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A river has a steady speed of 0.500 m/s. A student swims upstream a distance of 1.00 km and swims back to the starting point. If the student can swim at a speed of 1.20 m/s in still water, how long does the trip take? Compare this with the time the trip would take if the water were still.

Short Answer

Expert verified
The total trip time with the river current is 2016.81 seconds, whereas the trip would take 1666.67 seconds if the water were still.

Step by step solution

01

Calculate the effective speed upstream

When swimming upstream, the water's speed reduces the swimmer's effective speed. Calculate the effective speed by subtracting the river speed from the swimmer's speed in still water: Effective speed upstream = swimmer's speed - river speed. So, Effective speed upstream = 1.20 m/s - 0.500 m/s = 0.700 m/s.
02

Calculate the time taken to swim upstream

Time taken to swim a certain distance is the distance divided by speed. Time upstream = Distance upstream / Effective speed upstream. So, Time upstream = 1000 m / 0.700 m/s = 1428.57 s.
03

Calculate the effective speed downstream

When swimming downstream, the river's speed adds to the swimmer's speed. Calculate the effective speed by adding the river speed to the swimmer's speed in still water: Effective speed downstream = swimmer's speed + river speed. So, Effective speed downstream = 1.20 m/s + 0.500 m/s = 1.70 m/s.
04

Calculate the time taken to swim downstream

Time downstream = Distance downstream / Effective speed downstream. So, Time downstream = 1000 m / 1.70 m/s = 588.24 s.
05

Calculate the total trip time

Total trip time is the sum of the time taken to swim upstream and the time taken to swim downstream. So, Total trip time = Time upstream + Time downstream = 1428.57 s + 588.24 s = 2016.81 s.
06

Calculate the time taken for the trip in still water

If the water were still, the swimmer's speed would be constant at 1.20 m/s both ways. Time in still water for one way = Distance / Swimmer's still water speed. So, Time for one way = 1000 m / 1.20 m/s = 833.33 s, and for the round trip, Time in still water = 833.33 s * 2 = 1666.67 s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Velocity
Understanding relative velocity is crucial when analyzing motion in a fluid, such as swimming in a river. It refers to how the speed of one object appears from the perspective of another moving object. In our exercise, the student's swimming speed in still water is different from their speed in a moving river.

When the student swims upstream, we observe their motion relative to the shore. However, the river's current opposes the swimmer, effectively reducing their speed. In physics, we calculate the student's effective speed upstream by subtracting the river's velocity from the swimmer's velocity in still water, which is \(v_{effective, upstream} = v_{swimmer} - v_{river}\).

Conversely, when swimming downstream, the river's current aids the swimmer, increasing their effective speed. It's a classic relative velocity situation: \(v_{effective, downstream} = v_{swimmer} + v_{river}\). This application of relative velocity helps in critical problem-solving involving motion in fluids where two velocities interact.
Effective Speed Calculation
The concept of effective speed is essential in situations where different velocities combine to affect the actual speed of an object. For the swimming exercise, we calculate the effective speed for both swimming upstream and downstream. This is the swimmer's actual speed relative to the riverbank.

Upstream, the swimmer labors against the current, which results in \(v_{effective, upstream} = 1.20 m/s - 0.500 m/s = 0.700 m/s\). Downstream, the current assists the swimmer, giving an effective speed of \(v_{effective, downstream} = 1.20 m/s + 0.500 m/s = 1.70 m/s\).

The tracking of effective speed in each direction enables us to understand the impact of external factors, like current, on the swimmer's performance and time calculations. This calculation is a perfect demonstration of how environmental conditions modify the capabilities of movers within a medium, such as air or water.
Time and Distance Analysis
Analyzing time and distance in the context of motion involves a straightforward formula: \(time = \frac{distance}{speed}\). Applying this to our scenario, after calculating the effective speeds, we use them to determine the total time the swimmer takes to cover the distances upstream and downstream.

For the upstream swim, time is found by dividing the distance (1.00 km or 1000 m) by the effective speed upstream (\(time_{upstream} = \frac{1000 m}{0.700 m/s} = 1428.57 s\)). Similarly, for the downstream swim, the calculation is \(time_{downstream} = \frac{1000 m}{1.70 m/s} = 588.24 s\).

To get the total trip time, we simply add the times for both directions, resulting in a comprehensive understanding of the journey's duration. If the water was still, the total time would instead be twice the time taken for one direction at constant speed (\(time_{still water} = 2 \times \frac{1000 m}{1.20 m/s} = 1666.67 s\)), showcasing how currents impact the overall time taken for a swimmer to complete a route.

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