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Onc mole of oxygen gas is at a pressure of \(6.00 \mathrm{~atm}\) and a temperature of \(27.0^{\circ} \mathrm{C}\). (a) If the gas is heated at constant volume until the pressure triples, what is the final temperature? (b) If the gas is heated so that both the pressure and volume are doubled, what is the final temperature?

Short Answer

Expert verified
The final temperature when the pressure triples is 900.45 K and when both the pressure and volume doubles, the final temperature is 1200.6 K.

Step by step solution

01

Calculation of Initial Temperature in Kelvin

To work with the Ideal Gas Law, the temperature needs to be in Kelvin. The conversion from Celsius to Kelvin is: \( T(K) = T(^\circ C) + 273.15 \). Therefore, the initial temperature, \( T_1 \), is \( 27.0^\circ C + 273.15 = 300.15 K \).
02

Calculation of Final Temperature When Pressure Triples

Since the volume is constant, we can write the Ideal Gas Laws for each state as follows: \( P_1 \times V = nRT_1 \) and \( P_2 \times V = nRT_2 \). Dividing these two equations we get: \( T_2 = \frac{P_2}{P_1} \times T_1 \). Given that \( P_2 = 3 P_1 \), we have \( \frac{3 P_1}{P_1} \times 300.15 K = 900.45 K \).
03

Calculation of Final Temperature When Both Pressure and Volume are Doubled

The new Ideal Gas Law is given by: \( P_2 \times V_2 = nRT_2 \). Substituting \( P_2 = 2P_1 \) and \( V_2 = 2V_1 \) into the equation, we get: \( 2P_1 \times 2V_1 = nRT_2 \rightarrow 4nRT_1 = nRT_2 \) Therefore, \( T_2 = 4T_1 = 4 \times 300.15K = 1200.6 K \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Temperature conversion
Understanding the methods of temperature conversion is essential when working with the Ideal Gas Law, as it requires temperatures in the Kelvin scale. Celsius and Fahrenheit are the other common scales used in various regions and applications. The Kelvin scale, however, is the SI unit for temperature and is commonly used in physics due to its direct relationship with thermal energy, where zero Kelvin (0 K) indicates absolute zero, the point at which no more thermal energy can be removed from a system.

As seen in the exercise, to convert temperature from Celsius to Kelvin, one must add 273.15 to the Celsius temperature. This is represented with the equation: T(K) = T(^#176;C) + 273.15 .This conversion ensures that all temperature dependent calculations are accurate and comply with the standard scientific unit of measurement for thermodynamic temperature.
Thermodynamics
The field of thermodynamics explores the principles governing the conversion of energy from one form to another, the direction of heat transfer, and the relationships between heat and work. One of the fundamental laws of thermodynamics is the conservation of energy, which assures us that energy can neither be created nor destroyed in an isolated system.

Thermodynamics encompasses several laws, but one of the most pertinent to our exercise is the first law, which involves the Ideal Gas Law. This law relates several thermodynamic quantities: pressure (P), volume (V), number of moles (n), the universal gas constant (R), and temperature (T), which must be in Kelvin for accuracy. The law is represented by the equation: PV = nRT . Here, we see the interdependence of these variables; if you know three, you can solve for the fourth. Understanding these relationships allows us to predict how a given quantity of gas will react to changes in temperature, pressure, or volume.
Pressure-volume relationship
The pressure-volume relationship is a key aspect of gas laws and thermodynamics. It describes how pressure (P) and volume (V) change in relation to each other when temperature and the number of gas particles are held constant. This relationship is highlighted in Boyle's Law, which states that pressure and volume are inversely proportional to each other in a closed system at constant temperature.

However, when considering temperature changes, as in the Ideal Gas Law, we must look at Charles's Law, which states that volume and temperature are directly proportional to each other at constant pressure. In the exercise provided, we applied the Ideal Gas Law in different ways to find the final temperature of the gas. When the pressure was tripled at constant volume, the final temperature also increased. In contrast, when both the pressure and volume were doubled, the final temperature quadrupled, indicating a direct relationship between pressure and volume when temperature varies. This helps students to grasp the significance of the manipulation of these variables within the context of the Ideal Gas Law.

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Most popular questions from this chapter

The ideal gas law can be recast in terms of the density of a gas. (a) Use dimensional analysis to find an expression for the density \(\rho\) of a gas in terms of the number of moles \(n_{1}\) the volume \(V_{1}\) and the molecular weight \(M\) in kilograms per mole. (b) With the expression found in part (a), show that $$ P=\frac{\rho}{M} R T $$ for an ideal gas. (c) Find the density of the carbon dioxide atmosphere at the surface of Venus, where the pressure is \(90.0\) atm and the temperature is \(7.00 \times 10^{2} \mathrm{~K}\). (d) Would an evacuated steel shell of radius \(1.00 \mathrm{~m}\) and mass \(2.00 \times\) \(10^{2} \mathrm{~kg}\) rise or fall in such an atmosphere? Why?

Gas is confined in a tank at a pressure of \(11.0 \mathrm{~atm}\) and a temperature of \(25.0^{\circ} \mathrm{C}\). If two thirds of the gas is withdrawn and the temperature is raised to \(75.0^{\circ} \mathrm{C}\), what is the new pressure in the tank?

The density of helium gas at \(T=0^{\circ} \mathrm{C}\) is \(\rho_{o}=0.179 \mathrm{~kg} / \mathrm{m}^{3}\). The temperature is then raised to \(T=100^{\circ} \mathrm{C}\), but the pres sure is kept constant. Assuming the helium is an ideal gas, calculate the new density \(\rho_{f}\) of the gas.

Death Valley holds the record for the highest recorded temperature in the United States. On July 10, 1913 , at at place called Fumace Creek Ranch, the temperature rose to \(134^{\circ} \mathrm{F}\). The lowest U.S. temperature ever recorded occurred at Prospect Creek Camp in Alaska on January 23,1971, when the temperature plummeted to \(-79.8^{\circ}\) F. (a) Convert these temperatures to the Celsius scale. (b) Convert the Cielsius temperatures to Kelvin.

Two small containers, each with a volume of \(100 \mathrm{~cm}^{3}\), contain helium gas at \(0^{-} \mathrm{C}\) and \(1.00\) atm pressure. The two containers are joined by a small open tube of negligible volume, allowing gas to flow from one container to the other. What common pressure will exist in the two containers if the temperature of one container is raised to \(100^{\circ} \mathrm{C}\) while the other container is kept at \(0^{\circ} \mathrm{C}\) ?

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