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A taut clothesline has length \(L\) and a mass \(M\). \(A\) transverse pulse is produced by plucking one end of the -lothesline. If the pulse makes \(n\) round trips along the clothesline in \(t\) seconds, find expressions for (a) the speed of the pulse in terms of \(n, L\), and \(t\) and \((b)\) the tension in the clothesline in terms of the same variables and mass \(M\)

Short Answer

Expert verified
The speed of the pulse in terms of \(n, L\) and \(t\) is \(v = \frac{{2nL}}{t}\). The tension \(T\) in the clothesline in terms of \(n, L, t\) and \(M\) is \(T = \frac{4n^2M L^2}{t^2}\).\n

Step by step solution

01

Calculate the Pulse Speed

In order to find the speed of the pulse, it is necessary to divide the total distance that the pulse travels by the time it takes to travel that distance. Since the pulse makes \(n\) round trips along the clothesline of length \(L\), the total distance is \(2nL\). Thus, the speed \(v\) of the pulse is given by the formula \(v = \frac{{\text{{distance}}}}{{\text{{time}}}}\), so \(v = \frac{{2nL}}{t}\). Consequently, the speed of the pulse in terms of \(n, L\) and \(t\) is \(\frac{{2nL}}{t}\).
02

Find the Tension in the Clothesline

Knowing the speed of the pulse along the clothesline and the mass of the clothesline, the tension in the clothesline can be calculated using the formula for wave speed in a string: \(v = \sqrt{\frac{T}{\mu}}\), where \(T\) represents the tension in the string and \(\mu\) the linear density of the string (mass per unit length). In our case, \(\mu = \frac{M}{L}\). Rearranging the formula we get \(T = \mu v^2\). Substituting \(\mu\) and \(v\) we get \(T = \left(\frac{M}{L}\right) \left(\frac{2nL}{t}\right)^2\). After simplifying, the tension \(T\) in the clothesline in terms of \(n, L, t\) and \(M\) is \(T = \frac{4n^2M L^2}{t^2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Speed Formula
When studying wave mechanics, one of the fundamental concepts is the wave speed formula. This formula is crucial for understanding how quickly a disturbance propagates through a medium.

In the context of a transverse pulse on a string, such as a clothesline, the formula is elegantly simple. For a pulse making multiple round trips, speed is defined as the total distance traveled divided by the time taken. If it makes n round trips along a string of length L in t seconds, the speed v is calculated as \( v = \frac{2nL}{t} \), where the factor of 2 accounts for the round trip journey. Understanding this helps students grasp why wave speed can change depending on the medium, tension, and other physical properties.
Tension in a String
The tension T in a string plays a vital role in how waves behave while traveling through the string. It's linked to the force that's being applied to the string to keep it stretched. This tension affects the wave speed and can be determined from the physical properties of the wave.

To find the tension using wave characteristics, we can rearrange the wave speed formula: \( v = \sqrt{\frac{T}{\mu}} \), where \(\mu\) is the linear density and v is the wave speed. Solving for T gives us \( T = \mu v^2 \). This formula demonstrates that tension is directly proportional to the square of the wave speed – as the speed of the wave increases, so does the tension required to sustain that speed. For instance, the higher tension on guitar strings results in higher pitch notes, which is a practical application of this relationship.
Linear Density of a String
Linear density \(\mu\) of a string refers to the mass per unit length of the string and is a key parameter in understanding wave motion on strings. It is mathematically defined as \( \mu = \frac{M}{L} \), where M is the total mass of the string and L is the length.

Linear density impacts the wave speed; a string with greater mass per unit length (higher linear density) will typically have slower wave speeds for the same tension, similar to how thicker ropes tend to be less flexible than thinner ones. It's an important characteristic to consider, especially in musical instruments where the linear density of the strings influences tone and pitch. By altering the linear density, different frequencies of sound waves can be produced, which is the essence of creating music with stringed instruments.

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Most popular questions from this chapter

A spring of negligible mass stretches \(3.00 \mathrm{~cm}\) from its relaxed length when a force of \(7.50 \mathrm{~N}\) is applied. A \(0.500\) -kg particle rests on a frictionless horizontal surface and is attached to the free end of the spring. The particle is displaced from the origin to \(x=5.00 \mathrm{~cm}\) and released from rest at \(t=0 .\) (a) What is the force constant of the spring? (b) What are the angular frequency \(\omega\), the frequency, and the period of the motion? (c) What is the total energy of the system? (d) What is the amplitude of the motion? (e) What are the maximum velocity and the maximum acceleration of the particle? (f) Determine the displacement \(x\) of the particle from the equilibrium position at \(t=0.500 \mathrm{~s} .(\mathrm{g})\) Determine the velocity and acceleration of the particle when \(t=0.500 \mathrm{~s}\).

A certain tuning fork vibrates at a frequency of \(196 \mathrm{~Hz}\) while each tip of its two prongs has an amplitude of \(0.850 \mathrm{~mm}\). (a) What is the period of this motion? (b) Find the wavelength of the sound produced by the vibrating fork, taking the speed of sound in air to be \(343 \mathrm{~m} / \mathrm{s}\).

ecp A spring \(1.50 \mathrm{~m}\) long with force constant \(475 \mathrm{~N} / \mathrm{m}\) is hung from the ceiling of an elevator, and a block of mass \(10.0 \mathrm{~kg}\) is attached to the bottom of the spring. (a) By how much is the spring stretched when the block is slowly lowered to its equilibrium point? (b) If the elevator subsequently accelerates upward at \(2.00 \mathrm{~m} / \mathrm{s}^{2}\), what is the position of the block, taking the equilibrium position found in part (a) as \(y=0\) and upwards as the positive \(y\) -direction. (c) If the elevator cable snaps during the acceleration, describe the subsequent motion of the block relative to the freely falling elevator. What is the amplitude of its motion?

A cork on the surface of a pond bobs up and down two times per second on ripples having a wavelength of \(8.50 \mathrm{~cm}\). If the cork is \(10.0 \mathrm{~m}\) from shore, how long does it take a ripple passing the cork to reach the shore?

A "seconds" pendulum is one that moves through its equilibrium position once each second. (The period of the pendulum is \(2.000\) s.) The length of a seconds pendulum is \(0.9927 \mathrm{~m}\) at Tokyo and \(0.9942 \mathrm{~m}\) at Cambridge, England. What is the ratio of the free-fall accelerations at these two locations?

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