/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 An eight-turn coil encloses an e... [FREE SOLUTION] | 91Ó°ÊÓ

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An eight-turn coil encloses an elliptical area having a major axis of \(40.0 \mathrm{~cm}\) and a minor axis of \(30.0 \mathrm{~cm}\) (Fig. P19.27). The coil lies in the plane of the page and has a \(6.00-\mathrm{A}\) current flowing clockwise around it. If the coil is in a uniform magnetic field of \(2.00 \times 10^{-4} \mathrm{~T}\) directed toward the left of the page, what is the magnitude of the torque on the coil? (Hint: The area of an ellipse is \(A=\pi a b\), where \(a\) and \(b\) are, respectively, the semimajor and semiminor axes of the ellipse.)

Short Answer

Expert verified
The magnitude of the torque on the coil in the magnetic field is \(0.0898 ~\text{Nm}\).

Step by step solution

01

Calculate the Area of the Ellipse

First, calculate the area of the elliptical coil using the given dimensions. The formula for the area of an ellipse is \(A = \pi a b\), where \(a\) and \(b\) are the semi-major and semi-minor axes. The given values are for the entire ellipse, so we divide those by 2 to get \(a = 20.0~\text{cm} = 0.2~\text{m}\) and \(b = 15.0~\text{cm} = 0.15~\text{m}\). Therefore, the area will be calculated as \(A = \pi \cdot 0.2~\text{m} \cdot 0.15~\text{m} = 0.094~\text{m}^2\).
02

Calculate Torque

Now, use the formula for torque on a coil in a magnetic field: \(\tau = NIA\sinθB\). Here, \(N=8\) as the coil has 8 turns, \(I = 6.00~\text{A}\) as given, \(A = 0.094~\text{m}^2\) which we calculated earlier, \(B = 2.00 \times 10^{-4}~\text{T}\) as given. The magnetic field is directed toward the left of the page and current is flowing clockwise around the coil, which gives the angle \(θ=90^{\circ}\). So, \(\sinθ=1\). Plug in all the values to get the torque: \(\tau = 8 \cdot 6.00~\text{A} \cdot 0.094~\text{m}^2 \cdot 1 \cdot 2.00 \times 10^{-4}~\text{T} = 0.0898~\text{Nm}\).
03

Final Answer

So, the magnitude of the torque on the coil is \(0.0898~\text{Nm}\). Remember that the torque is a vector quantity and it tends to rotate the coil out of the plane of the page.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Fields
Magnetic fields play a fundamental role in the physics of electromagnetic interactions. They are created by moving electric charges, such as a current flowing through a wire. These fields exert a force on other moving charges and magnetic materials. In our context, a uniform magnetic field is one that has the same strength and direction everywhere within a specified area. In this exercise, the magnetic field is directed toward the left, perpendicular to the current direction, which is crucial for torque induction. The magnetic field strength is often denoted by the letter B and measured in teslas (T). A stronger magnetic field exerts a more significant influence on charged particles and currents moving within it. Here, the field's strength is given as a relatively small value of \(2.00 \times 10^{-4} \text{ T} \), indicating a weak but uniform field affecting the coil.
Elliptical Coil
An elliptical coil differs from circular and rectangular coils in its shape. Instead of having a consistent radius, an elliptical shape involves two distinct axes: the major and the minor. In this problem, the elliptical coil has a major axis measuring \(40.0 \text{ cm}\) and a minor axis measuring \(30.0 \text{ cm}\). To calculate the semi-major and semi-minor axes, which are essential for computing the area, we halve these values: \(20.0 \text{ cm} \) and \(15.0 \text{ cm} \). The area \( A \) of an ellipse is crucial when calculating torque since it defines the space through which the magnetic field interacts with the current. The formula for the area of an ellipse, \(A = \pi a b \), allows us to compute \(0.094 \text{ m}^2\) with \(a\) and \(b\) as the semi-major and semi-minor axes in meters. Understanding the coil's geometry helps us comprehend how this shape affects the torque experienced due to interaction with the magnetic field.
Torque Calculation
Calculating torque involves understanding its components, especially when dealing with coils in a magnetic field. Torque, denoted by \( \tau \), measures the tendency of a force to rotate an object around an axis. For a coil, this rotation is influenced by several factors:
  • The number of turns \( N \), which impacts the total interaction with the field
  • The current \( I \) flowing through the coil
  • The area \( A \) of the coil that the magnetic field penetrates
  • The magnetic field strength \( B \)
  • The angle \( \theta \) between the normal to the coil and the magnetic field direction
The formula \( \tau = NIA\sin\theta B \) integrates these to determine the torque's magnitude. For maximal torque, the angle \( \theta \) should be \(90^\circ\), ensuring that \( \sin\theta = 1 \). This equation reflects how each parameter contributes to the torque, and substituting the calculated and given values results in \(0.0898 \text{ Nm}\). This torque hinges on the interplay of current, coil turns, field strength, and geometry.

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Most popular questions from this chapter

A uniform horizontal wire with a linear mass density of \(0.50 \mathrm{~g} / \mathrm{m}\) carries a \(2.0-\mathrm{A}\) current. It is placed in a constant magnetic field with a strength of \(4.0 \times 10^{-3} \mathrm{~T}\). The field is horizontal and perpendicular to the wire. As the wire moves upward starting from rest, (a) what is its acceleration and (b) how long does it take to rise \(50 \mathrm{~cm}\) ? Neglect the magnetic field of Earth.

A current of \(17.0 \mathrm{~mA}\) is maintained in a single circular loop with a circumference of \(2.00 \mathrm{~m}\). A magnetic field of \(0.800 \mathrm{~T}\) is directed parallel to the plane of the loop. What is the magnitude of the torque exerted by the magnetic field on the loop?

A cosmic-ray proton in interstellar space has an energy of \(10.0 \mathrm{MeV}\) and executes a circular orbit having a radius equal to that of Mercury's orbit around the Sun, which is \(5.80 \times 10^{10} \mathrm{~m}\). What is the magnetic field in that region of space?

Figure P19.64 is a setup that can be used to measure magnetic fields. A rectangular coil of wire contains N turns has a width \(w\). The coil is attached to one arm of a balance and is suspended between the poles of a magnet. The field is uniform and perpendicular to the plane of the coil. The system is first balanced when the current in the coil is zero. When the switch is closed and the coil carries a current \(I\), a mass \(m\) must be added to the right side to balance the system. (a) Find an expression for the magnitude of the magnetic field and determine its direction. (b) Why is the result independent of the vertical dimension of the coil? (c) Suppose the coil has 50 turns and width of \(5.0 \mathrm{~cm}\). When the switch is closed, the coil carries a current of \(0.30 \mathrm{~A}\), and a mass of \(20.0 \mathrm{~g}\) must be added to the right side to balance the system. What is the magnitude of the magnetic field?

At the cquator, near the surface of Earth, the magnetic field is approximately \(50.0 \mu \mathrm{T}\) northward and the electric field is about \(100 \mathrm{~N} / \mathrm{C}\) downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron with an instantaneous velocity of \(6.00 \times 10^{6} \mathrm{~m} / \mathrm{s}\) directed to the east in this enyironment.

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