/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 GP In the summer of 1958 in St. ... [FREE SOLUTION] | 91Ó°ÊÓ

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GP In the summer of 1958 in St. Petersburg, Florida, a new sidewalk was poured near the childhood home of one of the authors. No expansion joints were supplied, and by mid-July the sidewalk had been completely destroyed by thermal expansion and had to be replaced, this time with the important addition of expansion joints! This event is modeled here. A slab of concrete \(4.00 \mathrm{~cm}\) thick, \(1.00 \mathrm{~m}\) long, and \(1 \leq 00 \mathrm{~m}\) wide is poured for a sidewalk at an ambient temperature of \(25.0^{\circ} \mathrm{C}\) and allowed to set. The slab is exposed to direct sunlight and placed in a series of such slabs without proper expansion joints, so linear expansion is prevented. (a) Using the linear expansion equation (Eq. \(10.4)\), eliminate \(\Delta I\). from the equation for compressive stress and strain (Eq. 9.3). (b) Use the expression found in part (a) to eliminate \(\Delta T\) from Equation \(11.3\), obtain ing a symbolic equation for thermal energy transfer \(Q\). (c) Compute the mass of the concrete slab given that its density is \(2.40 \times 10^{5} \mathrm{~kg} / \mathrm{m}^{3}\). (d) Concrete has an ultimate compressive strength of \(2.00 \times 10^{7} \mathrm{~Pa}\), specific heat of \(880 \mathrm{~J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\), and Young's modulus of \(2.1 \times 10^{10} \mathrm{~Pa}\). How much thermal energy must be transferred to the slab to reach this compressive stress? (e) What temperature change is required? (f) If the sun delivers \(1.00 \times 10^{3} \mathrm{~W}\) of power to the top surface of the slab and if half the energy, on the average, is absorbed and retained, how long does it Lake the slab to reach the point at which it is in danger of cracking due to compressive stress?

Short Answer

Expert verified
First, the mass of the concrete slab is computed to be \(9600 kg\). The equation for thermal energy transfer, after substitutions, is \(Q = \frac{ \sigma L m}{\alpha Y}\), where \(\sigma\) is ultimate compressive stress, L is length of slab, m is mass, \(\alpha\) is the coefficient of linear expansion, and Y is Young's modulus. From computations, the thermal energy required to cause dangerous crack is found to be \(8.68 \times 10^{10} J\), and the corresponding temperature change is found to be \(22.5 °C\). The time it takes for the slab to reach this dangerous temperature is found to be around \(174,400 s or 48.4 hours\).

Step by step solution

01

Compute mass from given density and volume

Using the formula for volume and given density, calculate the mass of the concrete slab.\nThe formula for volume of a rectangular cuboid is \(length \times width \times height\). So, volume would be \(1.00 m \times 1.00 m \times 0.04 m = 0.04 m^3\).\nMass is \(density \times volume\), given the density as \(2.40 \times 10^5 kg/m^3\), we can multiply with the volume to get mass of the slab, \(m = density \times volume\).
02

Substitute equations to find thermal energy transfer equation

By substituting the linear expansion equation to find the compressive strain, and then use that to substitute in place of the change in temperature in the equation for thermal energy transfer. Linear expansion equation is \(\Delta L = L \times \alpha \times \Delta T\), compressive strain is \(- \Delta L / L\), and thermal energy transfer \(Q = m \cdot c \cdot \Delta T\), where m is mass, c is specific heat, and \(\Delta T\) is change in temperature.
03

Calculate thermal energy needed and corresponding temperature change

Use the compressive stress (ultimate compressive strength) to solve for thermal energy by substituting in the obtained equation from step 2.\nSubstitute this value in the equation for thermal energy transfer to find the change in temperature.
04

Calculate the time for slab to reach dangerous temperature

Given the power delivered by the sun and the energy retention, find the actual energy absorbed in one second, which is a watt.\nThen, divide the total required thermal energy by the energy absorbed per second to find the time it takes for the slab to reach dangerous temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compressive Stress
Compressive stress is a critical concept in understanding how materials respond to force. It occurs when a material is subjected to axial load that pushes it together, causing it to shorten. This type of stress is described by how much force is applied over an area with the formula:
\[ \text{Compressive Stress} = \frac{F}{A} \]where:
  • \( F \) is the force applied
  • \( A \) is the area of the cross-section
In contexts like concrete slabs, if the thermal expansion of the slab is constrained, like in the exercise, compressive stress builds up, potentially leading to cracking or failure if the material's compressive strength is exceeded. This underscores the importance of accommodating thermal expansion in building design, such as by adding expansion joints to prevent the accumulation of stress.
Linear Expansion Equation
The linear expansion equation helps predict how much a material will expand or contract when the temperature changes. It is critical for materials like concrete, which can undergo significant changes due to environmental conditions. The formula is given by:
\[ \Delta L = L \times \alpha \times \Delta T \]where:
  • \( \Delta L \) is the change in length
  • \( L \) is the original length of the material
  • \( \alpha \) is the coefficient of linear expansion
  • \( \Delta T \) is the change in temperature
Using this equation, engineers can predict how structural elements like beams and slabs will behave under different temperatures, ensuring that structures remain safe and intact through various weather conditions. In the exercise, the slab's inability to expand due to lack of joints leads to increased compressive stress.
Thermal Energy Transfer
Understanding thermal energy transfer is essential for calculating how much energy is needed to change a material's temperature. This concept embodies how energy is absorbed or released as heat, affecting the temperature of the material. The formula used is:
\[ Q = m \cdot c \cdot \Delta T \]where:
  • \( Q \) is the thermal energy
  • \( m \) is the mass of the material
  • \( c \) is the specific heat capacity
  • \( \Delta T \) is the change in temperature
In the context of the exercise, it’s crucial for calculating how much energy, due to solar exposure, causes the slab to reach a point where it might crack. The absorption of too much energy without the capacity to expand leads to increased danger of stress beyond the material's limit, requiring careful calculation and preventative measures.
Young's Modulus
Young's Modulus is a measure of a material's stiffness or rigidity and is a fundamental concept in understanding material deformation. It quantifies the relationship between stress (force per unit area) and strain (deformation in the material). The formula is:
\[ E = \frac{\text{stress}}{\text{strain}} \]where:
  • \( E \) is Young’s Modulus
  • Stress is the force applied
  • Strain is the resultant deformation
Young's Modulus provides a valuable understanding of how a material like concrete will behave when subjected to forces, affecting its ability to recover its original shape after deforming. In the exercise, a high Young's Modulus of concrete indicates it does not easily deform under stress, which, combined with squeeze from thermal expansion, can lead to cracking without adequate accommodations like expansion joints.

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Most popular questions from this chapter

A class of 10 students taking an exam has a power output per student of about \(200 \mathrm{~W}\). Assume the initial temperature of the room is \(20^{\circ} \mathrm{C}\) and that its dimensions are \(6.0 \mathrm{~m}\) by \(15.0 \mathrm{~m}\) by \(3.0 \mathrm{~m}\). What is the temperature of the room at the end of \(1.0 \mathrm{~h}\) if all the energy remains in the air in the room and none is added by an outside source? The specific heat of air is \(837 \mathrm{~J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\), and its density is about \(1.3 \times 10^{-3} \mathrm{~g} / \mathrm{cm}^{3}\)

\(\mathrm{A}\) solar sail is made of aluminized Mylar having an emissivity of \(0.03\) and reflecting \(97 \%\) of the light that falls on it. Suppose a sail with area \(1.00 \mathrm{~km}^{2}\) is oriented so that sunlight falls perpendicular to its surface with an intensity of \(1.40 \times 10^{3} \mathrm{~W} / \mathrm{m}^{2}\). To what temperature will it warm before it emits as much energy (from both sides) by radiation as it absorbs on the sunny side? Assume the sail is so thin that the temperature is uniform and no energy is emitted from the edges. Take the environment to be \(0 \mathrm{~K}\).

The apparatus shown in Figure \(\mathrm{P} 11.10\) was used by Joule to measure the mechanical equivalent of heat. Work is done on the water by a rotating paddle wheel, which is driven by two blocks falling at a constant speed. The temperature of the stirred water increases due to the friction between the water and the paddles. If the energy lost in the bearings and through the walls is neglected, then the loss in potential energy associated with the blocks equals the work done by the paddle wheel on the water, If each block has a mass of \(1.50 \mathrm{~kg}\) and the insulated tank is filled with \(200 \mathrm{~g}\) of water, what is the increase in temperature of the water after the blocks fall through a distance of \(3.00 \mathrm{~m}\) ?

A Styrofoam box has a surface area of \(0.80 \mathrm{~m}^{2}\) and a wall thickness of \(2.0 \mathrm{~cm}\). The temperature of the inner surface is \(5.0^{\circ} \mathrm{C}\), and the outside temperature is \(25^{\circ} \mathrm{C}\). If it takes \(8.0 \mathrm{~h}\) for \(5.0 \mathrm{~kg}\) of ice to melt in the container, determine the thermal conductivity of the Styrofoam.

[8 The excess internal energy of metabolism is exhausted through a variery of channels, such as through radiation and evaporation of perspiration. Consider another pathway for energy loss: moisture in exhaled breath. Suppose you breathe out \(22.0\) breaths per minute, each with a volume of \(0.600 \mathrm{~L}\). Suppose also that you inhale dry air and exhale air at \(37^{\circ} \mathrm{C}\) containing water vapor with a vapor pressure of \(3.20 \mathrm{kPa}\). The vapor comes from the evaporation of liquid water in your body. Model the water vapor as an ideal gas. Assume its latent heat of evaporation at \(37^{\circ} \mathrm{C}\) is the same as its heat of vaporization at \(100^{\circ} \mathrm{C}\). Calculate the rate at which you lose energy by exhaling humid air.

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