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The inner conductor of a coaxial cable has a radius of 0.800 \(\mathrm{mm}\) , and the outer conductor's inside radius is 3.00 \(\mathrm{mm}\) . The space between the conductors is filled with polyethylene, which has a dielectric constant of 2.30 and a dielectric strength of \(18.0 \times 10^{6} \mathrm{V} / \mathrm{m}\) . What is the maximum potential difference that this cable can withstand?

Short Answer

Expert verified
The maximum potential difference is \(V_{max} = E \cdot (r_{o} - r_{i})\).

Step by step solution

01

Determine the Maximum Electric Field

The dielectric strength of the material gives us the maximum electric field (E) that it can experience without breaking down. For polyethylene, the dielectric strength is given as 18 MV/m, hence, the maximum electric field is \(E = 18.0 \times 10^{6} \, \mathrm{V/m}\).
02

Calculate the Maximum Potential Difference

To find the maximum potential difference that the cable can withstand across the dielectric, you can use the formula for the electric field in a coaxial cable: \(E = \frac{V}{d}\). In this case, \(d\) is the difference in the radii of the inner and outer conductors. Convert the radii from mm to meters, calculate \(d\), and rearrange the formula to solve for \(V\): \(V = E \cdot d\).
03

Perform the Calculations

First, convert the radii from mm to meters: inner radius \(r_{i} = 0.800 \times 10^{-3} \) meters and outer radius \(r_{o} = 3.00 \times 10^{-3} \) meters. Find the difference in the radii \(d = r_{o} - r_{i}\). Then, use the maximum electric field to find \(V\), the maximum potential difference: \(V_{max} = E \cdot d\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Electric Field
An electric field is a vector field that surrounds electrically charged objects. It represents the force that would be exerted on other electric charges if placed in the vicinity of the field. The strength of this field is contingent upon the amount of charge on the source object and inversely proportional to the square of the distance from the source charge. In the context of a coaxial cable, the electric field exists between the inner and outer conductors. The magnitude of this field, denoted by the symbol \( E \), can be calculated using the formula \( E = \frac{V}{d} \), where \( V \) is the potential difference and \( d \) is the separation between the conductors.

Understanding the electric field inside a coaxial cable is crucial. It determines the operational parameters, such as the way the cable transmits electrical signals and the maximum voltage it can safely carry. When the field exceeds a certain threshold, known as the dielectric strength, the insulating material can break down, which may cause the cable to fail. Therefore, electric field analysis is fundamental to ensure co to avoid any disruptive discharges.
Dielectric Strength and Cable Design
The dielectric strength of a material is the maximum electric field strength that the material can withstand without experiencing electrical breakdown. This is a key property, especially in the design of electrical insulators, as it determines how much electric stress the material can tolerate before it becomes conductive. It is expressed in units of volts per meter (V/m).

For example, polyethylene, commonly used as an insulating material in coaxial cables, has a specified dielectric strength that must not be exceeded to prevent damage. As per the exercise, polyethylene's dielectric strength is \(18.0 \times 10^{6}\,\text{V/m}\) which means that within the coaxial cable, the electric field must be less than \(18.0 \times 10^{6}\,\text{V/m}\) to prevent any breakdown of the insulating layer. Knowledge of a material's dielectric strength is critical for engineers to ensure the long-term reliability and safety of electrical systems, particularly in regions of high electric stress.
Coaxial Cable Capacitance
The capacitance of a coaxial cable is a measure of its ability to store electric charge per unit voltage difference applied between its conductors. The capacitance is determined by the physical properties of the cable, such as the dielectric constant of the insulating material, and the geometrical factors including the radii of the inner and outer conductors and the distance between them.

For a typical coaxial cable capacitor, the capacitance \( C \) can be calculated using the formula \( C = \frac{2\pi\varepsilon_0 \varepsilon_r}{\ln(\frac{r_o}{r_i})} \), where \( \varepsilon_0 \) is the permittivity of free space, \( \varepsilon_r \) is the relative permittivity (dielectric constant) of the insulator, \( r_i \) is the inner conductor radius, and \( r_o \) is the outer conductor radius. In the exercise, the coaxial cable has a dielectric constant of 2.30, indicating the effectiveness of polyethylene in storing charge compared to the vacuum.

This capacitance impacts not only the charge storage but also the transmission properties, including signal speed and impedance. Understanding and calculating the capacitance are vital for the design and functioning of coaxial cables in various applications, such as in telecommunications and networking.

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Most popular questions from this chapter

A 1 -megabit computer memory chip contains many \(60.0-\mathrm{fF}\) capacitors. Each capacitor has a plate area of \(21.0 \times 10^{-12} \mathrm{m}^{2} .\) Determine the plate separation of such a capacitor (assume a parallel-plate configuration). The order of magnitude of the diameter of an atom is \(10^{-10} \mathrm{m}=0.1 \mathrm{nm} .\) Express the plate separation in nanometers.

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