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A boat moves through the water with two forces acting on it. One is a \(2000-\mathrm{N}\) forward push by the water on the propeller, and the other is a \(1800-\mathrm{N}\) resistive force due to the water around the bow. (a) What is the acceleration of the \(1000-\mathrm{kg}\) boat? (b) If it starts from rest, how far will the boat move in \(10.0 \mathrm{~s}\) ? (c) What will its velocity be at the end of that time?

Short Answer

Expert verified
The acceleration of the boat is \(0.2 m/s²\), it will move \(10 m\) in \(10 s\), and its velocity at the end of that time will be \(2 m/s\).

Step by step solution

01

Determine the Net Force

Newton's second law can be written as \( F_{net} = m \cdot a \). Here, the net force \( F_{net} \) is the forward force minus the resistive force. Hence, \( F_{net} = 2000 - 1800 = 200 N \).
02

Calculate Acceleration

Substitute \( F_{net} = 200 N \) and \( m = 1000 kg \) into the equation and solve for \( a \): \( a = F_{net}/m = 200N / 1000kg = 0.2 m/s² \).
03

Calculate Displacement

For finding displacement, use the kinematic equation: \( s = u \cdot t + 0.5 \cdot a \cdot t² \). With \( u = 0 m/s \) (starts from rest), \( a = 0.2 m/s² \) (from the above step) and \( t = 10.0 s \): we have \( s = 0 + 0.5 \cdot 0.2 m/s² \cdot (10.0s)² = 0 + 0.5 \cdot 0.2 m/s² \cdot 100 s² = 10 m \).
04

Calculate Final Velocity

One can calculate the final velocity using the equation \( v = u + a \cdot t \). The initial velocity \( u \) is 0 m/s, the acceleration \( a \) is 0.2 m/s², and the time \( t \) is 10.0 s. Hence, \( v = 0 m/s + 0.2 m/s² \cdot 10 s = 2 m/s \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Net Force Calculation
Understanding how to calculate net force is central to applying Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting upon it and inversely proportional to its mass.

When calculating net force, the direction of each force must be considered. Forces in the same direction are added together, while forces in opposite directions are subtracted from one another to determine the overall force influencing the object's motion. For instance, in the case of the boat moving through water, the forward push by the water on the propeller is a positive force, while the resistive force due to water around the bow is a negative force. The net force can thus be calculated by subtracting the resistive force from the forward force:
\[ F_{net} = Forward\thinspace Force - Resistive\thinspace Force = 2000N - 1800N = 200N \] The net force of 200 N is then used to determine the acceleration of the boat.
Kinematic Equations
The kinematic equations are a set of four equations that describe the motion of objects in terms of displacement (\( s \)), initial velocity (\( u \)), final velocity (\( v \)), acceleration (\( a \)), and time (\( t \)). These equations do not take into account the forces that cause the motion and assume constant acceleration throughout the motion.

These equations are especially useful for problems involving motion with constant acceleration, such as our example with the boat. For instance, the equation \[ s = u \thinspace t + 0.5 \thinspace a \thinspace t^2 \] is used to find the boat's displacement. In each kinematic equation, it is essential to correctly plug in the known values and to keep in mind that directions are significant—velocity and acceleration can be positive or negative based on their defined direction in a problem.
Acceleration
Acceleration is the rate at which an object changes its velocity. It is a vector quantity, which means it has both magnitude and direction.

To calculate an object's acceleration, you divide the net force acting on the object by its mass: \[ a = \frac{F_{net}}{m} \] For our boat example, an acceleration of \( 0.2 m/s^2 \) is found by applying the net force of 200 N to the boat's mass of 1000 kg. Understand that acceleration can be a change in speed (getting faster or slower), a change in direction, or both.
Displacement and Velocity
Displacement is the vector quantity that refers to an object's overall change in position. It's not the same as distance, which is scalar and does not account for direction. Velocity, on the other hand, is the speed of an object in a particular direction.

In the context of our boat, knowing both its velocity and displacement after 10 seconds allows us to gain a full picture of its state of motion. The velocity calculated from the final step \( v = u + a \thinspace t \) gives us the speed and direction at a particular instance, while the displacement represents the overall change in position of the boat after a given period, determined using the formula: \[ s = 0.5 \thinspace a \thinspace t^2 \] Both displacement and velocity are crucial in understanding an object's motion, providing information about 'how far' and 'how fast' it has moved.

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Most popular questions from this chapter

A hockey puck struck by a hockey stick is given an initial speed \(v_{0}\) in the positive \(x\) -direction. The coefficient of kinetic friction between the ice and the puck is \(\mu_{k^{\prime}}\) (a) Obtain an expression for the acceleration of the puck. (b) Use the result of part (a) to obtain an expression for the distance \(d\) the puck slides. The answer should be in terms of the variables \(v_{0}, \mu\), and \(g\) only.

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A \(5.0-\mathrm{kg}\) bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is \(3.0 \mathrm{~m} / \mathrm{s}^{2}\), find the force exerted by the rope on the bucket.

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