/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 A certain corner of a room is se... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A certain corner of a room is selected as the origin of a rectangular coordinate system. If a fly is crawling on an adjacent wall at a point having coordinates \((2.0,1.0)\), where the units are meters, what is the distance of the fly from the corner of the room?

Short Answer

Expert verified
The distance of the fly from the corner of the room is approximately \(2.236\) meters.

Step by step solution

01

- Noting down the given coordinates

Note down the Cartesian coordinates of the fly on the wall. They are given as (2.0, 1.0) meters.
02

- Applying the Pythagorean theorem

To find out the distance of a point from the origin in a 2D coordinate system, we apply the Pythagorean theorem. The theorem calculates the hypotenuse of a right-angle triangle using the formula: \(\sqrt{{x}^{2} + {y}^{2}}\). Here, x=2.0m and y=1.0m , hence the distance can be calculated as \(\sqrt{{2.0}^{2} + {1.0}^{2}}\) meters.
03

- Calculation

Calculate the expression under the square root. This gives \(\sqrt{4.0 + 1.0} = \sqrt{5.0}\) meters. Then, calculate the square root of 5 .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rectangular Coordinate System
The rectangular coordinate system is the backbone of many physical and mathematical problems, providing a way to specify the location of points in a two-dimensional space. To visualize this, imagine a flat surface with two lines intersecting at right angles to each other. This intersection is called the origin, often designated as the point (0,0). The horizontal line is known as the x-axis, and the vertical line is called the y-axis.

In this system, the position of any point can be identified with a pair of numerical coordinates, which are the distances from the point to the two perpendicular axes. For instance, in our exercise of the fly on the wall, the coordinates (2.0, 1.0) represent the fly's position relative to the corner of the room, with 2.0 meters away along the x-axis (horizontal direction), and 1.0 meter up along the y-axis (vertical direction). The beauty of this system is that it allows us not only to find the location of points but also to perform various calculations, such as distances or displacements, with relative ease.
Distance Calculation
Distance calculation is a fundamental concept in physics, and it's one where the Pythagorean theorem shines. According to the theorem, in a right-angled triangle, the square of the length of the hypotenuse (the side opposite to the right angle) is equal to the sum of the squares of the lengths of the other two sides. To put it simply, if we have a triangle with side lengths of 'a', 'b', and 'c', where 'c' is the hypotenuse, the Pythagorean theorem tells us that: \[c = \sqrt{a^2 + b^2}\].

This equation is particularly useful in a rectangular coordinate system when we want to calculate the straight-line distance between two points, or from a point to the origin. In the case of the fly on the wall, we apply this theorem with 'a' and 'b' being the distances from the fly to the axes—2.0 meters along the x-axis and 1.0 meter along the y-axis—and 'c' being the distance we wish to find. By substituting the values into the Pythagorean theorem, we efficiently calculate the fly's distance from the origin.
2D Coordinate System
The Rectangular Coordinate System gets simplified to a 2D coordinate system when applied in two spatial dimensions, which means that only two axes (x and y) are used for specifying the location of points. This system is widely utilized, not only in physics but also in various fields like engineering, navigation, and even computer graphics.

The 2D coordinate system makes it easier to map out the physical world onto a plane. When we discuss the fly on the wall, we are actually applying the principles of a 2D coordinate system to measure the distance in a plane—the wall in this case—with the corner of the room serving as the reference origin. By doing this, we simplify the three-dimensional problem into a more manageable two-dimensional one, making the calculation more straightforward.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Compute the order of magnitude of the mass of (a) a bathtub filled with water and (b) a bathtub filled with pennies. In your solution, list the quantities you estimate and the value you estimate for each.

The period of a simple pendulum, defined as the time necessary for one complete oscillation, is measured in time units and is given by $$T=2 \pi \sqrt{\frac{\ell}{g}}$$ where \(\ell\) is the length of the pendulum and \(g\) is the acceleration due to gravity, in units of length divided by time squared. Show that this equation is dimensionally consistent. (You might want to check the formula using your keys at the end of a string and a stopwatch.)

Two points in a rectangular coordinate system have the coordinates \((5.0,3.0)\) and \((-3.0,4.0)\), where the units are centimeters. Determine the distance between these points:

(a) How many seconds are there in a year? (b) If one micrometeorite (a sphere with a diameter on the order of \(10^{-6} \mathrm{~m}\) ) struck each square meter of the Moon each second, estimate the number of years it would take to cover the Moon with micrometeorites to a depth of one meter. (Hint: Consider a cubic box, \(1 \mathrm{~m}\) on a side, on the Moon, and find how long it would take to fill the box.)

A woman measures the angle of elevation of a mountaintop as \(12.0^{\circ}\). After walking \(1.00 \mathrm{~km}\) closer to the mountain on level ground, she finds the angle to be \(14.0^{\circ} .\) (a) Draw a picture of the problem, neglecting the height of the woman's eyes above the ground. Hint: Use two triangles. (b) Select variable names for the mountain height (suggestion: \(y\) ) and the woman's original distance from the mountain (suggestion: \(x\) ) and label the picture. (c) Using the labeled picture and the tangent function, write two trigonometric equations relating the two sclected variables. (d) Find the height \(y\) of the mountain by first solving one equation for \(x\) and substituting the result into the other equation.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.