/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 When the Sun is directly overhea... [FREE SOLUTION] | 91Ó°ÊÓ

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When the Sun is directly overhead, a hawk dives toward the ground with a constant velocity of 5.00 \(\mathrm{m} / \mathrm{s}\) at \(60.0^{\circ}\) below the horizontal. Calculate the speed of her shadow on the level ground.

Short Answer

Expert verified
The speed of the hawk's shadow on the ground is 2.50 m/s.

Step by step solution

01

Understand the problem

The hawk is diving with a velocity of 5.00 m/s at a 60-degree angle below horizontal. We need to determine the horizontal component of this velocity, as it represents the speed of the shadow on the ground.
02

Calculate the horizontal component of the velocity

To find the horizontal component of the hawk's velocity (which is the same as the shadow's speed), we use the cosine of the angle. The formula is: horizontal velocity = total velocity * cos(angle). Since the angle given is below horizontal, we will still use the cosine for the horizontal component.
03

Apply the cosine function to determine the shadow's speed

Substitute the given values into the formula: horizontal velocity = 5.00 m/s * cos(60.0 degrees). Use a calculator to find cos(60.0 degrees), which is 0.5. So, horizontal velocity = 5.00 m/s * 0.5.
04

Calculate the final velocity

Multiplying the total velocity by the cosine of the angle gives the horizontal velocity: horizontal velocity = 5.00 m/s * 0.5 = 2.50 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Velocity
Horizontal velocity is a crucial concept when it comes to understanding motion in two dimensions, especially in physics problems involving projectiles or similar scenarios. In our case, we look at the hawk's shadow speed, which is represented by the horizontal component of the bird's dive velocity. This is because the shadow moves along the ground, maintaining a consistent pace with the hawk's position horizontally.

When an object moves at an angle to the horizontal, such as the hawk's dive, its velocity can be split into two components: horizontal and vertical. The horizontal velocity remains constant if air resistance is negligible. To calculate these components, trigonometry becomes a handy tool, breaking down the angled flight path into a right-angled triangle. We'll see that trigonometric functions are particularly essential when deriving these components for the hawk's dive and, by extension, for various physics problems involving angled motion.
Angle of Projection
The angle of projection is the angle at which an object is launched, kicked, thrown, or in our scenario, in which the hawk dives relative to the horizontal. This angle is crucial because it directly affects the trajectory and landing point of the moving object. In the case of our hawk, it determines how the velocity is divided between horizontal and vertical directions.

When the hawk dives at a 60-degree angle below the horizontal, this specific angle influences how fast the shadow cast by the hawk moves across the ground. The steeper the angle (closer to vertical), the slower the shadow will move horizontally; conversely, the shallower the angle (closer to horizontal), the faster the shadow will move. Understanding the impact of the angle of projection helps us predict not just the shadow's speed, but also the nature of the object's motion in a broader context of physics problems.
Cosine Function
The cosine function is a cornerstone of trigonometry and is essential in calculating the horizontal component of an angled velocity. In our exercise, we utilize the cosine function to determine the speed at which the hawk's shadow moves across the ground. Defined as the adjacent side over the hypotenuse in a right-angled triangle, the cosine function offers a relationship between the angle and the lengths of the triangle’s sides.

Applying the cosine function to our problem, we calculate the horizontal component by multiplying the hawk's velocity (the hypotenuse in our imaginary right-angled triangle) by the cosine of the dive angle. By doing this, we leverage the consistent mathematical relationship provided by the cosine function to give us the precise horizontal speed of the shadow. Since this is a fundamental application used in many physics problems, grasping the concept of using cosine to find a horizontal velocity can greatly enhance a student’s problem-solving skills in trigonometry and physics.

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Most popular questions from this chapter

Young David who slew Goliath experimented with slings before tackling the giant. He found that he could revolve a sling of length 0.600 m at the rate of 8.00 rev/s. If he increased the length to 0.900 m, he could revolve the sling only 6.00 times per second. (a) Which rate of rotation gives the greater speed for the stone at the end of the sling? (b) What is the centripetal acceleration of the stone at 8.00 rev/s? (c) What is the centripetal acceleration at 6.00 rev/s?

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