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A 2.0-m-long pendulum is released from rest when the support string is at an angle of \(25^{\circ}\) with the vertical. What is the speed of the bob at the bottom of the swing?

Short Answer

Expert verified
The speed of the bob at the bottom of the swing is 1.84 m/s.

Step by step solution

01

Define givens

The exercise provides the length of the pendulum (\(L = 2.0 m\)), the angle to the vertical when released (\(\theta = 25^{\circ}\)), and the gravitational constant (\(g = 9.8 m/s^2\)). The goal is to find the speed of the bob at the bottom of the swing. This corresponds to the velocity (\(v\)).
02

Calculate the height

The vertical height \(h\) from which the bob is effectively dropped (which gives it potential energy) can be calculated using the formula \(h = L - L \cos \theta\). Here, \(\theta\) should be converted to radians before calculation to ensure accurate answer: \(\theta_rad = \theta \cdot \left(\frac{\pi}{180}\right)\). Hence, \(h = L - L \cos (25 \cdot \left(\frac{\pi}{180}\right)) = 0.1713 m\).
03

Apply the conservation of energy principle

According to conservation of energy, potential energy is converted to kinetic energy, i.e., \(mgh = \frac{1}{2} m v^2\). Solving for the velocity gives \(v = \sqrt{2gh}\). Substituting \(h = 0.1713 m\) and \(g = 9.8 m/s^2\) gives \(v = \sqrt{2 \cdot 9.8 \cdot 0.1713} = 1.84 m/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
In a pendulum motion, the principle of conservation of energy is crucial. It states that energy cannot be created or destroyed, only transformed from one form to another. For a pendulum, energy shifts between potential and kinetic forms.

Initially, when the pendulum is released, all the energy is stored as gravitational potential energy. As it swings downwards, this potential energy gradually converts to kinetic energy. At the very bottom of the swing, the pendulum bob's speed is highest and all the potential energy has been transformed into kinetic energy.

It's important to note some key points:
  • At the top of its motion, the pendulum has maximum potential energy and zero kinetic energy.
  • At the lowest point of the swing, the potential energy is zero, and all energy is kinetic.
  • The total mechanical energy (potential + kinetic) is constant if we ignore air resistance.
Understanding this principle makes it easier to see why a pendulum behaves the way it does, and it helps us calculate the speed at different points in its swing.
Gravitational Potential Energy
Gravitational potential energy (GPE) is the energy an object possesses due to its position relative to the Earth. In the case of a pendulum, GPE depends on how high the bob is above the lowest point of its swing.

The formula for gravitational potential energy is given by\[PE = mgh\]where:
  • \( m \) is the mass of the pendulum bob.
  • \( g \) is the acceleration due to gravity (approximately \(9.8 m/s^2\)).
  • \( h \) is the height of the bob above the reference point.
In the solution of the problem, height can be determined using the difference in the pendulum's length and its effective vertical displacement \(L - L \cos \theta\).

Calculating the initial gravitational potential energy is essential, as it sets the foundation for knowing how much kinetic energy the bob will have when this energy is fully converted at the bottom of its swing.
Trigonometry in Physics
Trigonometry often plays a significant role in solving physics problems that involve angles and measurements. In the pendulum problem, we use trigonometric functions to determine how much potential energy is available to convert into kinetic energy.

To find the height the pendulum bob is dropped from, we use the cosine of the release angle to determine the vertical displacement:\[h = L - L \cos \theta\]
Converting degrees to radians is a crucial step since trigonometric functions in mathematics are typically computed in radians. The conversion is done using the formula:\[\theta_{rad} = \theta \cdot \left(\frac{\pi}{180}\right)\]
By applying trigonometry, we can better understand how the displacement correlates with potential energy loss or gain at varying points in the pendulum's movement.

This trigonometric application is straightforward but powerful, helping us to solve numerous physics problems involving angles and forces.

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Most popular questions from this chapter

An archer pulls her bowstring back \(0.400 \mathrm{~m}\) by exerting a force that increases uniformly from zero to \(230 \mathrm{~N}\). (a) What is the equivalent spring constant of the bow? (b) How much work does the archer do in pulling the bow?

A child of mass \(m\) starts from rest and slides without friction from a height \(h\) along a curved waterslide (Fig. P5.46). She is launched from a height \(h / 5\) into the pool. (a) Is mechanical energy conserved? Why? (b) Give the gravitational potential energy associated with the child and her kinetic energy in terms of \(m g h\) at the following positions: the top of the waterslide, the launching point, and the point where she lands in the pool. (c) Determinc her initial speed \(v_{0}\) at the launch point in terms of \(g\) and \(h\). (d) Determine her maximum airborne height \(y_{\max }\) in terms of \(h, g\), and the horizontal speed at that height, \(v_{0 x}\) (e) Use the \(x\) -component of the answer to part (c) to climinate \(v_{0}\) from the answer to part (d), giving the height \(y_{\text {emax }}\) in terms of \(g, h\), and the launch angle \(\theta\). (f) Would your answers be the same if the waterslide were not frictionless? Explain.

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