/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 A furlong is an old British unit... [FREE SOLUTION] | 91Ó°ÊÓ

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A furlong is an old British unit of length equal to \(0.125 \mathrm{mi}\), derived from the length of a furrow in an acre of ploughed land. A fortnight is a unit of time corresponding to two weeks, or 14 days and nights. Find the speed of light in megafurlongs per fortmight. (One megafurlong equals a million furlongs.)

Short Answer

Expert verified
The speed of light is approximately \(1802619180 \, megafurlongs/fortnight\).

Step by step solution

01

Convert the Speed of Light to miles per second

The speed of light is approximately \(299792 \, km/s\). To convert this to miles per second, the conversion factor \(1 \, mile = 1.60934 \, km\) is to be used. Thus, the speed of light is approximately \(299792/1.60934 ≈ 186282 \, mile/s\).
02

Convert miles per second to furlongs per second

As given, a furlong is equivalent to \(0.125 \, miles\). Thus, by converting miles to furlongs, the speed of light will be approximately \(186282/0.125 = 1490256 \, furlongs/s\).
03

Convert seconds to fortnights

One fortnight is equivalent to \(1209600 \, seconds\) (14 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute). Therefore, the speed of light can be converted to furlongs per fortnight by multiplying the previous result by the number of seconds in a fortnight, yielding \(1490256*1209600 ≈ 1802619180000 \, furlongs/fortnight\).
04

Convert to megafurlongs per fortnight

To convert the speed of light from furlongs per fortnight to megafurlongs per fortnight (where 1 megafurlong = \(10^6\) furlongs), simply divide the previous result by \(10^6\). This gives a final result of approximately \(1802619180000/10^6 = 1802619180 \, megafurlongs/fortnight\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Understanding unit conversion is essential when dealing with measurements from different systems, such as converting the speed of light, a scientific measurement typically given in meters per second, into more novel units like megafurlongs per fortnight. A unit conversion involves using a conversion factor, a ratio that expresses how many of one unit are equivalent to another.
For the speed of light conversion, you would start by expressing it in a common unit like miles per second, and then break it down into the target units step by step. When performing these conversions, ensure to accurately use the conversion factors, such as knowing that 1 mile equals 1.60934 kilometers or that 1 furlong is 0.125 miles. This arithmetic process can be made clearer and easier by explicitly stating each conversion factor used and proceeding in a single dimension at a time, to avoid confusion.
Speed of Light
The speed of light is a fundamental constant in physics, denoting the speed at which light travels in a vacuum. It's typically recorded as approximately 299,792 kilometers per second (km/s). Understanding the vastness of this value can be daunting, so comparing it to more comprehensible units can help grasp its magnitude.
For instance, when you learn that light can travel around the Earth nearly 7.5 times in just one second, it gives a sense of perspective. In our textbook problem, when the speed of light is converted into the unusual unit of megafurlongs per fortnight, it doesn't change the speed itself but rather offers a creative way to express this astronomical figure within a different context, perhaps making it more relatable or memorable.
Dimensional Analysis
Dimensional analysis is a powerful tool used in physics and engineering to check the validity of equations and to convert between different units of measurement. It involves treating units of measure as algebraic quantities, which can cancel out or combine to give new units. This technique allows complex unit conversions to be handled systematically.
doing dimensional analysis, it's crucial to consistently multiply or divide all relevant units, and to ensure that the units we end with match the units we need. The last part of our exercise illustrates this well. After finding the speed of light in furlongs per fortnight, dimensional analysis demands one final step: dividing by a million (or multiplying by the micro conversion factor) to adjust from furlongs to megafurlongs, perfectly showcasing how this method is used to solve real-world problems and enhance understanding of units in various contexts.

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Most popular questions from this chapter

(a) How many seconds are there in a year? (b) If one micrometeorite (a sphere with a diameter on the order of \(10^{-6} \mathrm{~m}\) ) struck each square meter of the Moon each second, estimate the number of years it would take to cover the Moon with micrometeorites to a depth of one meter. (Hint: Consider a cubic box, \(1 \mathrm{~m}\) on a side, on the Moon, and find how long it would take to fill the box.)

(a) Using your calculator, find, in scientific notation with appropriate rounding, (a) the value of \(\left(2.437 \times 10^{4}\right)\) \(\left(6.5211 \times 10^{9}\right) /\left(5.37 \times 10^{4}\right)\) and (b) the value of \(\left(3.14159 \times 10^{2}\right)\left(27.01 \times 10^{4}\right) /\left(1234 \times 10^{6}\right)\)

(a) Find a conversion factor to convert from miles per hour to kilometers per hour. (b) For a while, federal law mandated that the maximum highway speed would be 55 \(\mathrm{mi} / \mathrm{h}\). Use the conversion factor from part (a) to find the speed in kilometers per hour, (c) The maximum highway speed has been raised to \(65 \mathrm{mi} / \mathrm{h}\) in some places. In kilometers per hour, how much of an increase is this over the \(55-\mathrm{mi} / \mathrm{h}\) limit?

A point is located in a polar coordinate system by the coordinates \(r=2.5 \mathrm{~m}\) and \(\theta=35^{\circ}\). Find the \(x\) - and \(y\) coordinates of this point, assuming that the two coordinate systems have the same origin.

(a) About how many microorganisms are found in the human intestinal tract? (A typical bacterial length scale is \(10^{-6} \mathrm{~m}\). Estimate the intestinal volume and assume one hundredth of it is occupied by bacteria.) (b) Discuss your answer to part (a). Are these bacteria beneficial, dangerous, or neutral? What finctions could they serve?

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