/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 A bat, moving at 5.00 \(\mathrm{... [FREE SOLUTION] | 91Ó°ÊÓ

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A bat, moving at 5.00 \(\mathrm{m} / \mathrm{s}\) , is chasing a flying insect (Fig. Pl7.7). If the bat emits a 40.0 \(\mathrm{kHz}\) chirp and receives back an echo at 40.4 \(\mathrm{kHz}\) , at what speed is the insect moving toward or away from the bat? (Take the speed of sound in air to be \(v=340 \mathrm{m} / \mathrm{s} . )\)

Short Answer

Expert verified
The insect is moving away from the bat at approximately 2.35 m/s.

Step by step solution

01

- Determine the observed frequency increase

Calculate the increase in frequency of the echo received by the bat as the difference between the emitted frequency and the received frequency. Use the formula \( f' - f = \Delta f \) where \( f \) is the emitted frequency and \( f' \) is the received frequency.
02

- Calculate the Doppler shift for the stationary observer

Using the Doppler shift formula for a stationary observer and a moving source, calculate the velocity \( v_s \) of the source (insect). The formula is given by \( f' = f \left(\frac{v}{v - v_s}\right) \) where \( f' \) is the observed frequency, \( f \) is the emitted frequency, \( v \) is the speed of sound, and \( v_s \) is the velocity of the source.
03

- Solve for insect's speed

Rearrange the formula to solve for the source velocity \( v_s \). The rearranged formula is \( v_s = \frac{f'v - fv}{f} \) and then plug in the values \( f' = 40.4 kHz \) for the observed frequency, \( f = 40.0 kHz \) for the emitted frequency, and \( v = 340 \frac{m}{s} \) for the speed of sound to calculate \( v_s \) - the insect’s speed relative to the air.
04

- Determine the insect’s actual speed

Adjust for the bat's speed by adding the bat's velocity \( v_b \) to the relative speed of the insect \( v_s \) to find the actual speed \( v_i \) of the insect with respect to the bat. The bat is moving at \( v_b = 5 m/s \) toward the insect, so the insect's actual speed is \( v_i = v_s + v_b \) if the insect is moving away from the bat or \( v_i = v_s - v_b \) if the insect is moving toward the bat.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Doppler shift calculation
The Doppler effect, a common phenomenon in wave mechanics, occurs when a wave source and an observer are moving relative to one another. The perceived frequency of the sound changes due to this relative motion. The calculation of this frequency shift, known as the Doppler shift, hinges upon a set of variables: the speed of the source, the speed of the observer, the original emitted frequency, and the speed of sound through the medium.

To compute the Doppler shift for a sound wave, the formula \( f' = f\left(\frac{v \pm v_o}{v \mp v_s}\right) \) is used, where \( f' \) is the observed frequency, \( f \) is the emitted frequency, \( v \) is the speed of sound, \( v_o \) is the observer's velocity towards the source, and \( v_s \) is the source's velocity towards the observer. The plus or minus signs are chosen based on the direction of motion. This formula encapsulates the effect that relative motion has on wave frequency, and is essential for solving practical problems involving the Doppler effect, like predicting the behavior of a bat using echolocation to hunt.
Speed of sound
When discussing the Doppler effect, it's essential to consider the speed of sound, which is the velocity at which sound waves travel through a medium. The speed of sound is not constant; it varies with the medium and its properties, such as temperature, density, and molecular composition. In air at room temperature, the speed of sound is approximately \(340 \text{ m/s} \).

This value is fundamental for calculating Doppler shifts, as it serves as a frame of reference for determining how frequency changes relative to the motion of the source and observer. Accurate knowledge of the speed of sound is required to predict the resonant frequency shifts and for solving exercises like the textbook example with the bat and insect, where the consistent value of \(340 \text{ m/s} \) was used for calculations.
Frequency change
Frequency change is the alteration in the number of wave cycles that occur per second, as measured by an observer—in this case, due to the Doppler effect. The perceived frequency increases if the distance between the source and observer decreases, and it decreases when that distance grows.

In terms of the bat and insect scenario, the bat emits a chirp at a certain frequency and then detects an echo at a slightly different frequency. This difference, termed \( \Delta f \), is the change in frequency and is a direct outcome of the relative motion. By examining \( \Delta f \), we can deduce information about the velocity of the insect relative to the bat. The formula \( \Delta f = f' - f \) is vital for understanding how frequency shifts correlate to the movement of a wave source or observer.
Source velocity
Source velocity refers to the speed at which the source of waves—such as sound waves—is moving relative to a given medium. In Doppler effect discussions, this is key to understanding how the waves are perceived by an observer.

The textbook example showcased an insect moving relative to the air; this motion creates changes in the frequency of the echoes received by the bat. When the source (in this case, the insect) moves towards the observer (the bat), the waves seem to compress, leading to a higher perceived frequency. Conversely, if the source moves away, the waves appear stretched out, resulting in a lower frequency. The source velocity thus greatly influences the calculations for Doppler shifts, and determining its value can reveal the speed of objects like insects in motion, which is essential for animals utilizing echolocation. The final step of the provided solution adjusts the calculated source velocity by considering the bat's own velocity to deduce the actual relative speed of the insect.

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Most popular questions from this chapter

A sinusoidal sound wave is described by the displacement wave function $$ s(x, t)=(2.00 \mu \mathrm{m}) \cos \left[\left(15.7 \mathrm{m}^{-1}\right) x-\left(858 \mathrm{s}^{-1}\right) t\right] $$ (a) Find the amplitude, wavelength, and speed of this wave. (b) Determine the instantaneous displacement from equilibrium of the elements of air at the position \(x=0.0500 \mathrm{m}\) at \(t=3.00 \mathrm{ms}\) . (c) Determine the maximum speed of the element's oscillatory motion.

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Ultrasound is used in medicine both for diagnostic imaging and for therapy. For diagnosis, short pulses of ultrasound are passed through the patient’s body. An echo reflected from a structure of interest is recorded, and from the time delay for the return of the echo the distance to the structure can be determined. A single transducer emits and detects the ultrasound. An image of the structure is obtained by reducing the data with a computer. With sound of low intensity, this technique is noninvasive and harmless. It is used to examine fetuses, tumors, aneurysms, gallstones, and many other structures. A Doppler ultrasound unit is used to study blood flow and functioning of the heart. To reveal detail, the wavelength of the reflected ultrasound must be small compared to the size of the object reflecting the wave. For this reason, frequencies in the range 1.00 to 20.0 MHz are used. What is the range of wavelengths corresponding to this range of frequencies? The speed of ultra- sound in human tissue is about 1 500 m/s (nearly the same as the speed of sound in water).

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