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Two identical parallel-plate capacitors, each with capacitance \(C,\) are charged to potential difference \(\Delta V\) and connected in parallel. Then the plate separation in one of the capacitors is doubled. (a) Find the total energy of the system of two capacitors before the plate separation is doubled. (b) Find the potential difference across each capacitor after the plate separation is doubled. (c) Find the total energy of the system after the plate separation is doubled. (d) Reconcile the difference in the answers to parts (a) and (c) with the law of conservation of energy.

Short Answer

Expert verified
The initial total energy is \(U_{\text{initial}} = C(\Delta V)^2\). After doubling the plate separation, the potential difference across the altered capacitor is \(2\Delta V\) and the final total energy remains \(U_{\text{final}} = C(\Delta V)^2\). The law of conservation of energy is not violated since mechanical work was done to double the plate separation.

Step by step solution

01

Calculate Initial Energy of the System

The energy stored in a single capacitor is given by \(E = \frac{1}{2}CV^2\). Since there are two identical capacitors connected in parallel, each with capacitance \(C\) and potential difference \(\Delta V\), the total initial energy of the system is \(U_{\text{initial}} = 2 \times \frac{1}{2}C(\Delta V)^2\).
02

Determine the Potential Difference after Plate Separation is Doubled

For the capacitor with doubled plate separation, the capacitance becomes \(C' = \frac{C}{2}\) because capacitance is inversely proportional to plate separation for a parallel-plate capacitor. The charge on this capacitor remains the same because it is isolated after being charged. The new potential difference across this capacitor is \(V' = \frac{Q}{C'} = \frac{Q}{\frac{C}{2}} = 2 \times \frac{Q}{C} = 2 \Delta V\), where \(Q = C \Delta V\) is the initial charge on each capacitor.
03

Calculate the New Total Energy of the System

The energy of the capacitor with unchanged separation remains \(\frac{1}{2}C(\Delta V)^2\). The energy of the capacitor with doubled separation is \(\frac{1}{2}C'V'^2 = \frac{1}{2}\left(\frac{C}{2}\right)(2\Delta V)^2 = \frac{1}{2}C(\Delta V)^2\). Therefore, the total energy after the change is \(U_{\text{final}} = \frac{1}{2}C(\Delta V)^2 + \frac{1}{2}C(\Delta V)^2 = C(\Delta V)^2\).
04

Reconcile with the Law of Conservation of Energy

The initial total energy is \(U_{\text{initial}} = C(\Delta V)^2\) and the final total energy is also \(U_{\text{final}} = C(\Delta V)^2\). The energy remains the same before and after the plate separation is doubled, which is in accordance with the law of conservation of energy. However, a mechanical work is done in the process of separating one of the plates which compensates for the potential energy that appeared to be 'lost' when only looking at the capacitors.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parallel-Plate Capacitor
A parallel-plate capacitor is a device that stores electrical energy in an electric field created between two conductive plates separated by an insulating material known as a dielectric. The plates are charged to a certain potential difference, which results in an accumulation of positive charge on one plate and negative charge on the opposite plate.

The simplicity of its design makes the parallel-plate capacitor a staple in explaining the fundamental concepts of capacitance and electrostatics. When discussing exercises or problems involving these capacitors, it is essential to grasp how physical changes to the capacitor, such as modifying plate separation, impact its ability to store charge and energy.

Effectively, as seen in our exercise, when the plate separation is doubled, for one of the capacitors, we witness a direct impact on its capacitance and thus, its stored energy. This conceptual understanding helps students visualize and comprehend the changes in the system's behavior when physical alterations occur.
Capacitance
Capacitance is a measure of a capacitor's ability to store charge per unit potential difference across its plates and is denoted by the symbol \(C\). It is mathematically expressed as \(C = \frac{Q}{\Delta V}\), where \(Q\) is the charge stored and \(\Delta V\) is the potential difference across the capacitor.

The capacitance of a parallel-plate capacitor is directly proportional to the surface area of the plates and inversely proportional to the distance between them. When the distance between plates is doubled as in our exercise, the capacitance is halved. Understanding this relationship is fundamental when analyzing scenarios where changes occur in the physical dimensions of a capacitor.

For a parallel-plate capacitor specifically, the capacitance can be calculated using the formula \(C = \frac{\epsilon_0 A}{d}\), where \(\epsilon_0\) is the vacuum permittivity, \(A\) is the area of one plate, and \(d\) is the separation between plates. A delicate understanding of this concept ensures that students can navigate through problems that involve modifications to the capacitance of a system.
Potential Difference
Potential difference, also known as voltage, is an electrical quantity that measures the energy difference per unit charge between two points in an electric field. In the context of capacitors, the potential difference \(\Delta V\) across the plates dictates how much energy is stored in the electric field of the capacitor.

The formula for energy in a capacitor, \(E = \frac{1}{2}CV^2\), clearly indicates that energy depends on the square of the potential difference. When the plate separation of the capacitor in our exercise is doubled, students must clearly understand that the capacitance changes and thus affects the potential difference if the stored charge remains constant. This nuanced understanding is vital for comprehending the behavior of electric circuits and the energy transformations within them.

Grasping the concept of potential difference is also crucial for understanding electric circuit behavior, as changes in voltage can dramatically affect current flow and energy distribution within the components.
Conservation of Energy
The law of conservation of energy states that energy cannot be created or destroyed in an isolated system, it can only be transformed from one form to another. This fundamental law applies to all areas of physics, including electrodynamics and specifically, capacitor systems, as seen in the exercise.

In our scenario, the initial and final energy calculations of the capacitor system show an apparent discrepancy that can confuse students. However, this difference is reconciled when considering that mechanical work is done to separate the plates, and this work is essentially converted into electrical potential energy within the system, thus upholding the principle of energy conservation.

Through detailed exploration of this principle, students not only resolve mathematical puzzles but also deepen their understanding of physical processes. Recognizing the conservation of energy as a universal truth allows students to confidently approach problems involving complex energy changes and ensures a solid foundation for studying advanced topics in physics.

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