/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 The force acting on an object is... [FREE SOLUTION] | 91Ó°ÊÓ

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The force acting on an object is given by \(F_{n}=(8 x-16) \mathrm{N}\), where \(x\) is in meters. (a) Make a plot of this force versus \(x\) from \(x=0\) to \(x=3.00 \mathrm{~m} .\) (b) From your graph, find the net work done by the force as the object moves from \(x=0\) to \(x=3.00 \mathrm{~m}\).

Short Answer

Expert verified
The net work done by the force as the object moves from \(x=0\) to \(x=3.00 m\) can be found by integrating the force equation over this interval. The exact numerical value will be obtained from the result of this integration.

Step by step solution

01

Plotting the Force Function

Start by plotting the graph of the given force function \(F_n=(8x-16) N\), for \(x\) ranging from 0 to 3 m. This can be done using a graphing calculator or an online tool that can graph equations.
02

Calculating the Work Done

The work done by a variable force when an object moves from one point to another is given by the area under the force-displacement graph from the initial to the final position. In this case, it is obtained by finding the area under the curve from \(x=0\) to \(x=3.00 m\). This can be calculated by integrating the force function over the given range. The integral of \(F_n\) from 0 to 3 gives the work done by the force as the object moves from \(x=0\) to \(x=3.00 m\). Therefore, evaluate \(\int_0^3 (8x-16) dx\).
03

Final Evaluation

The result of the integration is the work done on the object as it moves from \(x=0\) to \(x=3.00 m\). This will be the numerical value obtained from the integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variable Force
Variable force is a concept in mechanics where the force acting on an object changes with the position, time, or certain conditions. Unlike constant force, which remains the same irrespective of the object's displacement, variable force is dynamic and dependent on specific variables. In the original exercise, the expression for force is given as \( F_n = (8x - 16) \ \text{N} \). Here, the force changes with the displacement \( x \), which is in meters.
In practical terms, this means:
  • The force is not uniform over the distance from 0 to 3 meters.
  • It increases or decreases depending on the position \( x \).
  • Must be described using functions that detail how force changes over space or time.
Understanding variable force is crucial because it allows us to describe situations more realistically, such as the force of gravity varying with altitude or the force of a spring changing as it compresses or stretches. Recognizing variable forces is the first step in solving physics problems involving non-uniform force distributions.
Force-Displacement Graph
A force-displacement graph is a crucial tool in understanding how forces work over a certain distance. This graph plots force on the y-axis and displacement on the x-axis. In the exercise, you were asked to plot the function \( F_n = (8x - 16) \). This graphical representation provides a visual understanding of the relationship between force and displacement.
The benefits of using a force-displacement graph include:
  • Identifying patterns in how force varies with distance.
  • Visualizing changes in force, which are not immediately apparent from an equation.
  • Determining areas under the curve, which correspond to the work done.
To draw this graph, consider the starting and ending points corresponding to the range from 0 to 3 meters. Not only does it show the magnitude of force at any point but also presents a clear picture of how work is distributed over that range. The slope of the line in this graph directly tells us about the nature of the force in play, and the steeper the slope, the greater the change of force with displacement.
Integration in Physics
Integration is a mathematical technique essential in physics for dealing with variable forces. Specifically, it allows us to calculate the total work done by these forces when they act over a distance. In the context of the exercise, you perform integration to find the work done from 0 to 3 meters. The force function given is \( F_n = (8x - 16) \), and to find the work done, we integrate this function over the limits of displacement.
When integrating, you're effectively summing up an infinite number of infinitesimally small contributions to total work:
  • The integral of the force function \( \int_0^3 (8x - 16) \, dx \) gives the work done.
  • Integration turns a variable force equation into a scalar quantity, representing total work.
  • It's a tool that transforms the continuous function of force into a single value that reflects physical effort over a range.
The result from this particular integral isn't just a number—it's a physical insight into the cumulative effect of the force across a distance. Integrals translate dynamic force equations into tangible outcomes, such as energy expended or gained.

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Most popular questions from this chapter

An archer pulls her bowstring back \(0.400 \mathrm{~m}\) by exerting a force that increases uniformly from zero to \(230 \mathrm{~N}\). (a) What is the equivalent spring constant of the bow? (b) How much work does the archer do in pulling the bow?

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(a) A child slides down a water slide at an amusement park from an initial height \(h\). The slide can be considered frictionless because of the water flowing down it. Can the equation for conservation of mechanical energy be used on the child? (b) Is the mass of the child a factor in determining his speed at the bottom of the slide? (c) The child drops straight down rather than following the curved ramp of the slide. In which case will he be traveling faster at ground level? (d) If friction is present, how would the conservation-of-energy equation be modified? (c) Find the maximum speed of the child when the slide is frictionless if the initial height of the slide is \(12.0 \mathrm{~m}\).

An accelerometer in a control system consists of a \(3.65-\mathrm{g}\) object sliding on a horizontal rail. A low-mass spring is connected between the object and a flange at one end of the rail. Grease on the rail makes static friction negligible, but rapidly damps out vibrations of the sliding object. When subject to a steady acceleration of \(0.500 \mathrm{~g}\), the object must be located \(0.350 \mathrm{~cm}\) from its equilibrium position. Find the force constant required for the spring.

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