/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 A roller coaster moves 200 ft ho... [FREE SOLUTION] | 91Ó°ÊÓ

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A roller coaster moves 200 ft horizontally and then rises \(135 \mathrm{ft}\) at an angle of \(30.0^{\circ}\) above the horizontal. Next, it travels \(135 \mathrm{ft}\) at an angle of \(40.0^{\circ}\) below the horizontal. Use graphical techniques to find the roller coaster's displacement from its starting point to the end of this movement.

Short Answer

Expert verified
The displacement of the roller coaster from its starting point to the end of the movement is approximately equal to D in both magnitude and direction.

Step by step solution

01

Plotting the Vectors

First, interpret the motion of the roller coaster as a sum of three vectors. Vector A is the initial horizontal movement of 200 ft. Vector B is the upward motion which forms an angle of 30.0° above the horizontal. Vector C is the downward motion which forms an angle of 40° below the horizontal. Draw these vectors using an appropriate scale, with the tail of each next vector starting from the head of the preceding vector.
02

Computing the Components

Solve for the x and y components of each vectors using sines and cosines. For vector B, Bx = 135 cos(30), By = 135 sin(30). For vector C, Cx = 135 cos(-40), Cy = 135 sin(-40). The x and y components of vector A are simply Ax = 200, Ay = 0.
03

Summing Vectors

Find the resultant vector D by adding the corresponding x and y components from the three vectors. Dx = Ax + Bx + Cx, Dy = Ay + By + Cy. Calculate the magnitude of D using the Pythagorean theorem, D = sqrt(Dx^2 + Dy^2). Calculate the direction of D by finding the angle θ = tan^(-1)(Dy/Dx).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement
In physics, displacement refers to the overall change in position of an object. It's a vector quantity, which means it has both magnitude and direction. Displacement tells you how far out of place an object has moved, regardless of the path it took to get there.
In the roller coaster problem, the goal is to find the coaster's displacement from its starting point to its final position.

This is accomplished by looking at the problem as a vector addition scenario, combining different movements into a single resultant vector. The resultant vector shows the shortest path from the starting position to the end position — effectively capturing the complete displacement as a vector.
Unlike the mere path covered (distance), displacement focuses only on the initial and final points, summarizing the motion in a direct line.
Trigonometric Functions
To solve problems involving angles and distances, trigonometric functions like sine, cosine, and tangent are invaluable. These functions help break down vectors into horizontal (x) and vertical (y) components, which simplifies complex movements into easier parts to handle.
In the vector addition task of the roller coaster, trigonometric functions help us determine the influence of Vector B and Vector C's angled paths.
  • For the upward motion (Vector B), use sine to find the vertical component: \( By = 135 \sin(30^{\circ}) \). This equals the vertical rise of the roller coaster.
  • To determine the horizontal component of Vector B, use cosine: \( Bx = 135 \cos(30^{\circ}) \).
  • Similarly, for the movement angled downward (Vector C), apply cosine and sine with \(-40^{\circ}\) to find horizontal \((Cx)\) and vertical components \((Cy)\), considering the negative angle depicts downward motion.
With these calculated components, you can easily combine vectors using basic addition rules.
Graphical Techniques
Graphical techniques in vector addition involve illustrating vectors to visually find the result of operations like addition. These methods use diagrams to help understand how vectors interact and combine.
For this exercise, plotting vectors on a graph allows you to see the journey of the roller coaster plotted out.

Start by drawing Vector A horizontally, representing the 200 ft distance. From the end of Vector A, draw Vector B at a 30-degree angle from the horizontal, depicting the movement upward. Finally, from the end of Vector B, draw Vector C angled 40 degrees downward from the horizontal.
By arranging vectors in this tail-to-head fashion, you create a clear path. The resultant vector, from start to finish, appears when you connect the starting point to the endpoint, effectively representing the total displacement.
  • Such graphical solutions give a visual check to confirm calculations.
  • They also illustrate vector relationships in comprehensible ways, which aids in learning and understanding vector behavior.
This visual approach complements analytical methods, providing a comprehensive understanding.

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Most popular questions from this chapter

A dart gun is fired while being held horizontally at a height of \(1.00 \mathrm{~m}\) above ground level and while it is at rest relative to the ground. The dart from the gun travels a horizontal distance of \(5.00 \mathrm{~m}\). A college student holds the same gun in a horizontal position while sliding down a \(45.0^{\circ}\) incline at a constant speed of \(2.00 \mathrm{~m} / \mathrm{s}\). How far will the dart travel if the student fires the gun when it is \(1.00 \mathrm{~m}\) above the ground?

An artillery shell is fired with an initial velocity of \(300 \mathrm{~m} / \mathrm{s}\) at \(55.0^{\circ}\) above the horizontal. To clear an avalanche, it explodes on a mountainside \(42.0 \mathrm{~s}\) after firing. What are the \(x\) -and \(y\) -coordinates of the shell where it explodes, relative to its firing point?

A golfer takes two putts to get his ball into the hole once he is on the green. The first putt displaces the ball \(6.00 \mathrm{~m}\) east, the second \(5.40 \mathrm{~m}\) south. What displacement would have been needed to get the ball into the hole on the first putt?

A jogger runs \(100 \mathrm{~m}\) due west, then changes direction for the second leg of the run. At the end of the run, she is 175 \(\mathrm{m}\) away from the starting point at an angle of \(15.0^{\circ}\) north of west. What were the direction and length of her second displacement? Use graphical techniques.

A boat moves through the water of a river at \(10 \mathrm{~m} / \mathrm{s}\) relative to the water, regardless of the boat's direction. If the water in the river is flowing at \(1.5 \mathrm{~m} / \mathrm{s}\), how long does it Lake the boat to make a round trip consisting of a \(900-\mathrm{m}\) displacement downstream followed by a \(300-\mathrm{m}\) displacement upstream?

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