stroke. This information can be obtained by means of a ballistocardiograph. The instrument works as follows: The subject lies on a horizontal pallet floating on a film of air. Friction on the pallet is negligible. Initially, the momentum of the system is zero. When the heart beats, it expels a mass \(m\) of blood into the aorta with speed \(v\), and the body and platform move in the opposite direction with speed \(V\). The speed of the blood can be determined independently (for example, by observing an ultrasound Doppler shift). Assume that the blood's speed is \(50.0 \mathrm{~cm} / \mathrm{s}\) in one typical trial. The mass of the subject plus the pallet is \(54.0 \mathrm{~kg}\). The pallet moves \(6.00 \times 10^{-5} \mathrm{~m}\) in \(0.160 \mathrm{~s}\) after one heartbeat. Calculate the mass of blood that leaves the heart. Assume that the mass of blood is negligible compared with the total mass of the person. This simplified example illustrates the principle of ballistocardiography, but in practice a more sophisticated model of heart function is used.

A billiard ball rolling across a table at \(1.50 \mathrm{~m} / \mathrm{s}\) makes a head-on elastic collision with an identical ball. Find the speed of each ball after the collision (a) when the second ball is initially at rest, (b) when the second ball is moving toward the first at a speed of \(1.00 \mathrm{~m} / \mathrm{s}\), and (c) when the second ball is moving away from the first at a speed of \(1.00 \mathrm{~m} / \mathrm{s}\)

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