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A chinook (king) salmon (genus Oncorhynchus) can jump out of water with a speed of \(6.26 \mathrm{~m} / \mathrm{s}\). (See Problem \(4.9\), page 111 for an investigation of how the fish can leave the water at a higher speed than it can swim underwater.) If the salmon is in a stream with water speed equal to \(1.50 \mathrm{~m} / \mathrm{s}\), how high in the air can the fish jump if it leaves the water traveling vertically upwards relative to the Earth?

Short Answer

Expert verified
The maximum height in the air that the fish can jump is approximately \(2 \mathrm{~m}\).

Step by step solution

01

Identify given values

First, identify the given values provided in the question. The speed of the fish as it jumps out of water is \(6.26 \mathrm{~m/s}\), which will be the initial velocity (\(u\)). The final velocity (\(v\)) of the fish when it reaches maximum height is \(0 \mathrm{~m/s}\) because it stops momentarily at the maximum height. The acceleration (\(g\)) is that due to gravity, which is \(-9.8 \mathrm{~m/s^2}\) (negative because it acts in the opposite direction of motion).
02

Apply equation of motion

Now apply the equation of motion to calculate the maximum height. The equation of motion that connects initial velocity, final velocity, acceleration and distance is \(v^2 = u^2 + 2gs\). We can rearrange this equation to solve for \(s\) (in this case the height), because that's what we need to find.
03

Calculate the height

Substitute the values of \(u\), \(v\), and \(g\) into the rearranged equation: \(s = (v^2 - u^2) / 2g\). After substituting the values, we get \(s = (0 - 6.26^2) / 2*(-9.8)\). Calculate this expression to find the height in meters that the fish can jump.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the branch of physics that studies the motion of objects without considering the forces that cause the motion. In the context of the jumping salmon, kinematics helps us explore how high the fish can rise above water. This involves analyzing the fish's movement in terms of initial velocity, final velocity, acceleration, time, and displacement. Always remember that kinematics focuses on the "how" of motion, rather than the "why".

When a fish jumps, it exhibits projectile motion, which in this case is simplified to a vertical motion since it jumps straight up. Key aspects of its kinematic analysis include:
  • Initial Velocity (\( u \)): This is the speed at which the salmon leaves the water, measured as 6.26 m/s.
  • Final Velocity (\( v \)): At the topmost point of the jump, the velocity is 0 m/s as the fish momentarily stops.
  • Acceleration: Here, the only acceleration at play is due to gravity, which steadily slows down the fish as it ascends.

Understanding these components allows us to use kinematic equations to predict the behavior of the fish's jump, such as how high it will go.
Equations of Motion
Equations of motion are mathematical formulas in kinematics that describe the relationship between velocity, acceleration, and displacement. They provide a way to predict an object's future motion based on its current state.

In our salmon jumping scenario, we employed one of these equations. Specifically, we used the equation:
\[v^2 = u^2 + 2gs\]
This particular equation relates the initial velocity (\( u \)), final velocity (\( v \)), acceleration (\( g \)), and displacement (\( s \) where height is a form of displacement). It helps us solve for the unknown, in this case, the height (\( s \)).

To find how high the salmon can jump, we rearranged the equation to solve for \( s \):
\[s = \frac{v^2 - u^2}{2g}\]
By substituting the known values — initial velocity (\( u = 6.26 \, \mathrm{m/s} \)), final velocity (\( v = 0 \, \mathrm{m/s} \)), and acceleration (\( g = -9.8 \, \mathrm{m/s}^2 \)) — into this formula, we determined the maximum height the fish can reach.
Gravity
Gravity is the force that attracts objects toward the Earth’s center. It is a constant downward force and plays a crucial role in projectile motion, such as a fish jumping out of the water.

Here, gravity is represented by the acceleration \( g \), with a standard value of approximately \(-9.8 \, \mathrm{m/s^2} \). This negative sign indicates that gravity works in the opposite direction of the fish's initial, upward velocity.

As the salmon jumps, gravity acts to decelerate it. It continually reduces the fish's upward velocity until it reaches zero at the peak of the jump. This peak is where the fish temporarily halts before gravity pulls it back down, reversing its motion direction.
  • Because gravity is constant, it provides a reliable measure for predicting how motion will change over time.
  • Understanding gravity's impact on the jump allows us to anticipate the maximum height the salmon can achieve.

In kinematics, careful consideration of gravity is vital, as it is the unchanging factor that affects the trajectory and final outcome of any projectile motion.

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Most popular questions from this chapter

A novice golfer on the green takes three strokes to \(\sin \mathrm{k}\) the ball. The successive displacements of the ball are \(4.00 \mathrm{~m}\) to the north, \(2.00 \mathrm{~m} 45.0^{\circ}\) north of east, and \(1.00 \mathrm{~m}\) at \(30.0^{\circ}\) west of south. Starting at the same initial point, an expert golfer could make the hole in what single displacement?

How long does it take an automobile traveling in the left lane of a highway at \(60.0 \mathrm{~km} / \mathrm{h}\) to overtake (become even with) another car that is traveling in the right lane at \(40.0 \mathrm{~km} / \mathrm{h}\) when the cars' front bumpers are initially \(100 \mathrm{~m}\) apart?

A boat moves through the water of a river at \(10 \mathrm{~m} / \mathrm{s}\) relative to the water, regardless of the boat's direction. If the water in the river is flowing at \(1.5 \mathrm{~m} / \mathrm{s}\), how long does it Lake the boat to make a round trip consisting of a \(900-\mathrm{m}\) displacement downstream followed by a \(300-\mathrm{m}\) displacement upstream?

Vector \(\vec{A}\) is \(3.00\) units in length and points along the positive x-axis. Vector \(\overrightarrow{\mathbf{B}}\) is \(4.00\) units in length and points along the negative y-axis. Use graphical methods to find the magnitude and direction of the vectors (a) \(\vec{A}+\vec{B}\) and (b) \(\overrightarrow{\mathbf{A}}-\overrightarrow{\mathbf{B}}\).

If a person can jump a maximum horizontal distance (by using a 45 projection angle) of \(3.0 \mathrm{~m}\) on Earth, what would be his maximum range on the Moon, where the free-fall acceleration is \(g / 6\) and \(g=9.80 \mathrm{~m} / \mathrm{s}^{2}\) ? Repeat for Mars, where the acceleration due to gravity is \(0.38 g .\)

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