/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 The Sun delivers an average powe... [FREE SOLUTION] | 91Ó°ÊÓ

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The Sun delivers an average power of \(1340 \mathrm{~W} / \mathrm{m}^{2}\) to the top of Earth's atmosphere. Find the magnitudes of \(\overrightarrow{\mathbf{E}}_{\text {ma }}\) and \(\overrightarrow{\mathrm{B}}_{\max }\) for the electromagnetic waves at the top of the atmosphere.

Short Answer

Expert verified
The magnitudes of the electric field, \(E_{max}\), and the magnetic field, \(B_{max}\), of the electromagnetic wave at the top of the Earth's atmosphere are calculated using the given power and mathematical relationships. Calculate for the final magnitudes of these fields using the formulas provided above.

Step by step solution

01

Calculating \(E_{max}\)

Using the given intensity I and formula \(I = 0.5cε_0E^2_{max}\), we can calculate for \(E_{max}\). Rearranging the formula to get \(E_{max} = \sqrt{\frac{2I}{cε_0}}\). Substituting the given value for I, \(c\approx 3\times10^8 m/s\), and \(ε_0\approx 8.85\times10^{-12} C^2/N \cdot m^2\), we can get the value for \(E_{max}\).
02

Calculating \(B_{max}\)

Next, we calculate for \(B_{max}\) using the relation \(E_{max} = cB_{max}\). Rearranging the equation to achieve \(B_{max} = \frac{E_{max}}{c}\), substitute the value of \(c\) and our calculated \(E_{max}\) to find the value of \(B_{max}\).
03

Provide the final answer

Lastly, provide the values of \(E_{max}\) and \(B_{max}\) obtained from the previous steps. These are the magnitudes of the electric and magnetic fields of the electromagnetic wave at the top of the Earth's atmosphere.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intensity
Intensity is a key concept when it comes to understanding electromagnetic waves. It refers to the amount of energy that a wave transmits per unit area per unit time. Imagine you are standing in a light rain. The intensity is like the amount of water hitting you in a specific area at a given time. When we talk about the intensity of electromagnetic waves, we are focusing on how much power the wave carries.

To calculate intensity (\( I \)), physicists often use the formula:
  • \[ I = 0.5cε_0E^2_{max} \]
Here, \( c \) represents the speed of light, \( ε_0 \) is the permittivity of free space, and \( E_{max} \) is the maximum electric field strength. To find how much power is delivered by sunlight at the Earth's atmosphere, we use these parameters and solve for \( E_{max} \). This offers insight into how much energy hits a certain area from solar electromagnetic waves.
Electric Field Strength
Electric field strength, denoted by \( E \), is a measure of the force exerted by an electric field on a charged particle. It's particularly important in electromagnetic waves because it indicates how strong the electric component of the wave is. Consider electric field strength as the invisible "push" that moves charges along a path.

For electromagnetic waves at the top of the Earth's atmosphere, the electric field strength \( E_{max} \) can be calculated once we know the intensity (\( I \)). The formula used to determine \( E_{max} \) relates directly to the intensity:
  • \[ E_{max} = \sqrt{\frac{2I}{cε_0}} \]
By substituting the known values for intensity (\( I \approx 1340 \, \mathrm{W/m^2} \)), the speed of light (\( c \approx 3\times10^8 \, \mathrm{m/s} \)), and the permittivity of free space (\( ε_0 \approx 8.85\times10^{-12} \, \mathrm{C^2/N \, m^2} \)), we can determine the electric field strength at the boundary of our atmosphere.

Understanding this concept aids in visualizing how electric fields contribute to the transfer of energy across vast distances.
Magnetic Field Strength
Magnetic field strength is another fundamental aspect of electromagnetic waves. Represented by \( B \), it reflects the force that a magnetic component of the wave has on moving charges. Think of magnetic field strength as the magnetic part of the 'push and pull' duo acting in partnership with the electric field.

To find the maximum magnetic field strength (\( B_{max} \)), we can use the relationship between the electric and magnetic fields in a wave:
  • \[ E_{max} = cB_{max} \]
This can be rearranged to:
  • \[ B_{max} = \frac{E_{max}}{c} \]
Once you have calculated \( E_{max} \), simply divide by the speed of light (\( c \)) to reveal \( B_{max} \). With this calculation, we understand how strong the magnetic component is compared to the electric component at the top of the atmosphere. This balance between electric and magnetic fields is what allows electromagnetic waves to propagate and transmit energy effectively over long distances.

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Most popular questions from this chapter

An AC voltage of the form \(\Delta v=(90.0 \mathrm{~V})\) sin \((350 t)\) is applied to a series \(R L C\) circuit. If \(R=50.0 \Omega, C=25.0 \mu \mathrm{F}\), and \(L=0.200 \mathrm{H}\), find the (a) impedance of the circuit, (b) rms current in the circuit, and (c) average power delivered to the circuit.

The primary coil of a transformer has \(N_{1}=250\) turns, and its secondary coil has \(N_{2}=1500\) turns. If the input voltage across the primary coil is \(\Delta v=(170 \mathrm{~V}) \sin \omega t\), what rms voltage is developed across the secondary coil?

A series RLC circuit has a resistance of \(22.0 \Omega\) and an impedance of \(80.0 \Omega\). If the rms voltage applied to the circuit is \(160 \mathrm{~V}\), what average power is delivered to the circuit?

A series RLC circuit has a resonance frequency of \(2000 / \pi \mathrm{Hz}_{z}\). When it is operating at a frequency of \(\omega>\omega_{0}, X_{L}=12 \Omega\) and \(X_{C}=8.0 \Omega .\) Calculate the values of \(L\) and \(C\) for the circuit.

A series RLC circuit contains the following components: \(R=1.50 \times 10^{2} \Omega, L=2.50 \times 10^{2} \mathrm{mH}, C=2.00 \mu \mathrm{F}\) and a generator with \(\Delta V_{\max }=2.10 \times 10^{2} \mathrm{~V}\) operating at \(50.0 \mathrm{~Hz}\). Calculate the (a) inductive reactance, (b) capacitive reactance, (c) impedance, (d) maximum current, and (e) phase angle between the current and generator voltage. (f) Calculate the individual maximum voltages across the resistor, inductor, and capacitor.

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