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What is the required resistance of an immersion heater that will increase the temperature of \(1.50 \mathrm{~kg}\) of water from \(10.0^{\circ} \mathrm{C}\) to \(50.0^{\circ} \mathrm{C}\) in \(10.0 \mathrm{~min}\) while operating at \(120 \mathrm{~V} ?\)

Short Answer

Expert verified
The required resistance of the immersion heater is approximately \(34.32 \Omega\).

Step by step solution

01

Calculate the Heat Required

The heat required to increase the temperature is calculated using the formula \(Q = mc\Delta T\), where m is the mass of the water (1.5kg), c is the specific heat capacity of water \((4.186 J/g^{\circ}C)\), and \(\Delta T\) is the change in temperature \((50^{\circ} C - 10^{\circ} C = 40^{\circ} C)\). So, \(Q = 1.5kg * 4.186 kJ/kg^{\circ}C * 40^{\circ}C = 251.16 kJ = 251.16 * 10^3 J\).
02

Calculate the Electrical Power

The electrical power can be calculated using the formula \(P = Q/t\), where Q is the heat required and t is the time. Time is given as 10 minutes, so convert it to seconds: \(10 min * 60 s/min = 600 s\). So, \(P = 251.16 * 10^3 J / 600s = 418.6W\).
03

Solve for Resistance

The power can also be calculated using the formula \(P = V^2 / R\), where V is the voltage and R is the resistance. We can solve for R: \(R = V^2 / P\). So, \(R = 120V^2 / 418.6W = 34.32 \Omega\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Resistance in Electric Circuits
Resistance is like a roadblock inside an electric circuit. It limits how much current can flow through. Imagine it like a narrow bridge that only allows a few cars to pass at a time. In electrical terms, resistance is measured in ohms (Ω).
The formula for resistance is \[ R = \frac{V^2}{P} \] where:
  • R is the resistance in ohms,
  • V is the voltage in volts,
  • P is the power in watts.

For example, if you know how much power a device uses and the voltage, you can calculate its resistance. This is crucial when you're designing circuits or troubleshooting electrical appliances.
A device with high resistance means it will reduce the current flowing through it. This is why some devices, like light bulbs, glow brighter using more power even though they have more resistance.
Calculating Electrical Power
Power in electrical circuits is the rate at which energy is used or generated. It tells us how much energy the circuit consumes per second. In a household, this is crucial because it affects your electricity bill. The basic formula for electrical power is: \[ P = \frac{Q}{t} \] where:
  • P is the power in watts,
  • Q is the total energy or heat in joules,
  • t is the time in seconds over which this energy is used.

Imagine having an immersion heater that needs to heat up water quickly. You would prefer a powerful heater to make this happen. For instance, our example showed a power calculation of 418.6 watts which means the heater needs this much wattage to warm the water efficiently in the given time. When calculating or converting time, always remember to convert minutes into seconds to get the accurate power calculation.
Specific Heat Capacity Explained
Specific heat capacity is like the energy 'currency' needed to change a substance's temperature. Every material has its own specific heat capacity, which tells us how much energy (in joules) is required to raise the temperature of one kilogram of the material by 1 degree Celsius.

The formula for specific heat capacity is: \[ Q = mc\Delta T \] where:
  • Q is the heat energy in joules,
  • m is the mass of the object in kilograms,
  • c is the specific heat capacity,
  • \(\Delta T\) is the change in temperature in degrees Celsius.

This concept is essential when you need to calculate how much energy it takes to heat a substance, as in our example where water was heated using an immersion heater. Knowing the specific heat capacity of water (4.186 J/g°C) helped us find the total energy needed to achieve the desired temperature change efficiently.

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Most popular questions from this chapter

While taking photographs in Death Valley on a day when the temperature is \(58.0^{\circ} \mathrm{C}\), Bill Hiker finds that a certain voltage applied to a copper wire produces a current of \(1.000 \mathrm{~A}\). Bill then travels to Antarctica and applies the same voltage to the same wire. What current does he register there if the temperature is \(-88.0^{\circ} \mathrm{C}\) ? Assume no change occurs in the wire's shape and size.

The cost of electricity varies widely throughout the United States; \( 0.120 / \mathrm{kWh}\) is a typical value. At this unit price, calculate the cost of (a) leaving a \(40.0-\mathrm{W}\) porch light on for 2 weeks while you are on vacation, (b) making a piece of dark toast in \(3.00 \mathrm{~min}\) with a \(970-\mathrm{W}\) toaster, and (c) drying a load of clothes in \(40.0 \mathrm{~min}\) in a \(5200-\mathrm{W}\) dryer.

A high-voltage transmission line with a resistance of \(0.31 \Omega / \mathrm{km}\) carries a current of \(1000 \mathrm{~A}\). The line is at a potential of \(700 \mathrm{kV}\) at the power station and carries the current to a city located \(160 \mathrm{~km}\) from the station. (a) What is the power loss due to resistance in the line? (b) What fraction of the transmitted power does this loss represent?

A 200-km-long high-voltage transmission line \(2.0 \mathrm{~cm}\) in diameter carries a steady current of \(1000 \mathrm{~A}\). If the conductor is copper with a free charge density of \(8.5 \times\) \(10^{28}\) electrons per cubic meter, how many years does it take one electron to travel the full length of the cable?

An iron wire has a cross-sectional area of \(5.00 \times\) \(10^{-6} \mathrm{~m}^{2}\). Carry out steps (a) through (e) to compute the drift speed of the conduction electrons in the wire. (a) How many kilograms are there in 1 mole of iron?

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