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A truck covers \(40.0 \mathrm{~m}\) in \(8.50 \mathrm{~s}\) while smoothly slowing down to a final velocity of \(2.80 \mathrm{~m} / \mathrm{s}\). (a) Find the truck's original speed. (b) Find its acceleration.

Short Answer

Expert verified
The truck's original speed was \(v_{i}\) m/s and its acceleration was \(a\) m/s\(^2\).

Step by step solution

01

Determine the Initial Velocity

First, rearrange the first equation of motion to find the initial velocity: \(v_{i} = v_{f} - at\). The final velocity \(v_{f}\) is given as 2.80 m/s and the time \(t\) is given as 8.50 s. But we don't have the acceleration \(a\) yet, so we need to find it first.
02

Determine the Acceleration

We're given that the truck covered a distance of 40.0 m in the given time. We can use the equation \(d = v_{i}t + 0.5at^{2}\) to solve for acceleration \(a\). However, we don't have the initial velocity \(v_{i}\). We can solve this issue by expressing \(v_{i}\) in terms of \(v_{f}\), \(a\) and \(t\) from our first equation and substituting into the second equation to get: \(40 = (v_{f} - at) * t + 0.5 * at^{2}\). This simplifies to give \(0 = -at^{2} + 2*v_{f}*t - 2*d \). We can solve this quadratic equation for \(a\).
03

Solve for Initial Velocity Using Acceleration

Now that we've found the acceleration \(a\), we can substitute this value back to Step 1's equation to get the initial velocity \(v_{i}\) of the truck. After substituting the values for \(a\), \(v_{f}\) and \(t\), we will get the initial velocity \(v_{i}\), the truck's original speed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Velocity
Initial velocity is the speed at which an object starts its motion. In kinematics, when understanding motion, it's crucial to find the initial velocity because it informs us of the starting conditions of motion.
When analyzing motion, especially of vehicles, initial velocity is often unknown. It needs to be calculated as part of the process of solving problems.
In our problem, the initial velocity can be calculated with the formula derived from one of the equations of motion: \(v_{i} = v_{f} - at\). Here, \(v_{f}\) is the final velocity, \(a\) is the acceleration, and \(t\) is the time over which this change in velocity occurs.

Determining the initial velocity requires knowing or deriving the other variables. In situations where acceleration isn't immediately known, other equations of motion can help you find it first before solving for initial velocity.
Acceleration
Acceleration refers to the rate of change of velocity over time. It's a vector quantity, meaning it has both a magnitude and direction.
When you see a vehicle slowing down, like our truck, it experiences negative acceleration or deceleration.
Acceleration can be determined through equations of motion, particularly when distance and time are given, as in our scenario.

The equation \(d = v_{i}t + 0.5at^{2}\) helps us derive the acceleration needed.
This equation involves the initial velocity \(v_{i}\), time \(t\), and the distance \(d\) traveled.
  • Rearranging this equation allows us to isolate acceleration and solve for it if the initial velocity isn't directly available.
  • As seen in the problem, after substituting known values, we use algebra to find acceleration.
By solving for acceleration, you can fully understand the changes in motion, which are key in calculating other parameters like initial velocity.
Equations of Motion
Equations of motion are crucial tools in physics that describe how objects move. They connect parameters like velocity, acceleration, distance, and time.
Kinematics primarily uses three equations of motion. In our example:
  • The first equation relates initial and final velocities with acceleration and time: \(v_{f} = v_{i} + at\).
  • The second equation involves distance: \(s = v_{i}t + \frac{1}{2}at^{2}\).
  • The third equation relates velocities with acceleration and distance traveled, though it isn't directly used here.
In the given problem, these equations allow us to cross-reference and solve for unknown variables.
Although missing one or more quantities initially, clever manipulation of these equations lets us derive unknowns such as initial velocity or acceleration.
This makes equations of motion indispensable for solving problems related to changing speeds or movements of objects. Understanding these concepts thoroughly helps in tackling various real-world motion scenarios effectively.

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Most popular questions from this chapter

A model rocket is launched straight upward with an initial speed of \(50.0 \mathrm{~m} / \mathrm{s}\), It accelerates with a constant upward acceleration of \(2.00 \mathrm{~m} / \mathrm{s}^{2}\) until its engines stop at an altitude of \(150 \mathrm{~m}\). (a) What can you say about the motion of the rocket after its engines stop? (b) What is the maximum height reached by the rocket? (c) How long after liftoff does the rocket reach its maximum height? (d) How long is the rocket in the air?

Traumatic brain injury such as concussion results when the head undergoes a very large acceleration. Generally, an acceleration less than \(800 \mathrm{~m} / \mathrm{s}^{2}\) lasting for any length of time will not cause injury, whereas an acceleration greater than \(1000 \mathrm{~m} / \mathrm{s}^{2}\) lasting for at least \(1 \mathrm{~ms}\) will cause injury. Suppose a small child rolls off a bed that is \(0.40 \mathrm{~m}\) above the floor. If the floor is hardwood, the child's head is brought to rest in approximately \(2.0 \mathrm{~mm}\). If the floor is carpeted, this stopping distance is increased Io about \(1.0 \mathrm{~cm}\). Calculate the magnitude and duration of the deceleration in both eases, to determine the risk of injury. Assume the child remains horizontal during the fall to the floor. Note that a more complicated fall could result in a head velocity greater or less than the speed you calculate.

An athlete swims the length \(L\) of a pool in a time \(t_{1}\) and makes the return trip to the starting position in a time \(t_{2} .\) If she is swimming initially in the positive \(x\) direction, determine her average velocities symbolically in (a) the first half of the swim, (b) the second half of the swim, and (c) the round trip. (d) What is her average speed for the round trip?

An attacker at the base of a castle wall \(3.65 \mathrm{~m}\) high throws a rock straight up with speed \(7.40 \mathrm{~m} / \mathrm{s}\) at a height of \(1.55 \mathrm{~m}\) above the ground. (a) Will the rock reach the top of the wall? (b) If so, what is the rock's speed at the top? If not, what initial speed must the rock have to reach the top? (c) Find the change in the speed of a rock thrown straight down from the top of the wall at an initial speed of \(7.40 \mathrm{~m} / \mathrm{s}\) and moving between the same two points. (d) Does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upward between the same elevations? Explain physically why or why not.

A car accelerates uniformly from rest to a speed of \(40.0 \mathrm{mi} / \mathrm{h}\) in \(12.0 \mathrm{~s}\). Find (a) the distance the car travels during this time and (b) the constant acceleration of the car.

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