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A 30 -turn circular coil of radius 4.00 \(\mathrm{cm}\) and resistance 1.00\(\Omega\) is placed in a magnetic field directed perpendicular to the plane of the coil. The magnitude of the magnetic field varies in time according to the expression \(B=0.0100 t+0.0400 t^{2},\) where \(t\) is in seconds and \(B\) is in tesla. Calculate the induced emf in the coil at \(t=5.00\) s.

Short Answer

Expert verified
The induced emf in the coil at t = 5.00 s is -0.28274 V.

Step by step solution

01

Calculate the Magnetic Flux

To find the induced emf, first calculate the magnetic flux through the coil. Magnetic flux (\(\Phi\)) is given by the product of the magnetic field (B), the area of the coil (A), and the cosine of the angle (\(\theta\)) between the field and the normal to the coil's plane. Since the field is perpendicular to the coil, \(\theta = 0\) degrees, and \(\cos(\theta) = 1\). The area of the coil is \(A = \pi r^2\), where r is the radius. Therefore, the magnetic flux is \[\Phi = B * A = B * \pi * r^2 = (0.0100t + 0.0400t^2) * \pi * (0.04)^2\] because the radius is 4.00 cm or 0.04 m.
02

Calculate the Time Derivative of the Magnetic Flux

The induced emf (\(\varepsilon\)) in the coil is defined by Faraday's law, which states that the induced emf is equal to the negative of the time rate of change of magnetic flux through the coil. Mathematically, \[\varepsilon = -\frac{d\Phi}{dt}\]. Substitute the expression for \(\Phi\) into Faraday's law and differentiate with respect to time t to find \(\varepsilon\). \[\varepsilon = -\frac{d}{dt}[(0.0100t + 0.0400t^2) * \pi * (0.04)^2]\]
03

Evaluate the Induced emf at t = 5.00s

To find the induced emf at t = 5.00 s, plug t = 5.00s into the differentiated expression from Step 2. First, calculate the derivative: \[\frac{d}{dt}(0.0100t + 0.0400t^2) = 0.0100 + 2 * 0.0400 * t\]. Then plug in t = 5.00 s: \[\varepsilon = -\pi * (0.04)^2 * (0.0100 + 2 * 0.0400 * 5.00)\].Solve this expression to find the induced emf at t = 5.00 s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Imagine a flat surface, like a piece of paper, and a magnetic field passing perpendicularly through it. Magnetic flux represents the quantity of magnetic field lines penetrating this surface. To calculate it, we use the formula \[\Phi = B \times A \times \text{cos}(\theta)\], where \(\Phi\) is the magnetic flux, \(B\) is the magnetic field strength, \(A\) is the area through which the field lines pass, and \(\theta\) is the angle between the magnetic field and the normal (perpendicular) to the area. For a coil perpendicular to the magnetic field, \(\theta\) is 0 degrees, simplifying the calculation since \(\cos(0)\) equals 1. When working with a circular coil, the area \(A\) is given by \(\pi r^2\), where \(r\) is the radius of the coil.

In our exercise, with the known radius and magnetic field as a function of time, we can express the magnetic flux at any instant using the specified variables.
Faraday's Law of Electromagnetic Induction
Faraday's Law forms the cornerstone of electromagnetism, revealing the interaction between changing magnetic fields and electric circuits. The law states that an electromotive force (also known as emf or \(\varepsilon\)) is induced in a coil when the magnetic flux through the coil changes over time. This principle is used in many technologies, such as generators and transformers. Mathematically, Faraday's Law is expressed as
\[\varepsilon = -\frac{d\Phi}{dt}\]
with \(\varepsilon\) being the induced emf, \(\Phi\) the magnetic flux, and \(\frac{d\Phi}{dt}\) representing the time derivative of magnetic flux. The negative sign indicates the direction of the induced emf, which, according to Lenz's Law, opposes the change in flux— a concept known as 'the law of conservation of energy'.
Circular Coil
A circular coil, such as the one described in our exercise, is a loop or series of loops of wire, often wound concentrically, forming a circular shape. These coils are an essential component in many electromagnetic devices. The behavior of a coil in a magnetic field is governed by Faraday's Law, through which an emf can be induced in the coil by a changing magnetic field.

The coil's properties, including the number of turns and radius, significantly influence the induced emf; these relationships are quantified through the equations that govern magnetic flux and Faraday's Law. For a coil with multiple turns, the induced emf for each turn adds together, making the total emf proportional to the number of turns in the coil.
Time Derivative of Magnetic Flux
When dealing with Faraday's Law of Electromagnetic Induction, we often encounter the concept of the time derivative of magnetic flux, denoted as \(\frac{d\Phi}{dt}\). This term describes how quickly the magnetic flux through the coil is changing with respect to time; in other words, it's the rate of change of the magnetic flux.

In practical terms, calculating the time derivative requires us to differentiate the magnetic flux \(\Phi\) with respect to time \(t\). If the magnetic flux is expressed as a function of time – as it is in our exercise with \(\Phi(t) = (0.0100t + 0.0400t^2) \times \pi \times (0.04)^2\) – then we apply the differentiation rules to find the function that describes the induced emf over time. In turn, this allows us to calculate the instantaneous value of the induced emf at any given moment, such as at \(t = 5.00\) seconds.

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Most popular questions from this chapter

A 25 -turn circular coil of wire has diameter \(1.00 \mathrm{m} .\) It is placed with its axis along the direction of the Earth's magnetic field of 50.0\(\mu \mathrm{T}\) , and then in 0.200 \(\mathrm{s}\) it is flipped \(180^{\circ} .\) An average emf of what magnitude is generated in the coil?

A 50 -turn rectangular coil of dimensions \(5.00 \mathrm{cm} \times\) 10.0 \(\mathrm{cm}\) is allowed to fall from a position where \(B=0\) to a new position where \(B=0.500 \mathrm{T}\) and the magnetic field is directed perpendicular to the plane of the coil. Calculate the magnitude of the average emf that is induced in the coil if the displacement occurs in 0.250 \(\mathrm{s}\) .

A long solenoid, with its axis along the \(x\) axis, consists of 200 turns per meter of wire that carries a steady current of 15.0 \(\mathrm{A}\) . A coil is formed by wrapping 30 turns of thin wire around a circular frame that has a radius of \(8.00 \mathrm{cm} .\) The coil is placed inside the solenoid and mounted on an axis that is a diameter of the coil and coincides with the \(y\) axis. The coil is then rotated with an angular speed of 4.00\(\pi \mathrm{rad} / \mathrm{s}\) . (The plane of the coil is in the \(y z\) plane at \(t=0 .\) Determine the emf generated in the coil as a function of time.

An automobile has a vertical radio antenna 1.20 \(\mathrm{m}\) long. The automobile travels at 65.0 \(\mathrm{km} / \mathrm{h}\) on a horizontal road where the Earth's magnetic field is 50.0\(\mu \mathrm{T}\) directed toward the north and downward at an angle of \(65.0^{\circ}\) below the horizontal. (a) Specify the direction that the automobile should move in order to generate the maximum motional emf in the antenna, with the top of the antenna positive relative to the bottom. (b) Calculate the magnitude of this induced emf.

A coil of area 0.100 \(\mathrm{m}^{2}\) is rotating at 60.0 \(\mathrm{rev} / \mathrm{s}\) with the axis of rotation perpendicular to a 0.200 - T magnetic field. ( a) If the coil has 1000 turns, what is the maximum emf generated in it? (b) What is the orientation of the coil with respect to the magnetic field when the maximum induced voltage occurs?

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