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(a) Find the electrostatic force between a \(\mathrm{Na}^{+}\) ion and a Cl ion separated by \(0.50 \mathrm{~nm}\). (b) Would the answer change if the sodium ion were replaced by Lit and the Chloride ion by \(\mathrm{Br}^{-}\) e Explain.

Short Answer

Expert verified
The electrostatic force between a sodium ion and a chlorine ion separated by 0.50 nm is roughly \( 9.2056 \times 10^{-9} N \). This would not change if we replaced the sodium ion with lithium and the chlorine ion with bromine because the charges on lithium and bromine ions are the same as on sodium and chlorine ions respectively, implying the same result according to Coulomb's Law.

Step by step solution

01

State Coulomb's Law

Coulomb's law states the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. It is given by \( F = k \cdot \frac{q1 \cdot q2} {r^2} \), where \( F \) is the electrostatic force, \( k \) is Coulomb's constant (\(8.99 \times 10^9 N \cdot m^2/C^2\)), \( q1 \) and \( q2 \) are the charges, and \( r \) is the separation.
02

Identify the values

The charges of sodium (\( \mathrm{Na}^{+} \)) and chlorine ions are \( +e \) and \( -e \), respectively, where \( e = 1.6 \times 10^{-19} C \). The separation distance is \( 0.50 \times 10^{-9} m \). Replace these values into Coulomb's Law.
03

Calculate the force

Upon substitution of the values, the equation becomes \( F = 8.99 \times 10^9 \cdot \frac{1.6 \times 10^{-19} \cdot -1.6 \times 10^{-19}} {(0.50 \times 10^{-9})^2} \). Upon resolving this, the force (in modulus) is roughly \( 9.2056 \times 10^{-9} N \).
04

Interpret the replacement of ions

Replacing sodium by lithium and chlorine by bromine will not change the result because both \( \mathrm{Li}^{+} \) and \( \mathrm{Br}^{-} \) have charges of \( +e \) and \( -e \) as well, similar to the charges of \( \mathrm{Na}^{+} \) and \( \mathrm{Cl}^{-} \). Thus, substituting these values would give the same result according to Coulomb's Law.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is a foundational principle in physics that describes the electrostatic interaction between two charged particles. The law states that the force (\( F \)) between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance (\( r \)) separating them. It is mathematically represented as:
\[ F = k \cdot \frac{q_1 \cdot q_2}{r^2} \]where:
  • \( F \) is the electrostatic force.
  • \( k \) is Coulomb's constant, approximately \( 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \).
  • \( q_1 \) and \( q_2 \) are the amounts of the charges involved.
  • \( r \) is the distance between the centers of the two charges.
The force described by Coulomb's Law is a vector, meaning it has both magnitude and direction. This force acts along the line joining the centers of the two charges. When the charges are of opposite signs, the force is attractive, pulling the charges toward one another. Conversely, if the charges have the same sign, they repel each other. This principle is crucial for understanding interactions at a molecular level, like those between ions, which we will explore shortly.
Ion Charges
Ions are atoms or molecules that have gained or lost electrons, giving them a net electric charge. Positive ions, known as cations, result from losing one or more electrons, whereas negative ions, anions, form by gaining electrons. Understanding ion charges is vital when applying Coulomb's Law, as this charge determines how ions interact with each other.In our example:
  • The \( \mathrm{Na}^{+} \) ion has a charge of \(+e \), where \( e \) is the elementary charge, approximately \( 1.6 \times 10^{-19} \text{C} \).
  • The \( \mathrm{Cl}^{-} \) ion has a charge of \(-e \, \).
These charges create an electrostatic force between them as described by Coulomb's Law. Because the sodium ion is positively charged and the chloride ion is negatively charged, the force between them will be attractive.Notably, this principle holds for other ions such as lithium (\( \mathrm{Li}^{+} \)) and bromide (\( \mathrm{Br}^{-} \)), because they also carry the charges \(+e\) and \(-e\) respectively, meaning that replacing one set of ions with another that has the same charges will yield the same electrostatic force.
Separation Distance
The distance between charged objects significantly affects the magnitude of the electrostatic force experienced between them. According to Coulomb's Law, the force is inversely proportional to the square of the separation distance (\( r \)).This means:
  • If the distance between the charges is halved, the force increases by a factor of four.
  • If the distance is doubled, the force decreases by a factor of four.
In the given problem, the separation distance between the sodium and chloride ions is \( 0.50 \, \text{nm} \), or \( 0.50 imes 10^{-9} \, \text{m} \). Accurately calculating the force requires converting the distance into meters, as Coulomb's constant is in units that include meters.Thus, the precise calculation is crucial and involves plugging the distance into Coulomb’s Law to understand how strongly these ions attract each other. This relationship between distance and force underscores why even tiny changes in molecular distances can significantly affect chemical interactions and states of matter.

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Most popular questions from this chapter

(a) Sketch the electric field pattern set up by a positively charged hollow sphere. Include regions inside and regions outside the sphere. (b) A conducring cube is given a positive charge. Sketch the electric field pattern both inside and outside the cube.

Two small identical conducting spheres are placed with their centers \(0.30 \mathrm{~m}\) apart. One is given a charge of \(12 \times 10^{-9} \mathrm{C}\), the other a charge of \(-18 \times 10^{-9} \mathrm{C}\). (a) Find the electrostatic force exerted on one sphere by the other. (b) The spheres are connected by a conducting wire. Find the electrostatic force between the two after equilibrium is reached.

Each of the electrons in a particle beam has a kinetic energy of \(1.60 \times 10^{-17} \mathrm{~J}\). (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' movement) that will stop these electrons in a distance of \(10.0 \mathrm{~cm}\) ? (b) How long will it take to stop the electrons? (c) After the electrons stop, what will they do? Explain.

Two point charges are a small distance apart. (a) Sketch the electric field lines for the two if one has a charge four times that of the other and both charges are positive. (b) Repeat for the case in which both charges are negative.

A proton accelerates from rest in a uniform electric field of \(640 \mathrm{~N} / \mathrm{C}\). At some later time, its speed is \(1.20 \times 10^{6} \mathrm{~m} / \mathrm{s}\). (a) Find the magnitude of the acceleration of the proton. (b) How long does it take the proton to reach this speed? (c) How far has it moved in that interval? (d) What is its kinetic energy at the later time?

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