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Calculate the temperature at which a tungsten filament that has an emissivity of \(0.90\) and a surface area of \(2.5 \times 10^{-5} \mathrm{~m}^{2}\) will radiate energy at the rate of \(25 \mathrm{~W}\) in a room where the temperature is \(22^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The temperature of the tungsten filament, given that it radiates at a rate of 25 W, has an emissivity of 0.90, and a surface area of \(2.5 \times 10^{-5} m^{2}\), is calculated using the Stefan-Boltzmann law. The final temperature \(T\) is determined in Kelvin units, which can then be converted into Celsius if needed.

Step by step solution

01

Understanding the Stefan-Boltzmann Law

The Stefan-Boltzmann Law describes how the power radiated by a body depends on its temperature. The formula is given by: \(P = e\sigma A T^{4}\) where \(P\) is the power radiated, \(e\) is the emissivity, \(A\) is the surface area, \(T\) is the absolute temperature and \(\sigma\) is the Stefan-Boltzmann constant (\(5.67 \times10^{-8} Wm^{-2}K^{-4}\)).
02

Substitute the Given Values into the Stefan-Boltzmann Law and Solve for \(T^4\)

We substitute the given values into the formula: \(25 W = 0.90 \times (5.67 \times10^{-8} Wm^{-2}K^{-4}) \times (2.5 \times 10^{-5} m^{2}) \times T^{4}\) and solve for \(T^4\).
03

Calculate The Fourth Root of the Result to Get \(T\)

After finding the value of \(T^{4}\), we then calculate the fourth root of the result to get \(T\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Emissivity
Emissivity is a measure of how effectively a surface emits thermal radiation compared to a perfect black body. A perfect emitter, or black body, has an emissivity of 1, meaning it emits thermal radiation as efficiently as possible. Anything with an emissivity lower than 1 emits less radiation.

The emissivity of a material depends on its surface characteristics. Like roughness, color, and material composition. Metals typically have low emissivities, while darker, non-metallic surfaces tend to emit radiation more effectively. In the tungsten filament example, an emissivity value of 0.90 indicates that it's a highly efficient emitter. Almost as effective as a perfect black body.
  • Higher emissivity means more efficient thermal radiation.
  • Real-world materials rarely achieve an emissivity of 1.
  • Emissivity is crucial for energy calculations involving thermal radiation.
Thermal Radiation
Thermal radiation is energy given off by objects in the form of electromagnetic waves due to their temperature. All objects emit thermal radiation, regardless of whether they are solid, liquid, or gas. The intensity and characteristics of the radiation depend on the object's temperature and emissivity.

The Stefan-Boltzmann Law gives a precise way to calculate this thermal energy emission for a black body. It states that the power radiated by an object is proportional to the fourth power of its temperature. This is represented as:\[P = e\sigma AT^{4}\]where:
  • \(e\) = emissivity
  • \(\sigma\) = Stefan-Boltzmann constant \((5.67 \times 10^{-8} \text{Wm}^{-2}\text{K}^{-4})\)
  • \(A\) = surface area
  • \(T\) = absolute temperature in Kelvin
Understanding thermal radiation is integral for fields like astrophysics, climate science, and engineering. It's how we estimate stellar temperatures and understand Earth's energy balance.
Temperature Calculation
To determine the temperature at which an object radiates a certain amount of energy, you need to solve the Stefan-Boltzmann equation for temperature. In our example, where a tungsten filament emits energy at 25 watts, the steps to calculate the temperature are as follows:
  • Substitute the given values into the Stefan-Boltzmann equation: \(25 \text{ W} = 0.90 \times (5.67 \times 10^{-8} \text{Wm}^{-2}\text{K}^{-4}) \times (2.5 \times 10^{-5} \text{m}^{2}) \times T^{4}\).
  • Solve for \(T^{4}\). This involves dividing both sides by the product of emissivity, Stefan-Boltzmann constant, and surface area.
  • Calculate the fourth root of the result to find the absolute temperature \(T\).
This calculated temperature gives the point at which the filament radiates energy at the specified rate, providing valuable data for designing efficient heating elements and understanding heat transfer dynamics in thermal systems.

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Most popular questions from this chapter

The apparatus shown in Figure \(\mathrm{P} 11.10\) was used by Joule to measure the mechanical equivalent of heat. Work is done on the water by a rotating paddle wheel, which is driven by two blocks falling at a constant speed. The temperature of the stirred water increases due to the friction between the water and the paddles. If the energy lost in the bearings and through the walls is neglected, then the loss in potential energy associated with the blocks equals the work done by the paddle wheel on the water, If each block has a mass of \(1.50 \mathrm{~kg}\) and the insulated tank is filled with \(200 \mathrm{~g}\) of water, what is the increase in temperature of the water after the blocks fall through a distance of \(3.00 \mathrm{~m}\) ?

B. For bacteriological testing of water supplies and in medical clinics, samples must routinely be incubated for \(24 \mathrm{~h}\) at \(37^{\circ} \mathrm{C}\). A standard constant-temperature bath with electric heating and thermostatic control is not suitable in developing nations without continuously operating electric power lines, Peace Corps volunteer and MIT engineenAmy Smith invented a low-cost, low-maintenance incubator to fill the need. The device consists of a foaminsulated box containing several packets of a waxy material that melts at \(37.0^{\circ} \mathrm{C}\), interspersed among tubes, dishes, or bottles containing the test samples and growth medium (food for bacteria). Outside the box, the waxy material is first melted by a stove or solar energy collector. Then it is put into the box to keep the test samples warm as it solidifies. The heat of fusion of the phasechange material is \(205 \mathrm{~kJ} / \mathrm{kg}\). Model the insulation as a panel with surface area \(0.490 \mathrm{~m}^{2}\), thickness \(9.50 \mathrm{~cm}\), and conductivity \(0.0120 \mathrm{~W} / \mathrm{m}^{\circ} \mathrm{C}\). Assume the exterior temperature is \(23.0^{\circ} \mathrm{C}\) for \(12.0 \mathrm{~h}\) and \(16.0^{\circ} \mathrm{C}\) for \(12.0 \mathrm{~h}\). (a) What mass of the waxy material is required to conduct the bacteriological test? (b) Explain why your calculation can be done without knowing the mass of the test samples or of the insulation.

8 A \(60.0\) -kg runner expends \(300 \mathrm{~W}\) of power while running a marathon. Assuming \(10.0 \%\) of the energy is deliyered to the muscle tissue and that the excess energy is removed from the body primarily by sweating, determine the volume of bodily fluid (assume it is water) lost per hour. (At \(37,0^{\circ} \mathrm{C}\), the latent heat of vaporization of water is \(\left.2.41 \times 10^{6} \mathrm{~J} / \mathrm{kg} .\right)\)

A Styrofoam box has a surface area of \(0.80 \mathrm{~m}^{2}\) and a wall thickness of \(2.0 \mathrm{~cm}\). The temperature of the inner surface is \(5.0^{\circ} \mathrm{C}\), and the outside temperature is \(25^{\circ} \mathrm{C}\). If it takes \(8.0 \mathrm{~h}\) for \(5.0 \mathrm{~kg}\) of ice to melt in the container, determine the thermal conductivity of the Styrofoam.

A \(200-\mathrm{g}\) aluminum cup contains \(800 \mathrm{~g}\) of water in thermal equilibrium with the cup at \(80^{\circ} \mathrm{C}\). The combination of cup and water is cooled uniformly so that the temperature decreases by \(1.5^{\circ} \mathrm{C}\) per minute. At what rate is energy being removed? Express your answer in watts.

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