/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 A light spring with spring const... [FREE SOLUTION] | 91Ó°ÊÓ

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A light spring with spring constant \(1.20 \times 10^{3} \mathrm{~N} / \mathrm{m}\) hangs from an elevated support. From its lower end hangs a second light spring, which has spring constant \(1.80 \times 10^{3} \mathrm{~N} / \mathrm{m}\). A \(1.50-\mathrm{kg}\) object hangs at rest from the lower end of the second spring. (a) Find the total extension distance of the pair of springs. (b) Find the effective spring constant of the pair of springs as a system. We describe these springs as being in series. Hint: Consider the forces on each spring separately.

Short Answer

Expert verified
The total extension distance of the springs when the object hangs at rest from the lower end is found by adding the extension distances of the individual springs, which are calculated from the weight of the object and the spring constants using Hooke's Law. The effective spring constant for the system of springs is calculated by summing the reciprocals of the individual spring constants, and then taking the reciprocal of this sum.

Step by step solution

01

Compute the extensions of individual springs

The object is hanging at rest from the bottom spring, so the force exerted on each spring is equal to the weight of the object. This force can be calculated as \(F = mg\), where \(m\) is the object's mass and \(g\) is the gravitational field strength (around \(9.8 N/kg\) on Earth). Using Hooke's Law, the extension \(x\) of the upper spring is given by the formula \(x_{1} = F / k_{1}\) and, similarly, the extension of the lower spring is given by \(x_{2} = F / k_{2}\).
02

Compute the total extension distance

The total displacement \(x_{\text{total}}\) is the sum of the individual displacements, \(x_{\text{total}} = x_{1} + x_{2}\).
03

Calculate the effective spring constant for the system

The effective spring constant \(k_{\text{total}}\) of the two springs as a system is calculated using the formula \(\frac{1}{k_{\text{total}}} = \frac{1}{k_{1}} + \frac{1}{k_{2}}\). To find \(k_{\text{total}}\), take the reciprocal of the right-hand side of this equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Constant
The spring constant, often denoted by the symbol k, is a measure of a spring's stiffness. In the context of Hooke's Law, which states that the force F needed to extend or compress a spring by some distance x is proportional to that distance, the spring constant serves as the proportionality factor: \[ F = kx \] In the given exercise, there are two springs with respective spring constants of 1.20 x 10^3 N/m and 1.80 x 10^3 N/m.

Understanding how to use the spring constant is crucial in solving problems that involve spring motion. The stiffer the spring, the greater the spring constant, and, conversely, the more the spring will resist deformation for a given force. This resistance to deformation is the key to calculating how much an object attached to the spring will stretch or compress it.

When approaching exercises involving the spring constant, it's essential to remember that the extension or compression x of a spring is inversely proportional to the spring constant; in other words, a spring with a higher k value will extend less under the same applied force than a spring with a lower k value.
Gravitational Field Strength
The gravitational field strength, commonly denoted as g, is defined as the force of gravity acting on an object per unit mass. On Earth's surface, it is approximately 9.8 N/kg. This value means that for every kilogram of mass, the Earth will exert a force of approximately 9.8 newtons.

When you are working with problems involving objects hanging from springs, as in the given textbook exercise, you must calculate the force exerted by the object due to gravity. This force is what stretches the spring, and it can be determined using the formula: \[ F = mg \] where m is the mass of the object hanging from the spring and g is the gravitational field strength.

In scenarios where multiple springs are involved or where objects are moving in a gravitational field, correctly applying the concept of gravitational field strength is fundamental to predicting and explaining physical behavior. For instance, when an object is suspended from a series of springs as in the exercise, the weight of the object, governed by g, is a critical factor in finding out how much each spring extends.
Effective Spring Constant
The effective spring constant, denoted as k_{total}, is a term used when combining multiple springs in a system. Each spring has its spring constant, but when springs are combined—as they are in series or in parallel— the system behaves as if there were a single spring with its effective spring constant.

For springs in series, the effective spring constant can be calculated using the formula: \[ \frac{1}{k_{\text{total}}} = \frac{1}{k_{1}} + \frac{1}{k_{2}} \] To find the effective spring constant for the system, you take the reciprocal of the sum of the reciprocals of each individual spring constant, as shown in Step 3 of the given solution.

This formula for the effective spring constant is vital in understanding how the overall stiffness of the system changes. A key point to note is that for springs in series, the combined effect is to create a system that is less stiff than any individual spring—meaning the effective spring constant is lower than the smallest individual spring constant in the series. The exercise improvement advice is, therefore, to pay special attention to the combination rule for the effective spring constant, as it determines the behavior of the entire system under the influence of a force.

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Most popular questions from this chapter

A \(5.75-\mathrm{kg}\) object is initially moving so that its \(x\) -component of velocity is \(6.00 \mathrm{~m} / \mathrm{s}\) and its \(y\) -component of velocity is \(-2.00 \mathrm{~m} / \mathrm{s}\), (a) What is the kinetic energy of the object at this time? (b) Find the change in kinetic energy of the object if its velocity changes so that its new \(x\) -component is \(8.50 \mathrm{~m} / \mathrm{s}\) and its new \(y\) -component is \(5.00 \mathrm{~m} / \mathrm{s}\).

In a needle biopsy, a narrow strip of tissue is extracted from a patient with a hollow needle. Rather than being pushed by hand, to ensure a clean cut the needle can be fired into the patient's body by a spring. Assume the needle has mass \(5.60 \mathrm{~g}\), the light spring has force constant \(375 \mathrm{~N} / \mathrm{m}\), and the spring is originally compressed \(8.10 \mathrm{~cm}\) to project the needle horizontally without friction. The tip of the needle then moves through \(2.40 \mathrm{~cm}\) of skin and soft tissue, which exerts a resistive force of \(7.60 \mathrm{~N}\) on it. Next, the needle cuts \(3.50 \mathrm{~cm}\) into an organ, which exerts a backward force of \(9.20 \mathrm{~N}\) on it. Find (a) the maximum speed of the needle and (b) the speed at which a flange on the back end of the needle runs into a stop, set to limit the penetration to \(5.90 \mathrm{~cm}\).

A certain rain cloud at an altitude of \(1.75 \mathrm{~km}\) contains \(3.20 \times 10^{7} \mathrm{~kg}\) of water vapor, How long would it take for a \(2.70-\mathrm{kW}\) pump to raise the same amount of water from Earth's surface to the cloud's position?

A projectile of mass \(m\) is fired horizontally with an initial speed of \(v_{0}\) from a height of \(h\) above a flat, desert surface. Neglecting air friction, at the instant before the projectile hits the ground, find the following in terms of \(m, v_{0}, h\), and \(g\); (a) the work done by the force of gravity on the projectile, (b) the change in kinetic energy of the projectile since it was fired, and (c) the final kinetic energy of the projectile. (d) Are any of the answers changed if the initial angle is changed?

An airplane of mass \(1.50 \times 10^{4} \mathrm{~kg}\) is moving at \(60.0 \mathrm{~m} / \mathrm{s}\). The pilot then increases the engine's thrust to \(7.50 \times 10^{4} \mathrm{~N}\). The resistive force exerted by air on the airplane has a magnitude of \(4.00 \times 10^{4} \mathrm{~N}\), (a) Is the work done by the engine on the airplane equal to the change in the airplane's kinetic energy after it travels through some distance through the air? Is mechamical energy conserved? Explain. (b) Find the speed of the airplane after it has traveled \(5.00 \times 10^{2} \mathrm{~m}\). Assume the airplane is in level flight throughout the motion.

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