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The nonrelativistic expression for the momentum of a particle, \(p=m u,\) agrees with experiment if \(u<

Short Answer

Expert verified
The speed that gives a 1.00% error in momentum is \(u = c \sqrt{1 - (1.01)^{-2}}\), and the speed that gives a 10.0% error is \(u = c \sqrt{1 - (1.10)^{-2}}\).

Step by step solution

01

Identify the relativistic momentum formula

Momentum in the relativistic case is given by the formula \(p = \frac{m u}{\sqrt{1-\frac{u^2}{c^2}}}\). We need to compare this formula with the nonrelativistic formula \(p = m u\) to find the speed \(u\) that results in the specified errors.
02

Calculate the speed for a 1.00% error in momentum

An error of 1.00% means the relativistic momentum is 1.01 times the nonrelativistic momentum. We set up the equation \(\frac{m u}{\sqrt{1-\frac{u^2}{c^2}}} = 1.01 \cdot m u\) and solve for \(u\).
03

Solve the equation for the speed resulting in 1.00% error

After simplifying the equation from Step 2, we get \(\sqrt{1-\frac{u^2}{c^2}} = \frac{1}{1.01}\). Solving for \(u\), we obtain \(u = c \sqrt{1 - (1.01)^{-2}}\).
04

Calculate the speed for a 10.0% error in momentum

Following the same procedure, for a 10.0% error, we have the equation \(\frac{m u}{\sqrt{1-\frac{u^2}{c^2}}} = 1.10 \cdot m u\). By solving this equation, we can find the speed that gives a 10.0% error.
05

Solve the equation for the speed resulting in 10.0% error

Solving the equation \(\sqrt{1-\frac{u^2}{c^2}} = \frac{1}{1.10}\), we find \(u = c \sqrt{1 - (1.10)^{-2}}\) for the speed that gives a 10.0% error in momentum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonrelativistic Momentum
When we study the motion of objects at speeds much less than the speed of light, we use the principles of classical mechanics, which are part of a broader theme known as nonrelativistic physics. One of the fundamental concepts in this area is nonrelativistic momentum, which serves as a measure of an object's motion. We often define the momentum (represented by the symbol p) of a particle as the product of its mass m and its velocity u, expressed by the simple equation p = m u.

This equation suggests that momentum is directly proportional to both mass and velocity—a more massive or faster-moving object will carry more momentum. However, as velocity approaches a significant fraction of the speed of light, this simplistic definition fails to hold true. In educational contexts, it's essential to comprehend this straightforward concept first, to then grasp why and how it evolves when we move into the realm of relativistic physics.
Speed of Light
In physics, the speed of light (c) is a critical universal constant and sets a limit on how fast information or matter can travel through space. The speed of light is approximately 299,792,458 meters per second. In the context of momentum, the speed of light is not just a speed cap but also a demarcation line between nonrelativistic (everyday speeds) and relativistic speeds (speeds close to c).

When objects move at a significant fraction of c, we observe deviations from the predictions of classical mechanics, like time dilation and length contraction. Understanding the speed of light is crucial both for theoretical insights and practical applications, such as plotting satellite orbits or synchronizing GPS systems.
Relativistic Physics
The realm of relativistic physics, championed by Albert Einstein's theory of relativity, modifies our understanding of motion when dealing with objects traveling at speeds close to c. It introduces the concept of relativistic momentum, where the classical definition p = m u gets replaced by a more complex equation that takes into account the Lorentz factor—\frac{1}{\(1-\frac{u^2}{c^2}\)^{\frac{1}{2}}}. The relativistic momentum expression is p = \frac{m u}{\sqrt{1-\frac{u^2}{c^2}}}. This takes into account the effects of relativistic speeds on mass and time.

The key takeaway here is that the faster an object moves, the more pronounced the effects of relativity become, leading to an increase in momentum that's not linear with speed, unlike the nonrelativistic scenario. This topic is profound as it underpins the workings of particle accelerators and the behavior of cosmic particles.
Momentum Error Calculation
Whenever we measure and calculate momentum at speeds approaching the speed of light, we must account for potential errors arising from using nonrelativistic formulas. Accurately calculating such errors is critical when precision is essential, like in experimental physics or engineering. For instance, the problem at hand requires finding at what velocities the use of the nonrelativistic equation gives an error in the momentum of 1.00% and 10.0%.

To perform this momentum error calculation, the relativistic momentum is compared to the nonrelativistic momentum, and the discrepancies are expressed as percentages. By setting up and solving equations with error percentages factored in, one can find the specific velocities at which these errors occur. This process helps foster a deeper understanding of the transition between classical and relativistic mechanics, and is fundamental for students as they explore realms wherein every fraction of a percent can lead to dramatically different outcomes.

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Most popular questions from this chapter

Police radar detects the speed of a car (Fig. P39.19) as follows. Microwaves of a precisely known frequency are broadcast toward the car. The moving car reflects the microwaves with a Doppler shift. The reflected waves are received and combined with an attenuated version of the transmitted wave. Beats occur between the two microwave signals. The beat frequency is measured. (a) For an electromagnetic wave reflected back to its source from a mirror approaching at speed \(v,\) show that the reflected wave has frequency $$ f=f_{\text { source }} \frac{c+v}{c-v} $$ where \(f_{\text { source }}\) is the source frequency. (b) When \(v\) is much less than \(c,\) the beat frequency is much smaller than the transmitted frequency. In this case use the approximation \(f+f_{\text { source }} \approx 2 f_{\text { source }}\) and show that the beat frequency can be written as \(f_{\text { beat }}\) \(=2 v / \lambda .\) (c) What beat frequency is measured for a car speed of 30.0 \(\mathrm{m} / \mathrm{s}\) if the microwaves have frequency 10.0 \(\mathrm{GHz}\) ? (d) If the beat frequency measurement is accurate to \(\pm 5 \mathrm{Hz},\) how accurate is the velocity measurement?

A particle of mass \(m\) moving along the \(x\) axis with a velocity component \(+u\) collides head-on and sticks to a particle of mass \(m / 3\) moving along the \(x\) axis with the velocity component \(-u\) . What is the mass \(M\) of the resulting particle?

A physics professor on the Earth gives an exam to her students, who are in a spacecraft traveling at speed \(v\) relative to the Earth. The moment the craft passes the professor, she signals the start of the exam. She wishes her students to have a time interval \(T_{0}\) (spacecraft time) to complete the exam. Show that should wait a time interval (Earth time) of $$ T=T_{0} \sqrt{\frac{1-v / c}{1+v / c}} $$ before sending a light signal telling them to stop. (Suggestion: Remember that it takes some time for the second light signal to travel from the professor to the students.)

Prepare a graph of the relativistic kinetic energy and the classical kinetic energy, both as a function of speed, for an object with a mass of your choice. At what speed does the classical kinetic energy underestimate the experimental value by 1\(\%\) ? by 5\(\%\) ? by 50\(\%\) ?

When 1.00 g of hydrogen combines with 8.00 g of oxygen, 9.00 g of water is formed. During this chemical reaction, \(2.86 \times 10^{5} \mathrm{J}\) of energy is released. How much mass do the constituents of this reaction lose? Is the loss of mass likely to be detectable?

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