/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 A pitcher throws a \(0.15\) -kg ... [FREE SOLUTION] | 91Ó°ÊÓ

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A pitcher throws a \(0.15\) -kg baseball so that it crosses home plate horizontally with a speed of \(20 \mathrm{~m} / \mathrm{s}\). The ball is hit straight back at the pitcher with a final speed of \(22 \mathrm{~m} / \mathrm{s}\). (a) What is the impulse delivered to the ball? (b) Find the average force exerted by the bat on the ball if the two are in contact for \(2.0 \times 10^{-3} \mathrm{~s}\).

Short Answer

Expert verified
The impulse delivered to the ball is \(-6.3 kg*m/s\), and the average force exerted by the bat on the ball is \(-3150 N\).

Step by step solution

01

Calculate the initial and final momentum

The momentum of an object is given by the product of its mass (m) and velocity (v). So, calculate the initial momentum (\(p_{initial}\)) and the final momentum (\(p_{final}\)) of the ball. The initial velocity is given as \(20 m/s\) (just before the ball is hit by the bat) and the final velocity is \(22 m/s\) (just after the ball is hit by the bat). The mass of the ball is given as \(0.15 kg\). Thus, \(p_{initial} = m * v_{initial} = 0.15 kg * 20 m/s = 3 kg*m/s\) and \(p_{final} = m * v_{final} = 0.15 kg * -22 m/s = -3.3 kg*m/s\). Note that the final velocity is considered negative because the direction of the velocity changes after the hit, assuming the initial direction to be positive.
02

Calculate the impulse delivered to the ball

Impulse is defined as the change in momentum of an object. It is obtained by subtracting the initial momentum from the final momentum. So, Impulse = \(p_{final} - p_{initial} = -3.3 kg*m/s - 3 kg*m/s = -6.3 kg*m/s\). The negative sign indicates that the impulse is in the opposite direction to the initial direction of motion.
03

Find the average force exerted by the bat

The average force exerted over an interval of time is equal to the total impulse divided by the total time. The time interval given in the problem is \(2.0 x 10^{-3} s\). Thus, Average Force = Impulse / Time = \(-6.3 kg*m/s / 2.0 x 10^{-3} s = -3150 N\). Again, the negative sign indicates that the force is exerted in the opposite direction of the initial motion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Momentum
Momentum refers to the quantity of motion an object has, which depends on its mass and velocity. Think of it as how hard it is to stop a moving object based on its speed and size. The formula for momentum is \[ p = m \cdot v \] where \( p \) represents momentum, \( m \) is mass, and \( v \) is velocity.

In the given exercise, the initial momentum of the baseball is calculated as \( p_{initial} = 0.15 \, \text{kg} \times 20 \, \text{m/s} = 3 \, \text{kg} \cdot \text{m/s} \), and the final momentum is calculated as \( p_{final} = 0.15 \, \text{kg} \times (-22 \, \text{m/s}) = -3.3 \, \text{kg} \cdot \text{m/s} \). Notice the negative sign in the final momentum. It denotes that the ball's direction changed after it was hit, moving back towards the pitcher.

Understanding the direction and magnitude of momentum is crucial, as it helps predict how objects behave when they interact, like how the ball moves when hit.
Average Force and Its Relation to Impulse
When two objects interact, they exert forces on each other, changing each other's momentum. The impulse is the term used to describe this change over time. Impulse is directly related to the force applied to an object within a specific time interval.

The relationship between impulse and average force is captured by the equation: \[ F_{avg} = \frac{\text{Impulse}}{\Delta t} \] where \( F_{avg} \) is the average force, and \( \Delta t \) represents the time over which the force acts.

In the given exercise, the impulse calculated was \(-6.3 \, \text{kg} \cdot \text{m/s} \), and the contact time was \(2.0 \times 10^{-3} \, \text{s}\). This results in an average force of \( F_{avg} = \frac{-6.3 \, \text{kg} \cdot \text{m/s}}{2.0 \times 10^{-3} \, \text{s}} = -3150 \, \text{N} \). The negative sign shows that the average force was exerted in the direction opposite to the ball's initial travel.
Velocity: The Speed and Direction of Motion
Velocity describes how fast an object travels in a certain direction. It is a vector quantity, which means it has both a magnitude (speed) and a direction. This is what differentiates it from speed, which is merely a scalar quantity that does not consider direction.

In the context of the exercise, the baseball's initial velocity was \( 20 \, \text{m/s} \) towards the batter. After being hit, its velocity changed to \( 22 \, \text{m/s} \) in the opposite direction towards the pitcher, marked as negative to indicate this shift.
  • Initial Velocity: Movement towards the batter (+ direction), \( v_{initial} = 20 \, \text{m/s} \)
  • Final Velocity: Movement back towards the pitcher (\(-\) direction), \( v_{final} = -22 \, \text{m/s} \)
This switch in direction highlights the importance of velocity's vector nature.

By carefully analyzing these changes, we gain insight into not just how fast an object is moving, but also understanding the dynamics of its motion in different situations.

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Most popular questions from this chapter

ecp Two ice skaters are holding hands at the center of a frozen pond when an argument ensues. Skater A shoves skater B along a horizontal direction. Identify (a) the horizontal forces acting on \(\mathrm{A}\) and (b) those acting on \(\mathrm{B}\). (c) Which force is greater, the force on \(\mathrm{A}\) or the force on B? (d) Can conservation of momentum be used for the system of \(A\) and \(B\) ? Defend your answer. (e) If \(A\) has a mass of \(0.900\) times that of \(\mathrm{B}\), and \(\mathrm{B}\) begins to move away with a speed of \(2.00 \mathrm{~m} / \mathrm{s}\), find the speed of \(\mathrm{A}\).

ecp A railroad car of mass \(M\) moving at a speed \(v_{1}\) collides and couples with two coupled railroad cars, each of the same mass \(M\) and moving in the same direction at a speed \(v_{2}\). (a) What is the speed \(v_{f}\) of the three coupled cars after the collision in terms of \(v_{1}\) and \(v_{2} ?\) (b) How much kinetic energy is lost in the collision? Answer in terms of \(M, v_{1}\), and \(v_{2}\).

A ball of mass \(0.150 \mathrm{~kg}\) is dropped from rest from a height of \(1.25 \mathrm{~m}\). It rebounds from the floor to reach a height of \(0.960 \mathrm{~m}\). What impulse was given to the ball by the floor?

ecp An astronaut in her space suit has a total mass of \(87.0 \mathrm{~kg}\), including suit and oxygen tank. Her tether line loses its attachment to her spacecraft while she's on a spacewalk. Initially at rest with respect to her spacecraft, she throws her \(12.0\) -kg oxygen tank away from her spacecraft with a speed of \(8.00 \mathrm{~m} / \mathrm{s}\) to propel herself back toward it (Fig. P6.25). (a) Determine the maximum distance she can be from the craft and still return within \(2.00 \mathrm{~min}\) (the amount of time the air in her helmet remains breathable). (b) Explain in terms of Newton's laws of motion why this strategy works.

A baseball player of mass \(84.0 \mathrm{~kg}\) running at \(6.70 \mathrm{~m} / \mathrm{s}\) slides into home plate. (a) What magnitude impulse is delivered to the player by friction? (b) If the slide lasts \(0.750 \mathrm{~s}\), what average friction force is exerted on the player?

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