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Consider electrons accelerated to an energy of 20.0 GeV in the \(3.00-\mathrm{km}\) -long Stanford Linear Accelerator. (a) What is the \(\gamma\) factor for the electrons? (b) What is their speed? (c) How long does the accelerator appear to them?

Short Answer

Expert verified
\(\gamma \approx 39196.9\), Speed \(v \approx c\), Length of the accelerator as perceived by the electrons \(L' \approx 76.6 \text{ m}\)

Step by step solution

01

Calculate the \(\gamma\) factor

The \(\gamma\) factor can be calculated using the relativistic equation \(\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\), where \(v\) is the velocity of the electron and \(c\) is the speed of light. Since the energy of the electron is given, we can relate it to \(\gamma\) by using \(E = \gamma m c^2\), where \(E = 20.0 \text{ GeV}\) (or \(20.0 \times 10^9 \text{ eV}\)) and \(m\) is the rest mass of an electron \(m = 0.511 \text{ MeV}/c^2\). Solving for \(\gamma\) gives us \(\gamma = \frac{E}{mc^2} = \frac{20.0 \times 10^9 \text{ eV}}{0.511 \times 10^6 \text{ eV}/c^2}\).
02

Calculate the speed of the electrons

After calculating \(\gamma\), we can determine \(v\) by rearranging the \(\gamma\) factor equation to solve for \(v\): \(v = c \sqrt{1-\frac{1}{\gamma^2}}\). We plug the value of \(\gamma\) obtained from Step 1 into this equation to calculate the speed.
03

Determine the length of the accelerator as perceived by the electrons

To find the length of the accelerator as perceived by the electrons, use the length contraction formula \(L' = L \sqrt{1-\frac{v^2}{c^2}}\), where \(L'\) is the contracted length, \(L = 3.00 \text{ km}\) is the proper length, and \(v\) is the speed of the electrons from Step 2. The term \(\sqrt{1-\frac{v^2}{c^2}}\) is the same as \(\frac{1}{\gamma}\), so \(L' = \frac{L}{\gamma}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gamma Factor
In the realm of relativistic physics, the gamma factor, denoted as \( \gamma \) plays a pivotal role when describing the behavior of objects moving at speeds close to that of light. It emerges from the need to adjust our classical understanding of time, space, and energy to accommodate the constant speed of light across all inertial frames of reference—a cornerstone of Einstein's theory of relativity.

The mathematical expression for the gamma factor is \( \gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}} \) where \( v \) represents the velocity of the object and \( c \) is the speed of light in vacuum, approximately \( 3.00 \times 10^8 \text{ m/s} \). As the velocity of an object increases and gets closer to the speed of light, the gamma factor increases. At velocities much lower than the speed of light, \( \gamma \) approaches 1, meaning relativistic effects are negligible. However, as demonstrated in textbook problems where electrons are accelerated to high energies, the gamma factor can become significant and is key in calculating other relativistic effects such as time dilation and length contraction.
Speed of Light
The speed of light, symbolized as \( c \) and equal to approximately \( 3.00 \times 10^8 \text{ meters per second} (\text{m/s}) \), is a fundamental constant of nature and sits at the heart of special relativity. It's not just the speed at which light travels; it's also the maximum speed at which all energy, matter, and information in the universe can travel.

According to Einstein's theory, no matter how fast you are moving, light always travels at the same speed when measured in your frame of reference. This constancy of \( c \) leads to intuitive contradictions with our everyday experiences and necessitates a reevaluation of time and space measures, manifested in phenomena such as length contraction and time dilation, which only become evident at speeds approaching \( c \). These insights revolutionized physics and led to the understanding of the universe in the framework of space-time, emphasizing the interconnectivity of space and time.
Length Contraction
Length contraction is a mind-bending yet essential consequence of special relativity. It predicts that objects moving at a significant fraction of the speed of light will measure shorter along the direction of motion in the frame of reference of an observer at rest relative to the object. The formula that governs this physical phenomenon is \( L' = L \sqrt{1-\frac{v^2}{c^2}} \) where \( L' \) is the contracted length, \( L \) is the proper length (the length of the object as measured in the object's rest frame), and \( v \) is the speed of the object.

The appearance of the \( \gamma \) factor within this context is not coincidental. Given that \( \gamma \) is equal to \( \frac{1}{\sqrt{1-\frac{v^2}{c^2}}} \) it's clear \( L' \) can also be written as \( \frac{L}{\gamma} \). Hence, an object's observed length decreases as the speed increases, and significantly so as one reaches relativistic speeds. This concept has practical implications in high-energy physics, such as understanding how the internal components of particle accelerators appear to subatomic particles whizzing through them at near-light speeds.

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Most popular questions from this chapter

The creation and study of new elementary particles is an important part of contemporary physics. Especially interesting is the discovery of a very massive particle. To create a particle of mass \(M\) requires an energy \(M c^{2} .\) With enough energy, an exotic particle can be created by allowing a fast moving particle of ordinary matter, such as a proton, to collide with a similar target particle. Let us consider a perfectly inelastic collision between two protons: an incident proton with mass \(m_{p},\) kinetic energy \(K,\) and momentum magnitude \(p\) joins with an originally stationary target proton to form a single product particle of mass \(M .\) You might think that the creation of a new product particle, nine times more massive than in a previous experiment, would require just nine times more energy for the incident proton. Unfortunately not all of the kinetic energy of the incoming proton is available to create the product particle, since conservation of momentum requires that after the collision the system as a whole still must have some kinetic energy. Only a fraction of the energy of the incident particle is thus available to create a new particle creation depends on the energy of the moving proton. Show that the energy available to create a product particle is given by $$ M c^{2}=2 m_{p} c^{2} \sqrt{1+\frac{K}{2 m_{p} c^{2}}} $$ From this result, when the kinetic energy \(K\) of the incident proton is large compared to its rest energy \(m_{p} c^{\prime},\) we see that \(M\) approaches \(\left(2 m_{p} K\right)^{1 / 2} / c\) . Thus if the energy of the incoming proton is increased by a factor of nine, the mass you can create increases only by a factor of three. This disappointing result is the main reason that most modern accelerators, such as those at CERN (in Europe), at Fermi- lab (near Chicago), at SLAC (at Stanford), and at DESY (in Germany), use colliding beams. Here the total momentum of a pair of interacting particles can be zero. The center of mass can be at rest after the collision, so in principle all of the initial kinetic energy can be used for particle creation, according to $$ M c^{2}=2 m c^{2}+K=2 m c^{2}\left(1+\frac{K}{2 m c^{2}}\right) $$ where \(K\) is the total kinetic energy of two identical colliding particles. Here if \(K>>m c^{2},\) we have \(M\) directly proportional to \(K,\) as we would desire. These machines are difficult to build and to operate, but they open new vistas in physics.

In a laboratory frame of reference, an observer notes that Newton's second law is valid. Show that it is also valid for an observer moving at a constant speed, small compared with the speed of light, relative to the laboratory frame.

The red shift. A light source recedes from an observer with a speed \(v_{\text { source }}\) that is small compared with \(c .\) (a) Show that the fractional shift in the measured wavelength is given by the approximate expression $$ \frac{\Delta \lambda}{\lambda} \approx \frac{v_{\text { source }}}{c} $$ This phenomenon is known as the red shift, because the visible light is shifted toward the red. (b) Spectroscopic measurements of light at \(\lambda=397 \mathrm{nm}\) coming from a galaxy in Ursa Major reveal a red shift of \(20.0 \mathrm{nm} .\) What is the recessional speed of the galaxy?

Police radar detects the speed of a car (Fig. P39.19) as follows. Microwaves of a precisely known frequency are broadcast toward the car. The moving car reflects the microwaves with a Doppler shift. The reflected waves are received and combined with an attenuated version of the transmitted wave. Beats occur between the two microwave signals. The beat frequency is measured. (a) For an electromagnetic wave reflected back to its source from a mirror approaching at speed \(v,\) show that the reflected wave has frequency $$ f=f_{\text { source }} \frac{c+v}{c-v} $$ where \(f_{\text { source }}\) is the source frequency. (b) When \(v\) is much less than \(c,\) the beat frequency is much smaller than the transmitted frequency. In this case use the approximation \(f+f_{\text { source }} \approx 2 f_{\text { source }}\) and show that the beat frequency can be written as \(f_{\text { beat }}\) \(=2 v / \lambda .\) (c) What beat frequency is measured for a car speed of 30.0 \(\mathrm{m} / \mathrm{s}\) if the microwaves have frequency 10.0 \(\mathrm{GHz}\) ? (d) If the beat frequency measurement is accurate to \(\pm 5 \mathrm{Hz},\) how accurate is the velocity measurement?

A ball is thrown at 20.0 \(\mathrm{m} / \mathrm{s}\) inside a boxcar moving along the tracks at 40.0 \(\mathrm{m} / \mathrm{s}\) . What is the speed of the ball relative to the ground if the ball is thrown (a) forward (b) backward (c) out the side door?

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