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A solid substance has a density \(\rho_{0}\) at a temperature \(T_{0}\). If its temperature is increased by an amount \(\Delta T\), show that its density at the higher temperature is given by $$ \rho=\frac{\rho_{0}}{1+\beta \Delta T} $$

Short Answer

Expert verified
The density of a solid substance at a higher temperature can be given by \(蟻 = \frac{蟻_{0}}{1 + \beta 鈭員}\), where \( 蟻_{0} \) is the initial density, \( 鈭員 \) is the change in temperature, and \( \beta \) is the thermal coefficient of volume expansion.

Step by step solution

01

Understand the concept of Volume Expansion

When bodies are heated, they usually expand. When the temperature change is small, this expansion can be considered linear. However, an object doesn鈥檛 just extend in one direction, it expands in all of them, which means its volume increases. This is called volume expansion. The volume expansion is commonly described by the formula \(V = V_{0}*(1 + \beta 鈭員)\), where \( V_{0} \) is the initial volume, \( 鈭員 \) is the change in temperature, and \( \beta \) is the coefficient of volume expansion.
02

Apply the density formula

Since density (蟻) is defined as mass divided by volume, at an initial temperature \(T_{0}\) we have \(蟻_{0} = \frac{m}{V_{0}}\), where m is the mass and \(V_{0}\) is the volume at \(T_{0}\). At a higher temperature, the volume expands to V and the density becomes 蟻 = \(\frac{m}{V}\).
03

Substituting and Rearranging

We substitute \(V_{0}*(1 + \beta 鈭員)\) for V in the formula: \(蟻 = \frac{m}{V_{0}*(1 + \beta 鈭員)}\). We then multiply the numerator and denominator by \( \frac{1}{V_{0}} \) to get \(蟻 = \frac{\frac{m}{V_{0}}}{1 + \beta 鈭員}\). As \( 蟻_{0} = \frac{m}{V_{0}} \), the formula becomes: \(蟻 = \frac{蟻_{0}}{1 + \beta 鈭員}\), which is the required equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a fundamental concept in physics, indicating how much mass is contained in a given volume of a substance. It's expressed mathematically as \( \rho = \frac{m}{V} \), where \( \rho \) represents density, \( m \) is mass, and \( V \) is volume. When considering the thermal expansion of materials, understanding changes in density is crucial.

When a material is heated, it generally expands, meaning its volume increases while the mass remains the same. This causes the density to decrease because the same amount of matter is now spread over a larger area.
  • Initial Density: At the initial temperature \( T_{0} \), the density is \( \rho_{0} = \frac{m}{V_{0}} \).
  • Changed Density: At a higher temperature with expanded volume, density is recalculated by dividing mass by the new volume.
Understanding density in terms of volume expansion helps determine how substances behave with temperature changes, crucial for applications across science and engineering.
Coefficient of Volume Expansion
The coefficient of volume expansion, denoted by \( \beta \), characterizes how much a substance's volume changes with temperature. It varies depending on the material and is crucial when analyzing thermal expansion.

For solids that expand uniformly in all directions, the formula for volume expansion is \( V = V_{0}(1 + \beta \Delta T) \). \( \beta \) is a constant that tells us how sensitive a given material's volume is to temperature changes.
  • Formula Elements: \( V_{0} \) is the initial volume, \( \Delta T \) is the temperature change, and \( \beta \) provides a measure of volumetric sensitivity to temperature.
  • Predictive Use: Knowing \( \beta \) helps predict changes in material properties and engineering outcomes due to temperature variation.
The coefficient allows us to establish a direct relationship between temperature change and volume change, forming the base for further calculations involving thermal dynamics.
Temperature Change
Temperature change, \( \Delta T \), refers to the difference between the initial and final temperatures of a substance. This change is the driving force behind thermal expansion, affecting both volume and density.

In the context of thermal expansion, an increased temperature typically results in:
  • Volume Expansion: The initial volume \( V_{0} \) of the substance increases, influencing the overall density.
  • Density Decrease: As the volume expands, the same mass occupies a larger space, hence reducing the density \( \rho \).
Understanding \( \Delta T \) is essential in predicting how substances will react to heat, aiding in material design and safety assessments. This concept interrelates with the coefficient of volume expansion to model and calculate the effects realistically in materials.

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