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A 2.0-m-long pendulum is released from rest when the support string is at an angle of \(25^{\circ}\) with the vertical. What is the speed of the bob at the bottom of the swing?

Short Answer

Expert verified
The speed of the bob at the bottom of the swing is 1.84 m/s.

Step by step solution

01

Define givens

The exercise provides the length of the pendulum (\(L = 2.0 m\)), the angle to the vertical when released (\(\theta = 25^{\circ}\)), and the gravitational constant (\(g = 9.8 m/s^2\)). The goal is to find the speed of the bob at the bottom of the swing. This corresponds to the velocity (\(v\)).
02

Calculate the height

The vertical height \(h\) from which the bob is effectively dropped (which gives it potential energy) can be calculated using the formula \(h = L - L \cos \theta\). Here, \(\theta\) should be converted to radians before calculation to ensure accurate answer: \(\theta_rad = \theta \cdot \left(\frac{\pi}{180}\right)\). Hence, \(h = L - L \cos (25 \cdot \left(\frac{\pi}{180}\right)) = 0.1713 m\).
03

Apply the conservation of energy principle

According to conservation of energy, potential energy is converted to kinetic energy, i.e., \(mgh = \frac{1}{2} m v^2\). Solving for the velocity gives \(v = \sqrt{2gh}\). Substituting \(h = 0.1713 m\) and \(g = 9.8 m/s^2\) gives \(v = \sqrt{2 \cdot 9.8 \cdot 0.1713} = 1.84 m/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
In a pendulum motion, the principle of conservation of energy is crucial. It states that energy cannot be created or destroyed, only transformed from one form to another. For a pendulum, energy shifts between potential and kinetic forms.

Initially, when the pendulum is released, all the energy is stored as gravitational potential energy. As it swings downwards, this potential energy gradually converts to kinetic energy. At the very bottom of the swing, the pendulum bob's speed is highest and all the potential energy has been transformed into kinetic energy.

It's important to note some key points:
  • At the top of its motion, the pendulum has maximum potential energy and zero kinetic energy.
  • At the lowest point of the swing, the potential energy is zero, and all energy is kinetic.
  • The total mechanical energy (potential + kinetic) is constant if we ignore air resistance.
Understanding this principle makes it easier to see why a pendulum behaves the way it does, and it helps us calculate the speed at different points in its swing.
Gravitational Potential Energy
Gravitational potential energy (GPE) is the energy an object possesses due to its position relative to the Earth. In the case of a pendulum, GPE depends on how high the bob is above the lowest point of its swing.

The formula for gravitational potential energy is given by\[PE = mgh\]where:
  • \( m \) is the mass of the pendulum bob.
  • \( g \) is the acceleration due to gravity (approximately \(9.8 m/s^2\)).
  • \( h \) is the height of the bob above the reference point.
In the solution of the problem, height can be determined using the difference in the pendulum's length and its effective vertical displacement \(L - L \cos \theta\).

Calculating the initial gravitational potential energy is essential, as it sets the foundation for knowing how much kinetic energy the bob will have when this energy is fully converted at the bottom of its swing.
Trigonometry in Physics
Trigonometry often plays a significant role in solving physics problems that involve angles and measurements. In the pendulum problem, we use trigonometric functions to determine how much potential energy is available to convert into kinetic energy.

To find the height the pendulum bob is dropped from, we use the cosine of the release angle to determine the vertical displacement:\[h = L - L \cos \theta\]
Converting degrees to radians is a crucial step since trigonometric functions in mathematics are typically computed in radians. The conversion is done using the formula:\[\theta_{rad} = \theta \cdot \left(\frac{\pi}{180}\right)\]
By applying trigonometry, we can better understand how the displacement correlates with potential energy loss or gain at varying points in the pendulum's movement.

This trigonometric application is straightforward but powerful, helping us to solve numerous physics problems involving angles and forces.

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Most popular questions from this chapter

A shopper in a supermarket pushes a cart with a force of \(95 \mathrm{~N}\) directed at an angle of \(25^{\circ}\) below the horizontal. The force is just sufficient to overcome various frictional forces, so the cart moves at constant speed. (a) Find the work done by the shopper as she moves down a \(50.0-\mathrm{m}\) length aisle, (b) What is the net work done on the cart? Why? (c) The shopper goes down the next aisle, pushing horizontally and maintaining the same speed as before. If the work done by frictional forces doesn't change, would the shopper's applied force be larger, smaller, or the same? What about the work done on the cart by the shopper?

A \(0.60-\mathrm{kg}\) particle has a speed of \(2,0 \mathrm{~m} / \mathrm{s}\) at point \(A\) and a kinetic energy of \(7.5 \mathrm{~J}\) at point \(\mathrm{B}\). What is (a) its kinetic energy at \(A ?\) (b) Its speed at point \(B\) ? (c) The total work done on the particle as it moves from \(A\) to \(B\) ?

A 2 \(300-\mathrm{kg}\) pile driver is used to drive a steel beam into the ground. The pile driver falls \(7.50 \mathrm{~m}\) before coming into contact with the top of the beam, and it drives the beam \(18.0 \mathrm{~cm}\) farther into the ground as it comes to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.

A \(3.50-\mathrm{kN}\) piano is lifted by three workers at constant speed to an apartment \(25.0 \mathrm{~m}\) above the street using a pulley system fastened to the roof of the building. Each worker is able to deliver \(165 . \mathrm{W}\) of power, and the pulley system is \(75.0 \%\) efficient (so that \(25.0 \%\) of the mechanical energy is lost due to friction in the pulley). Neglecting the mass of the pulley, find the time required to lift the piano from the street to the apartment.

An accelerometer in a control system consists of a \(3.65-\mathrm{g}\) object sliding on a horizontal rail. A low-mass spring is connected between the object and a flange at one end of the rail. Grease on the rail makes static friction negligible, but rapidly damps out vibrations of the sliding object. When subject to a steady acceleration of \(0.500 \mathrm{~g}\), the object must be located \(0.350 \mathrm{~cm}\) from its equilibrium position. Find the force constant required for the spring.

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