/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 92 A \(4800-\mathrm{kg}\) open rail... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(4800-\mathrm{kg}\) open railroad car coasts along with a constant speed of \(8.60 \mathrm{~m} / \mathrm{s}\) on a level track. Snow begins to fall vertically and fills the car at a rate of \(3.80 \mathrm{~kg} / \mathrm{min}\). Ignoring friction with the tracks, what is the speed of the car after \(60.0 \mathrm{~min} ?\) (See Section 9-2.)

Short Answer

Expert verified
The speed of the car after 60 minutes is approximately 8.21 m/s.

Step by step solution

01

Understand the Problem

The railroad car is moving on a track with a constant speed of \(8.60 \text{ m/s}\). Snow is falling into the car at a rate of \(3.80 \text{ kg/min}\). We want to determine the speed of the car after snow has been falling for \(60.0 \text{ minutes}\), assuming no friction affects the car's motion.
02

Identify the Concepts and Formulas

The principle of conservation of momentum will be applied here. Since there is no friction, the external forces do not affect the horizontal component of the system's momentum. The initial momentum of the car is the product of its mass and velocity. As snow fills the car, the mass changes, but the momentum is conserved.
03

Calculate the Initial Momentum

The initial momentum \(p_i\) of the railroad car is given by \(p_i = m_i \cdot v_i\), where \(m_i = 4800 \text{ kg}\) and \(v_i = 8.60 \text{ m/s}\). Thus, \(p_i = 4800 \times 8.60 = 41280 \text{ kg m/s}\).
04

Calculate the Change in Mass

The snow falls at a rate of \(3.80 \text{ kg/min}\). In \(60.0\) minutes, the total mass of the snow added to the car is \(60.0 \times 3.80 = 228 \text{ kg}\). The final mass of the system will be \(m_f = 4800 \text{ kg} + 228 \text{ kg} = 5028 \text{ kg}\).
05

Apply the Conservation of Momentum

According to the conservation of momentum, \(p_i = p_f\), where \(p_f = m_f \cdot v_f\). Solving for \(v_f\), we have:\(41280 = 5028 \cdot v_f\Rightarrow v_f = \frac{41280}{5028}.\)
06

Calculate the Final Velocity

Calculate \(v_f\):\(v_f = \frac{41280}{5028} \approx 8.21 \text{ m/s}.\) So, the speed of the car after \(60\) minutes is approximately \(8.21 \text{ m/s}.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Railroad Car Dynamics
When we talk about railroad car dynamics, we focus on how a railroad car moves and what affects this movement. The primary forces we consider include friction, momentum, and any external forces acting on the car. In our scenario, we ignore friction which simplifies our calculations significantly. This assumption allows us to focus on the train car's motion affected only by the weight of the incoming snow. The car is initially moving at a constant speed, indicating there are no unbalanced external forces initially.

Throughout the exercise, the snow falls directly into the car, gradually increasing its mass. Under normal circumstances, increased resistance might slow down the car, but in this problem, friction is not a factor. The car maintains its horizontal momentum even as its mass changes, highlighting how momentum can be conserved in dynamic systems like a railroad car.

Understanding railroad car dynamics involves comprehending different mechanical aspects and how they contribute to the overall motion. Despite increased mass, the absence of friction means the momentum principle continues to govern the car's dynamics, determining its new speed.
Mass Accumulation Effect
The mass accumulation effect highlights how adding mass to a moving object affects its momentum and velocity. In the given scenario, the railroad car collects snow over time, which steadily increases its overall mass. When we consider momentum, defined as the product of mass and velocity (\(p = m \cdot v\)), it’s crucial to recognize that any change in mass directly impacts the system's momentum.

With each kilogram of snow that settles into the car, the total mass increases, and thus the velocity needs to adjust to maintain the same momentum. This phenomenon explains why the final velocity of the car is less than its initial speed, even though no external horizontal forces interfere. The concept of mass accumulation is pivotal when evaluating systems where the mass change can alter functionality or motion over time.

In simpler terms, if the car initially had a certain speed, adding mass means more force is required to continue that speed. However, in the absence of external forces to add that extra push, the car must slow down to keep its momentum unchanged.
Physics Problem Solving
Solving physics problems requires a methodical approach to ensure clarity and accuracy. To tackle problems like the one about the railroad car and snow, we need to follow certain steps.

  • Start by understanding the problem: Clearly define what's happening in the scenario. Identify key variables like initial speed, rate of mass change, and time factor.
  • Use appropriate physics principles: In this case, the conservation of momentum is vital. Recognize how it applies and how to use it to link initial conditions with final outcomes.
  • Break down the calculations: Determine initial momentum using the mass and speed. Calculate total mass accumulation over time accurately. This step involves both qualitative understanding and quantitative calculations.
  • Always verify your results: After calculating, double-check each step to ensure your logic and math align with physics principles. Corrections here can prevent simple mistakes from skewing your results.
Approaching physics problems systematically allows for a clearer understanding and successful application of theoretical concepts to practical scenarios.

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Most popular questions from this chapter

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An extrasolar planet can be detected by observing the wobble it produces on the star around which it revolves. Suppose an extrasolar planet of mass \(m_{\mathrm{B}}\) revolves around its star of mass \(m_{\mathrm{A}}\) If no external force acts on this simple two-object system, then its \(\mathrm{CM}\) is stationary. Assume \(m_{\mathrm{A}}\) and \(m_{\mathrm{B}}\) are in circular orbits with radii \(r_{\mathrm{A}}\) and \(r_{\mathrm{B}}\) about the system's \(\mathrm{CM}\). (a) Show that \(r_{\mathrm{A}}=\frac{m_{\mathrm{B}}}{m_{\mathrm{A}}} r_{\mathrm{B}}\) (b) Now consider a Sun-like star and a single planet with the same characteristics as Jupiter. That is, \(m_{\mathrm{B}}=1.0 \times 10^{-3} \mathrm{~m}_{\mathrm{A}}\) and the planet has an orbital radius of \(8.0 \times 10^{11} \mathrm{~m} .\) Determine the radius \(r_{\mathrm{A}}\) of the star's orbit about the system's \(\mathrm{CM}\). (c) When viewed from Earth, the distant system appears to wobble over a distance of \(2 r_{\mathrm{A}}\). If astronomers are able to detect angular displacements \(\theta\) of about 1 milliarcsec \(\left(1 \operatorname{arcsec}=\frac{1}{3600}\right.\) of a degree), from what distance \(d\) (in light-years) can the star's wobble be detected \(\left(11 \mathrm{y}=9.46 \times 10^{15} \mathrm{~m}\right) ?(d)\) The star nearest to our Sun is about 4 ly away. Assuming stars are uniformly distributed throughout our region of the Milky Way Galaxy, about how many stars can this technique be applied to in the search for extrasolar planetary systems?

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