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A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 12.0 \(\mathrm{rad} / \mathrm{s}\) in 3.00 s. Find \((\mathrm{a})\) the magnitude of the angular acceleration of the wheel and \((\mathrm{b})\) the angle in radians through which it rotates in this time.

Short Answer

Expert verified
The angular acceleration is \(4.0\,\mathrm{rad/s^2}\) and the angle through which the wheel rotates is \(18.0\,\mathrm{rad}\).

Step by step solution

01

Use the angular acceleration formula

The angular acceleration, \(\alpha\), can be calculated using the formula \( \alpha = \frac{\Delta\omega}{\Delta t} \) where \(\Delta\omega\) is the change in angular velocity and \(\Delta t\) is the change in time. In this case, \(\Delta\omega = 12.0\,\mathrm{rad/s}\) and \(\Delta t = 3.00\,\mathrm{s}\).
02

Calculate the angular acceleration

Substitute the given values into the formula to find the angular acceleration: \(\alpha = \frac{12.0\,\mathrm{rad/s}}{3.00\,\mathrm{s}} = 4.0\,\mathrm{rad/s^2}\).
03

Use the formula for angular displacement

The angular displacement, \(\theta\), can be calculated using the formula \(\theta = \omega_0 t + \frac{1}{2}\alpha t^2\) where \(\omega_0\) is the initial angular velocity, \(t\) is the time, and \(\alpha\) is the angular acceleration. Since the wheel starts from rest, \(\omega_0 = 0\).
04

Calculate the angular displacement

Substitute \(\omega_0 = 0\), \(\alpha = 4.0\,\mathrm{rad/s^2}\), and \(t = 3.00\,\mathrm{s}\) into the angular displacement formula to find \(\theta\): \(\theta = 0 \times 3.00\,\mathrm{s} + \frac{1}{2} \times 4.0\,\mathrm{rad/s^2} \times (3.00\,\mathrm{s})^2 = 18.0\,\mathrm{rad}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
When we talk about how fast an object is rotating, we are referring to its angular velocity. This is similar to linear velocity, but instead of tracking how far an object moves in a straight line, angular velocity measures how quickly an object rotates about a point or axis. It is denoted by the symbol \(\omega\) and is usually expressed in radians per second (rad/s).

In the case of the rotating wheel from our exercise, the wheel's angular velocity increased from 0 to 12.0 rad/s over a period of 3.00 seconds. This change in angular velocity is central to understanding the wheel's rotational motion and will lead us directly to calculations involving angular acceleration.
Angular Displacement
Imagine turning a steering wheel or a merry-go-round; the amount by which these things turn is described by angular displacement. It's an angle, often measured in radians, that represents the difference in the orientation of a rotating body about a fixed point over some period of time. In our exercise, the angle through which the wheel rotated was calculated to be 18.0 radians.

The formula for angular displacement includes initial angular velocity, angular acceleration, and time. Since our wheel started from rest, its initial angular velocity was 0, simplifying our equation to only consider angular acceleration and time, leading us to calculate the angular displacement over 3 seconds.
Constant Angular Acceleration
When an object's angular velocity changes at a steady rate, we say that it has a constant angular acceleration. This concept is very important in rotational motion because it allows us to predict future behavior of rotating objects if we know their current state and how fast they're speeding up or slowing down. Angular acceleration is often denoted by the Greek letter \(\alpha\) and is measured in radians per second squared (rad/s^2).

In the exercise's solution, a constant angular acceleration was used to solve for the wheel's final angular velocity and angular displacement. The calculation showed an angular acceleration of 4.0 rad/s^2, indicating a steady increase in angular velocity over the given time.
Rotational Motion
Rotational motion is when an object spins around an internal axis. It's everywhere in our daily life, from the rotation of a bicycle wheel to the spin of the Earth around its axis. The principles governing rotational motion are similar to those for linear motion, but instead of displacement, velocity, and acceleration, we have angular displacement, angular velocity, and angular acceleration.

In rotational motion, every point in the object moves in a circle around the axis of rotation. A point farther from the axis moves a larger distance in the same amount of time, which means it has a higher angular velocity. All parts of the object share the same angular acceleration if the object's angular velocity changes uniformly, as was the case with the wheel in our exercise, where every part of the wheel experienced the same change in motion due to the constant angular acceleration.

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Most popular questions from this chapter

A grinding wheel is in the form of a uniform solid disk of radius 7.00 \(\mathrm{cm}\) and mass 2.00 \(\mathrm{kg}\) . It starts from rest and accelerates uniformly under the action of the constant torque of 0.600 \(\mathrm{N} \cdot \mathrm{m}\) that the motor exerts on the wheel. (a) How long does the wheel take to reach its final operating speed of 1200 \(\mathrm{rev} / \mathrm{min}\) ? (b) Through how many revolutions does it turn while accelerating?

(a) Determine the acceleration of the center of mass of a uniform solid disk rolling down an incline making angle \(\theta\) with the horizontal. Compare this acceleration with that of a uniform hoop. (b) What is the minimum coefficient of friction required to maintain pure rolling motion for the disk?

Figure \(\mathrm{P} 10.14\) shows the drive train of a bicycle that has wheels 67.3 \(\mathrm{cm}\) in diameter and pedal cranks 17.5 \(\mathrm{cm}\) long. The cyclist pedals at a steady angular rate of 76.0 rev/min. The chain engages with a front sprocket 15.2 \(\mathrm{cm}\) in diameter and a rear sprocket 7.00 \(\mathrm{cm}\) in diameter. (a) Calculate the speed of a link of the chain relative to the bicycle frame. (b) Calculate the angular speed of the bicycle wheels. (c) Calculate the speed of the bicycle relative to the road. (d) What pieces of data, if any, are not necessary for the calculations?

A rotating wheel requires 3.00 s to rotate through 37.0 revolutions. Its angular speed at the end of the 3.00 -s interval is 98.0 \(\mathrm{rad} / \mathrm{s}\) . What is the constant angular acceleration of the wheel?

A racing car travels on a circular track of radius \(250 \mathrm{m} .\) If the car moves with a constant linear speed of 45.0 \(\mathrm{m} / \mathrm{s}\) , find (a) its angular speed and (b) the magnitude and direction of its acceleration.

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