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A flat piece of glass is supported horizontally above the flat end of a \(10.0-\mathrm{cm}\) -long metal rod that has its lower end rigidly fixed. The thin film of air between the rod and the glass is observed to be bright when illuminated by light of wavelength \(500 \mathrm{~nm} .\) As the temperature is slowly increased by \(25.0^{\circ} \mathrm{C}\), the film changes from bright to dark and back to bright 200 times. What is the coefficient of linear expansion of the metal?

Short Answer

Expert verified
The coefficient of linear expansion for the metal rod is \(4 \times 10^{-6} °C^{-1}\).

Step by step solution

01

Understanding the Given Parameters

This step involves understanding the given data. In this exercise, the following parameters are given: \n Initial length of the rod \(L_0 = 10.0 cm\), \nChange in temperature \(\Delta T = 25.0 °C\), \nNumber of fringes \(N = 200\), \nWavelength of light \(\lambda = 500 nm\).
02

Formula for Coefficient of Linear Expansion

The coefficient of linear thermal expansion \(\alpha\) is defined as the fractional increase in length per unit rise in temperature. The formula for the coefficient of linear expansion is: \[\alpha = \frac{\Delta L} {L_0 \Delta T}\] Where \(\Delta L\) is the change in length of the rod.
03

Calculate the change in length

The change in length \(\Delta L\) is due to the thermal expansion and corresponds to the number of fringes. Each fringe corresponds to a path difference of one wavelength, so: \[\Delta L = N \lambda = 200 \times 500 \times 10^{-9} m = 0.0001 m.\]
04

Calculate the Coefficient of Linear Expansion

Substitute \(\Delta L\), \(L_0\) and \(\Delta T\) into the linear expansion formula: \[\alpha = \frac{\Delta L} {L_0 \Delta T} = \frac{0.0001 m} {0.1 m \times 25 °C } = 4 \times 10^{-6} °C^{-1}\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Linear Expansion
Thermal expansion is a common phenomenon where materials change size due to changes in temperature. The Coefficient of Linear Expansion (\(\alpha\)) quantifies this effect. It represents how much a material's length will change for each degree change in temperature. To calculate \(\alpha\), you can use the formula:\[\alpha = \frac{\Delta L}{L_0 \Delta T}\]- \(\Delta L\) is the change in length. - \(L_0\) is the original length of the material.- \(\Delta T\) is the change in temperature.Understanding this formula allows you to see how vast changes in temperature can significantly affect structures and materials. Engineers must consider these effects to prevent structural deformities or failures due to thermal expansion. The coefficient is unique for each material, indicating how sensitive each is to temperature changes. Metals often have a higher \(\alpha\) compared to other materials like ceramics or glass.
Interference of Light
Interference of light is an intriguing phenomenon where light waves overlap, creating patterns of bright and dark bands. These patterns result from constructive and destructive interference. When waves align perfectly in phase, they amplify each other, creating a bright band. When they are out of phase, they cancel each other, leading to a dark band. - **Constructive Interference**: Occurs when the path difference between two light waves is an integer multiple of their wavelength. - **Destructive Interference**: Happens when the path difference is a half-integer multiple of the wavelength. This is why you see alternating bright and dark bands. Interference is not only crucial to understanding wave behavior but also plays a critical role in various modern technologies, such as lasers and fiber optic communication. Studying interference helps us harness light effectively for numerous applications.
Thin Film Interference
Thin film interference occurs when light waves reflect off different surfaces of a thin layer, such as a soap bubble or an oil slick. These reflected waves interact with each other, leading to the fascinating colorful patterns you often observe. The thickness of the film and the wavelength of the light determine the interference pattern: - When the film's thickness is such that the path difference between the reflecting waves is a multiple of the wavelength, constructive interference produces bright colors. - Conversely, if the path difference leads to wave alignment off-phase by half a wavelength, destructive interference results in dark areas. This phenomenon reveals itself in everyday life, such as the vivid colors seen in soap bubbles or oil spills. Understanding thin film interference is also crucial in designing anti-reflective coatings and understanding biological structures like butterfly wings.

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Most popular questions from this chapter

A possible means for making an airplane invisible to radar is to coat the plane with an antireflective polymer. If radar waves have a wavelength of \(3.00 \mathrm{~cm}\) and the index of refraction of the polymer is \(n=1.50\), how thick would you make the coating?

Ecp Astronomers observe the chromosphere of the Sunt with a filter that passes the red hydrogen spectral line of wavelength \(656.3 \mathrm{~nm}\), called the \(\mathrm{H}_{\alpha}\) line. The filter consists of a transparent dielectric of thickness \(d\) held between two partially aluminized glass plates. The filter is kept at a constant temperature. (a) Find the minimum value of \(d\) that will produce maximum transmission of perpendicular \(\mathrm{H}_{a}\) light if the dielectric has an index of refraction of \(1.378 .\) (b) If the temperature of the filter increases above the normal value increasing its thickness, what happens Lo the transmitted wavelength? (c) The dielectric will also pass what near-visible wavelength? One of the glass plates is colored red to absorb this light.

The two speakers are placed \(35.0 \mathrm{~cm}\) apart. A single oscillator makes the speakers vibrate in phase at a frequency of \(2.00 \mathrm{kH}_{z}\). At what angles, measured from the perpendicular bisector of the line joining the speakers, would a distant observer hear maximum sound intensity? Minimum sound intensity? (Take the speed of sound to be \(340 \mathrm{~m} / \mathrm{s} .)\)

At what angle above the horizon is the Sun if light from it is completely polarized upon reflection from water?

Light with a wavelength in vacuum of \(546.1 \mathrm{~nm}\) falls perpendicularly on a biological specimen that is \(1.000 \mu \mathrm{m}\) thick. The light splits into two beams polarized at right angles, for which the indices of refraction are \(1.320\) and \(1.333\), respectively. (a) Calculate the wavelength of each component of the light while it is traversing the specimen. (b) Calculate the phase difference between the two beams when they emerge from the specimen.

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