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What mass of a material with density \(\rho\) is required to make a hollow spherical shell having inner radius \(r_{1}\) and outer radius \(r_{2} ?\)

Short Answer

Expert verified
The mass of the hollow spherical shell is \(m = \rho \cdot \frac{4}{3}\pi (r_{2}^3 - r_{1}^3)\).

Step by step solution

01

Understand the Volume of the Hollow Sphere

The volume of the hollow spherical shell can be found by calculating the difference between the volume of the outer sphere and the volume of the inner sphere. The formula for the volume of a sphere is \(\frac{4}{3}\pi r^3\). Therefore, the volume of the hollow sphere, \(V\), is \(V = \frac{4}{3}\pi r_{2}^3 - \frac{4}{3}\pi r_{1}^3\).
02

Simplify the Volume Formula

Take out the common factor \(\frac{4}{3}\pi\) from both terms to simplify the equation: \(V = \frac{4}{3}\pi (r_{2}^3 - r_{1}^3)\).
03

Calculate the Mass

To find the mass \(m\), use the formula for mass which is \(m = \rho \cdot V\), where \(\rho\) is the density of the material. Substitute \(V\) in this formula to get \(m = \rho \cdot \frac{4}{3}\pi (r_{2}^3 - r_{1}^3)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density, denoted by the Greek letter \rho, is a measure of how much mass is contained within a certain volume. Think of it like how tightly packed the material's particles are. The higher the density, the more mass per unit volume. It is an intrinsic property of a material and does not depend on the amount of substance. Mathematically, density is expressed as:
\[ \rho = \frac{m}{V} \]
where \(m\) is the mass and \(V\) is the volume. For instance, steel is denser than plastic; therefore, if you had a steel sphere and a plastic sphere of the same size, the steel sphere would be heavier due to its greater density. When calculating the mass of a spherical shell, understanding density is crucial because it allows us to determine how much mass should be in a certain volume.
Volume of Sphere
A sphere is a 3-dimensional shape where every point on its surface is an equal distance from its center. The formula to calculate the volume of a full sphere is given by:
\[ V_{\text{sphere}} = \frac{4}{3}\pi r^3 \]
where \(r\) is the radius of the sphere. This formula, derived from calculus, tells us how much space is inside the sphere. To visualize this, imagine how much water could totally fill up a spherical balloon. It's essential to understand this concept because it's the building block for calculating the volume of more complex shapes like the spherical shell we encounter in the exercise.
Spherical Shell Volume Calculation
A spherical shell is like a hollow ball with a certain thickness, having an inner radius \(r_1\) and an outer radius \(r_2\). The volume of a spherical shell is the difference between the volume of the larger sphere (with radius \(r_2\)) and the smaller, inner sphere (with radius \(r_1\)). So, it can be thought of as the volume of material present. To find this volume, we use the formula for the volume of a full sphere but applied to both the inner and outer spheres:
\[ V_{\text{shell}} = \frac{4}{3}\pi r_{2}^3 - \frac{4}{3}\pi r_{1}^3 \]
Instead of filling the whole space as with a full sphere, the shell occupies the region between the two radii. This calculation is the basis for finding the mass of the shell given the material's density.

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Most popular questions from this chapter

A pyramid has a height of 481 \(\mathrm{ft}\) and its base covers an area of 13.0 acres (Fig. Pl.32). If the volume of a pyramid is given by the expression \(V=\frac{1}{3} B h,\) where \(B\) is the area of the base and \(h\) is the height, find the volume of this pyramid in cubic meters. ( 1 acre \(=43560 \mathrm{ft}^{2} )\)

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