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On a Strange temperature scale, the freezing point of water is \(-15.0^{\circ} \mathrm{S}\) and the boiling point is \(+60.0^{\circ} \mathrm{S}\) . Develop a linear conversion equation between this temperature scale and the Celsius scale.

Short Answer

Expert verified
The conversion equation from the Strange temperature scale (S) to Celsius (C) is \( C = \frac{4}{3}S + 20 \).

Step by step solution

01

Identify Known Points on both Scales

First, determine the freezing and boiling points of water on both the Strange (S) scale and the Celsius (C) scale. For Celsius, these are 0°°ä and 100°°ä, and for the Strange scale, these are -15.0°S and +60.0°S respectively.
02

Establish Linear Relationship

Set up a system of equations to represent the linear relationship between the Strange scale (S) and the Celsius scale (C). We can use the general form of a linear equation: \( C = mS + b \), where \( m \) is the scale factor and \( b \) is the offset.
03

Utilize Freezing Points to Find the Equation

Using the freezing points of water, substitute \( C = 0 \) when \( S = -15.0 \) into the equation to get the first equation \( 0 = m(-15.0) + b \).
04

Utilize Boiling Points to Find the Equation

Using the boiling points of water, substitute \( C = 100 \) when \( S = 60.0 \) into the equation to get the second equation \( 100 = m(60.0) + b \).
05

Solve for Scale Factor \( m \) and Offset \( b \)

Solve the system of equations simultaneously to find the values of \( m \) and \( b \).
06

Calculate the Scale Factor \( m \)

Subtract the first equation from the second to eliminate \( b \) and solve for \( m \): \( 100 - 0 = m(60.0 + 15.0) \), which simplifies to \( m = \frac{100}{75} = \frac{4}{3} \).
07

Calculate the Offset \( b \)

Now substitute the value of \( m \) back into any of the original equations to find \( b \). Using the first equation: \( 0 = \frac{4}{3}(-15.0) + b \) leads to \( b = 20 \).
08

Write the Final Conversion Equation

Substitute the found values of \( m \) and \( b \) back into the general form of the linear equation \( C = mS + b \) to obtain the final conversion equation between the Strange scale and the Celsius scale: \( C = \frac{4}{3}S + 20 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Conversion Equation
Understanding the linear conversion equation is fundamental when comparing different temperature scales. It's a formula that allows us to convert a temperature value from one scale to another effectively. Essentially, it's a relation of the form C = mS + b, where C represents the temperature in Celsius, S is the temperature on a Strange scale, m is the scale factor, and b is the offset—these last two constants need to be determined using known reference points.

In our exercise, we first identified two fixed points common to all temperature scales: the freezing and boiling points of water. Next, we established a system of two equations using these points. By solving this system, we determined the scale factor m and the offset b, which are constant for any linear conversion between these two scales. Once these values are known, you can convert any temperature from the Strange scale to Celsius and vice versa using the derived equation.

When approaching similar problems, remember that it's all about finding those two constants. Think of m as how much faster or slower the temperatures rise on one scale compared to another, and b as the point where both scales coincide.
Celsius Scale
The Celsius scale, sometimes referred to as centigrade, is a temperature scale used by the International System of Units (SI). It is named after Anders Celsius, a Swedish astronomer. On this scale, the freezing point of water is set to 0°°ä and the boiling point at 100°°ä at sea level atmospheric pressure. This makes it intuitive as each degree change is equivalent to a 1% change between the freezing and boiling point of water.

It's crucial to understand that the Celsius scale is based on the properties of water, making it a very practical measurement in the scientific community and in daily life for most countries around the world. When performing exercises like the one we have just solved, using the Celsius scale as a reference point for conversion to or from other scales is often helpful because its fixed points are widely recognized.
Temperature Scale Relationships
Temperature scale relationships highlight how different scales correspond with one another. While some scales like Celsius and Fahrenheit are widely used, others can be purely hypothetical or created for specific purposes, like the Strange scale in our exercise. The relationship between different scales is not always linear, but when it is, as in the conversion from Strange to Celsius, a direct equation can be established to transition smoothly from one scale to another.

It's important to emphasize the understanding of temperature scale relationships as they not only help in the context of scientific calculation but also in everyday life – like adjusting cooking temperatures or when traveling to a country that uses a different scale. Remember, if you know the constants of your linear equation through a pair of reference points, you can establish a conversion for the entire scale range. This will help in many practical scenarios, such as recalibrating measuring devices or interpreting climate data.

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Most popular questions from this chapter

The pressure gauge on a tank registers the gauge pressure, which is the difference between the interior and exterior pressure. When the tank is full of oxygen \(\left(\mathrm{O}_{2}\right),\) it contains 12.0 \(\mathrm{kg}\) of the gas at a gauge pressure of \(40.0 \mathrm{atm} .\) Determine the mass of oxygen that has been withdrawn from the tank when the pressure reading is 25.0 atm. Assume that the temperature of the tank remains constant.

The mass of a hot-air balloon and its cargo (not including the air inside) is 200 \(\mathrm{kg}\) . The air outside is at \(10.0^{\circ} \mathrm{C}\) and 101 \(\mathrm{kPa}\) . The volume of the balloon is 400 \(\mathrm{m}^{3}\) . To what temperature must the air in the balloon be heated before the balloon will lift off? (Air density at \(10.0^{\circ} \mathrm{C}\) is \(1.25 \mathrm{kg} / \mathrm{m}^{3} . )\)

A popular brand of cola contains 6.50 g of carbon dioxide dissolved in 1.00 \(\mathrm{L}\) of soft drink. If the evaporating carbon dioxide is trapped in a cylinder at 1.00 \(\mathrm{atm}\) and \(20.0^{\circ} \mathrm{C},\) what volume does the gas occupy?

Each year thousands of children are badly burned by hot tap water. Figure \(\mathrm{P} 19.12\) shows a cross-sectional view of an antiscalding faucet attachment designed to prevent such accidents. Within the device, a spring made of material with a high coefficient of thermal expansion controls a movable plunger. When the water temperature rises above a preset safe value, the expansion of the spring causes the plunger to shut off the water flow. If the initial length \(L\) of the unstressed spring is 2.40 \(\mathrm{cm}\) and its coefficient of linear expansion is \(22.0 \times 10^{-6}\left(^{\circ} \mathrm{C}\right)^{-1}\) , determine the in- crease in length of the spring when the water temperature rises by \(30.0^{\circ} \mathrm{C}\) . (You will find the increase in length to be small. For this reason actual devices have a more complicated mechanical design, to provide a greater variation in valve opening for the temperature change anticipated.)

A constant-volume gas thermometer is calibrated in dry ice (that is, carbon dioxide in the solid state, which has a temperature of \(-80.0^{\circ} \mathrm{C} )\) and in boiling ethyl alcohol \(\left(78.0^{\circ} \mathrm{C}\right) .\) The two pressures are 0.900 \(\mathrm{atm}\) and 1.635 \(\mathrm{atm}\) . (a) What Celsius value of absolute zero does the calibration yield? What is the pressure at (b) the freezing point of water and (c) the boiling point of water?

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