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A proton travels with a speed of \(5.02 \times 10^{6} \mathrm{~m} / \mathrm{s}\) at an angle of \(60^{\circ}\) with the direction of a magnetic ficld of magnitude \(0.180 \mathrm{~T}\) in the positive \(\bar{x}\) -direction. What are (a) the magnitude of the magnetic force on the proton and (b) the proton's acceleration?

Short Answer

Expert verified
The magnitude of the magnetic force acting on the proton is approximately \(2.79 \times 10^{-15}\) N, and the acceleration of the proton is approximately \(1.67 \times 10^{12}\ \mathrm{m/s^2}\)

Step by step solution

01

Calculate the magnetic Force

The force \(F\) is given by \(F = qvBsin\theta\), where \(q = 1.6 \times 10^{-19} \mathrm{~C}\), \(v = 5.02 \times 10^{6}\ \mathrm{~m/s}\), \(B = 0.180\ \mathrm{T}\), and the angle \(\theta = 60^{\circ}\). Now put these values into the equation to get the magnetic force.
02

Calculate the acceleration

To calculate the acceleration, use Newton's second law \(F=ma\), where \(m = 1.67 \times 10^{-27} \mathrm{~kg}\) is the mass of the proton and \(F\) is the force calculated in step 1. Solve this equation for \(a\) (acceleration).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton Acceleration
Acceleration is an important aspect of motion, and when it involves charged particles like protons within a magnetic field, things get interesting. The acceleration of a proton tells us how fast its velocity changes with time. It's like if you're in a car and suddenly hit the gas; the car's speed increases and you feel pushed back against your seat. This concept isn't much different at the atomic level.

To calculate a proton’s acceleration, we first determine the magnetic force acting upon it using the formula: - \( F = qvB\sin\theta \).

Here:
  • \( q \) is the proton’s electric charge, \( 1.6 \times 10^{-19} \mathrm{~C} \).
  • \( v \) is the velocity, \( 5.02 \times 10^{6} \mathrm{~m/s} \).
  • \( B \) is the magnetic field strength, \( 0.180 \mathrm{~T} \).
  • \( \theta \) is the angle between the magnetic field and the proton’s direction, \( 60^{\circ} \).
Once the force is determined, we apply Newton's second law to find acceleration. The law combines force, mass, and acceleration in the following way: \( F = ma \). Rearranging this formula gives us the acceleration as,\( a = \frac{F}{m} \). Knowing the mass of the proton (\( m = 1.67 \times 10^{-27} \mathrm{~kg} \)), we can easily solve for its acceleration.
Newton's Second Law
Newton's second law is a cornerstone of classical mechanics. It provides a simple yet powerful way to understand how objects move and respond to forces. This law can be verbally stated as: *The acceleration of an object is directly proportional to the net force acting upon it and inversely proportional to its mass.*

Mathematically, it is expressed as: - \( F = ma \), where
  • \( F \) stands for the force applied to an object,
  • \( m \) is the mass of the object,
  • \( a \) refers to the acceleration.
This means that for a given force, a heavier object will have less acceleration compared to a lighter one. For instance, if you push a car and a bicycle with the same amount of force, the bicycle will speed up faster than the car because it has less mass.

When applied to problems involving protons and magnetic fields, Newton’s second law helps us calculate how protons accelerate under the influence of magnetic forces. By knowing the force exerted by the field and the mass of the proton, we can determine its acceleration, providing insights into its behavior in magnetic environments.
Magnetic Field
A magnetic field is an invisible force field that surrounds magnetic objects and can influence other magnetic or charged objects that enter it. Think of it like a gentle breeze that moves around, affecting anything light enough in its path. Though we can't see magnetic fields, their effects are quite tangible—they can pull or push on materials like iron or affect the paths of charged particles.

A magnetic field is usually represented by the symbol \( B \) and is measured in units called teslas (\( \mathrm{T} \)). These fields have both magnitude and direction, and their ability to exert force or influence a charged particle depends on:
  • the strength of the field (the larger the \( B \), the stronger the field),
  • the velocity of the particle moving through it, and
  • the angle at which the particle cuts across the field lines.
In the context of a proton moving in a magnetic field, the field influences its path by exerting a force perpendicular to both its velocity and the magnetic field direction. This force does not speed up or slow down the particle but alters its direction, causing the proton to undergo circular motion. This principle allows scientists and engineers to manipulate charged particles in various ways, serving as a fundamental concept in designing devices like cyclotrons and mass spectrometers.

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Most popular questions from this chapter

A cosmic-ray proton in interstellar space has an energy of \(10.0 \mathrm{MeV}\) and executes a circular orbit having a radius equal to that of Mercury's orbit around the Sun, which is \(5.80 \times 10^{10} \mathrm{~m}\). What is the magnetic field in that region of space?

A laboratory electromagnet produces a magnetic field of magnitude \(1.50 \mathrm{~T}\). A proton moves through this field with a speed of \(6.00 \times 10^{6 \mathrm{~m} / \mathrm{s} . \text { (a) Find the mag- }}\) nitude of the maximum magnetic force that could be exerted on the proton. (b) What is the magnitude of the maximum acceleration of the proton? (c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? Would the electron undergo the same acceleration? Explain.

Sodium ions (Nat) move at \(0.851 \mathrm{~m} / \mathrm{s}\) through a bloodstream in the arm of a person standing near a large magnet. The magnetic field has a strength of \(0.254 \mathrm{~T}\) and makes an angle of \(51.0^{\circ}\) with the motion of the sodium jons. The arm contains \(100 \mathrm{~cm}^{3}\) of blood with a concentration of \(3.00 \times 10^{20} \mathrm{Na}^{+}\) ions per cubic centimeter, If no other ions were present in the arm, what would be the magnetic force on the arm?

A 50 -turn coil of radius \(5.0 \mathrm{~cm}\) rotates in a uniform magnetic field having a magnitude of \(0.50 \mathrm{~T}\). If the coil carries a current of \(25 \mathrm{~mA}\), find the magnitude of the maximum torque exerted on the coil.

A wire with a weight per unit length of \(0.080 \mathrm{~N} / \mathrm{m}\) is suspended directly above a second wire. The top wire carries a current of \(30.0 \mathrm{~A}\), and the bottom wire carries a current of \(60.0 \mathrm{~A}\). Find the distance of separation between the wires so that the top wire will be held in place by magnetic repulsion.

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